Question

How do you solve the equation $-2x-7+3x=10$?

Answer 1

Hint: Now to solve the given equation we will first rearrange the terms by keeping all the variables on LHS and transposing all the constants on RHS. Now we will simplify the equation.
Hence on simplifying we will get the required value of x. Hence we get the solution of the given equation.

Complete step by step solution:
Now first let us consider the given equation $-2x-7+3x=10$
We can see that the above equation is a linear equation in x.
Now we know that there is just one solution to the linear equation in one variable. Hence we will find the value of x for which the equation holds.
Now let us first rearrange the terms of the given equation. Hence we get,
$\Rightarrow -7+3x-2x=10$
Now we know that 3x – 2x = x.
Hence we can write the equation as $-7+x=10$
Now again we will transpose the constant from LHS to RHS. Now we know that the sign of the term changes when shifting from one side to another.
Hence we get the equation as $x=10+7$
Hence on simplification we get the value of x as 17.
Hence we get the solution of the given equation is x = 17.

Note: Now note that the solution of linear equation are nothing but values of x for which the equation is true. Now since the degree of the equation is 1 we just have one solution. Now if the degree of equation is 2 then we call the equation as quadratic equation and the number of solutions in this case is 2.