A page of a calendar is $ 45\,cm $ long and $ 26\,cm $ wide. What is its area?
Answer
563.1k+ views
Hint: Here we have been given the dimension of the page of a calendar. As we can see from the dimension given that the calendar is in rectangle shape. Firstly we will write the formula for calculating the area of the rectangle then we will substitute the dimension of the calendar given in it. Finally we will solve the value and get the desired answer.
Complete step-by-step answer:
It is given that the page of a calendar is $ 45\,cm $ long and $ 26\,cm $ wide and we have to find its area.
So we can say that,
Length of calendar $ =45\,cm $
Width of calendar $ =26\,cm $
The shape of the page can be drawn as follows:
The formula for calculating the area of rectangle shaped thing in this case page is:
Area $ = $ Length $ \times $ Width
Substitute the values in above formula,
Area $ =45\,cm\times 26\,cm $
Area $ =1170\,c{{m}^{2}} $
Hence the area of $ 45\,cm $ long and $ 26\,cm $ wide page of the calendar is $ 1170\,c{{m}^{2}} $ .
So, the correct answer is “ $ 1170\,c{{m}^{2}} $ ”.
Note: Rectangle is a four sided polygon with the entire internal angle equal to $ 90 $ degrees where the opposite sides are equal in length. It has two diagonals and the sides with equal length are always parallel to each other. In this question as it is mentioned that it is a page whose length is given so it is clear that the page will have four sides and as the dimension has two different values it means the page is in rectangle form. Don’t use the square formula in this case. Remember the unit of area is always in square and use the correct unit given for stating the answer at the end.
Complete step-by-step answer:
It is given that the page of a calendar is $ 45\,cm $ long and $ 26\,cm $ wide and we have to find its area.
So we can say that,
Length of calendar $ =45\,cm $
Width of calendar $ =26\,cm $
The shape of the page can be drawn as follows:
The formula for calculating the area of rectangle shaped thing in this case page is:
Area $ = $ Length $ \times $ Width
Substitute the values in above formula,
Area $ =45\,cm\times 26\,cm $
Area $ =1170\,c{{m}^{2}} $
Hence the area of $ 45\,cm $ long and $ 26\,cm $ wide page of the calendar is $ 1170\,c{{m}^{2}} $ .
So, the correct answer is “ $ 1170\,c{{m}^{2}} $ ”.
Note: Rectangle is a four sided polygon with the entire internal angle equal to $ 90 $ degrees where the opposite sides are equal in length. It has two diagonals and the sides with equal length are always parallel to each other. In this question as it is mentioned that it is a page whose length is given so it is clear that the page will have four sides and as the dimension has two different values it means the page is in rectangle form. Don’t use the square formula in this case. Remember the unit of area is always in square and use the correct unit given for stating the answer at the end.
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