STATEMENT – 1: The slant height of frustum of cone is 4cm. and perimeter of its circular ends are 18 cm, and 6 cm, then the curved surface area is 48 sq. cm.
STATEMENT – 2: Curved surface area of frustum is $\pi \left( {{r_1} + {r_2}} \right)$ where ${r_1}{\text{ and }}{{\text{r}}_2}$ are the radii of the frustum and l is the slant height.
$
(a){\text{ Statement - 1 is True, Statement - 2 is True, Statement - 2 is a correct explanation for statement - 1}}{\text{.}} \\
(b){\text{ Statement - 1 is True, Statement - 2 is True, Statement - 2 is not a correct explanation for statement - 1}}{\text{.}} \\
(c){\text{ Statement - 1 is True, Statement - 2 is False}} \\
(d){\text{ Statement - 1 is False, Statement - 2 is True}} \\
$
Answer
646.5k+ views
Hint: In this question use the direct formula for the curved surface area of frustum of cone. Curved surface area of frustum of cone$\pi \left( {{r_1} + {r_2}} \right)l$.
Complete step-by-step answer:
As we know that the curved surface area (C.S.A) of the frustum is $\pi \left( {{r_1} + {r_2}} \right)l$ $cm^2$………… (1)
Where r2 and r1 are the radius of lower and upper circular parts.
And l = slant height of the frustum.
So from the above formula of the curved surface area of the frustum clearly that statement – 2 is false as in statement 2 slant height is not present in the formula.
Now according to statement – 1 it is given that slant height (l) = 4 cm.
And the perimeter of the circular ends are 18 and 6 cm respectively.
As we know that the perimeter of a circle is$2\pi r$, where r is the radius of the circle.
So the upper circular part of the circle perimeter is $2\pi {r_1}$
$ \Rightarrow 2\pi {r_1} = 18$
$ \Rightarrow {r_1} = \dfrac{{18}}{{2\pi }}$ cm.
Now the lower circular part of the circle perimeter is $2\pi {r_2}$
$ \Rightarrow 2\pi {r_2} = 6$
$ \Rightarrow {r_2} = \dfrac{6}{{2\pi }}$ cm.
So from equation (1) we have,
$ \Rightarrow C.S.A = \pi \left( {{r_1} + {r_2}} \right)l$
Now substitute all the values in this equation we have,
$ \Rightarrow C.S.A = \pi \left( {\dfrac{{18}}{{2\pi }} + \dfrac{6}{{2\pi }}} \right)4 = \pi \left( {\dfrac{{24}}{{2\pi }}} \right)4 = 12 \times 4 = 48$ sq. cm.
Thus statement – 1 is true.
So statement – 1 is true, statement – 2 is false.
Hence option (c) is correct.
Note: Whenever we face such types of problems the key concept is to have a gist of the direct formula of some of the basic conic sections like frustum of cone, sphere, cylindrical etc. This helps save a lot of time while solving such types of problems.
Complete step-by-step answer:
As we know that the curved surface area (C.S.A) of the frustum is $\pi \left( {{r_1} + {r_2}} \right)l$ $cm^2$………… (1)
Where r2 and r1 are the radius of lower and upper circular parts.
And l = slant height of the frustum.
So from the above formula of the curved surface area of the frustum clearly that statement – 2 is false as in statement 2 slant height is not present in the formula.
Now according to statement – 1 it is given that slant height (l) = 4 cm.
And the perimeter of the circular ends are 18 and 6 cm respectively.
As we know that the perimeter of a circle is$2\pi r$, where r is the radius of the circle.
So the upper circular part of the circle perimeter is $2\pi {r_1}$
$ \Rightarrow 2\pi {r_1} = 18$
$ \Rightarrow {r_1} = \dfrac{{18}}{{2\pi }}$ cm.
Now the lower circular part of the circle perimeter is $2\pi {r_2}$
$ \Rightarrow 2\pi {r_2} = 6$
$ \Rightarrow {r_2} = \dfrac{6}{{2\pi }}$ cm.
So from equation (1) we have,
$ \Rightarrow C.S.A = \pi \left( {{r_1} + {r_2}} \right)l$
Now substitute all the values in this equation we have,
$ \Rightarrow C.S.A = \pi \left( {\dfrac{{18}}{{2\pi }} + \dfrac{6}{{2\pi }}} \right)4 = \pi \left( {\dfrac{{24}}{{2\pi }}} \right)4 = 12 \times 4 = 48$ sq. cm.
Thus statement – 1 is true.
So statement – 1 is true, statement – 2 is false.
Hence option (c) is correct.
Note: Whenever we face such types of problems the key concept is to have a gist of the direct formula of some of the basic conic sections like frustum of cone, sphere, cylindrical etc. This helps save a lot of time while solving such types of problems.
Recently Updated Pages
Master Class 12 Business Studies: Engaging Questions & Answers for Success

Master Class 12 Biology: Engaging Questions & Answers for Success

Master Class 12 Chemistry: Engaging Questions & Answers for Success

Class 12 Question and Answer - Your Ultimate Solutions Guide

Master Class 11 Social Science: Engaging Questions & Answers for Success

Master Class 11 English: Engaging Questions & Answers for Success

Trending doubts
What is the full form of NDA a National Democratic class 10 social science CBSE

Explain the Treaty of Vienna of 1815 class 10 social science CBSE

Who Won 36 Oscar Awards? Record Holder Revealed

Bharatiya Janata Party was founded in the year A 1979 class 10 social science CBSE

What is the median of the first 10 natural numbers class 10 maths CBSE

Why is it 530 pm in india when it is 1200 afternoon class 10 social science CBSE

