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Elliot is 6 feet and 1 inch tall while his friend Vaughn is 64.5 inches tall. How much taller is Elliot than Vaughn?

Answer
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536.7k+ views
Hint: We will first write the relation between feet and inches. Then, we will convert Elliot’s height completely into inches and then subtract Vaughn’s height from it to obtain the difference.

Complete step by step answer:
We are given that we are required to find the difference in the heights of Elliot and Vaughn when Elliot is 6 feet and 1 inch tall while his friend Vaughn is 64.5 inches tall.
We know that 1 feet is equal to 12 inches.
We can write this as:-
1 feet = 12 inches
6 feet = $6 \times 12$ inches
$ \Rightarrow $ 6 feet = 72 inches
Since, Elliot is 6 feet and 1 inch tall.
Therefore, Elliot is 72 inches + 1 inch = 73 inches tall.
Now, since Vaughn is 64.5 inches tall.
Difference in their heights = (73 – 64.5) inches = 8.5 inches.

Hence, the answer is 8.5 inches.

Note: The students must notice that we may use the conversions other way round as well. We will first convert the height of Vaughn in feet instead of inches. Then, we will subtract the heights to get the difference in feet.
The students must also commit to the memory that 1 feet is equal to 12 inches and 1 inch is twelfth part of a foot.
So, 1 feet = 12 inches and 1 inch = $\dfrac{1}{12}$ feet.
The students must also note that we may use the fact that we convert both of their heights into a different unit than feet or inch and then subtract them to find the difference.
For example:- 1 inch = 2.54 cm and 1 foot = 30.48 cm
Using this, we have: Elliot’s height is equal to 185.42 cm and Vaughn’s height is equal to 163.83 cm.
Now, we can find the difference in their heights to find the difference in their heights in cm.

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