How do you factor \[ab+4+a+4b\]?
Answer
616.2k+ views
Hint: First of all, to solve these types of questions we should identify the common parts in different terms. Now, after identifying these terms we should common these parts from these terms. We should continue this process until the given expression is converted into a collection of linear factors. In this way, we can factor the given expression into linear factors.
Complete step by step solution:
From the question, it is clear that we have to find the factor of \[ab+4+a+4b\]. Let us assume that
\[f(a,b)=ab+4+a+4b\]
Let us assume that,
\[f(a,b)=ab+4+a+4b....(1)\]
Now let us rearrange the terms in equation (1). Then we get the equation as follows.
\[\Rightarrow f(a,b)=ab+a+4+4b\]
Now we can take as common in the first two terms and 4 as common in other terms. Then, we get the equation as follows.
After doing the above mentioned process we get,
\[\Rightarrow f(a,b)=a\left( b+1 \right)+4\left( b+1 \right)\]
Now let us assume that,
\[\Rightarrow f(a,b)=a\left( b+1 \right)+4\left( b+1 \right).....(2)\]
Now we can take \[\left( b+1 \right)\] as common in the equation (2). After taking \[\left( b+1 \right)\] common in the above equation we get the equation reduced as follows.
\[\Rightarrow f(a,b)=\left( a+4 \right)\left( b+1 \right)\]
Now let us assume that,
\[\Rightarrow f(a,b)=\left( b+1 \right)\left( a+4 \right).....(3)\]
From equation (3), it is clear that the factors of \[ab+4+a+4b\] this expression are \[\left( b+1 \right)\] and \[\left( a+4 \right)\].
So, we can write the solution for the given question as follows.
\[\Rightarrow ab+4+a+4b=\left( b+1 \right)\left( a+4 \right)\].
Hence, in this way we can factor the given question \[ab+4+a+4b\].
Note:
Students should avoid calculation mistakes while solving this problem and while taking terms as common. So, these mistakes should be avoided while solving this problem. Students should also have a clear view of the concept. For example in equation 1 if we take \[ab\] and \[4b\]into consideration without rearrangement the solution will be wrong. . Because if a small mistake is made, then the final answer will get interrupted.
Complete step by step solution:
From the question, it is clear that we have to find the factor of \[ab+4+a+4b\]. Let us assume that
\[f(a,b)=ab+4+a+4b\]
Let us assume that,
\[f(a,b)=ab+4+a+4b....(1)\]
Now let us rearrange the terms in equation (1). Then we get the equation as follows.
\[\Rightarrow f(a,b)=ab+a+4+4b\]
Now we can take as common in the first two terms and 4 as common in other terms. Then, we get the equation as follows.
After doing the above mentioned process we get,
\[\Rightarrow f(a,b)=a\left( b+1 \right)+4\left( b+1 \right)\]
Now let us assume that,
\[\Rightarrow f(a,b)=a\left( b+1 \right)+4\left( b+1 \right).....(2)\]
Now we can take \[\left( b+1 \right)\] as common in the equation (2). After taking \[\left( b+1 \right)\] common in the above equation we get the equation reduced as follows.
\[\Rightarrow f(a,b)=\left( a+4 \right)\left( b+1 \right)\]
Now let us assume that,
\[\Rightarrow f(a,b)=\left( b+1 \right)\left( a+4 \right).....(3)\]
From equation (3), it is clear that the factors of \[ab+4+a+4b\] this expression are \[\left( b+1 \right)\] and \[\left( a+4 \right)\].
So, we can write the solution for the given question as follows.
\[\Rightarrow ab+4+a+4b=\left( b+1 \right)\left( a+4 \right)\].
Hence, in this way we can factor the given question \[ab+4+a+4b\].
Note:
Students should avoid calculation mistakes while solving this problem and while taking terms as common. So, these mistakes should be avoided while solving this problem. Students should also have a clear view of the concept. For example in equation 1 if we take \[ab\] and \[4b\]into consideration without rearrangement the solution will be wrong. . Because if a small mistake is made, then the final answer will get interrupted.
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