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This type of question is very common in mensuration. First we have to calculate the curved surface area of the cylinder.

Formula for curved surface area of cylinder is:

$A = 2\pi rh$

Where r is the radius and h is the height of the cylinder.

So, r = $\dfrac{{70}}{2}$=35 cm= 0.35 m (As radius is half of the diameter.)

And h= 2 m

Now, we will substitute the values of r and h in the above formula. Then we will get,

$

A = 2 \times \dfrac{{22}}{7} \times 0.35 \times 2 \\

\Rightarrow A = 4.4 \\

$

Thus the area covered by the roller in one revolution will be 4.4 square meters.

Now, to find the total area covered by roller in 50 revolutions, we need to multiply the area covered in one revolution by 50.

Therefore,

$

50 \times 4.4 \\

\Rightarrow 220 \\

$

Area covered in 50 revolutions will be 220 square meters.