# NCERT Solutions for Class 8 Maths Chapter 1 Rational Numbers (EX 1.2) Exercise 1.2

## NCERT Solutions for Class 8 Maths Chapter 1 Rational Numbers (EX 1.2) Exercise 1.2 NCERT Solutions for Class 8 Maths Chapter 1 are provided by Vedantu. The very first chapter in the Class 8 Maths syllabus, ‘Rational Numbers’, and the exercise 1.2 Class 8 is a critical and important part of the Maths syllabus. So, if you are in search of assistance with the solutions to the exercise problems in the NCERT textbook, then there cannot be a better alternative than Vedantu’s Class 8 Maths Chapter 1. You can download this in PDF format prepared by our experts based on the CBSE guidelines. Vedantu is a platform that provides free NCERT Solution and other study materials for students. Science students who are looking for NCERT Solutions for Class 8 Science will also find the solutions curated by our Master Teachers really helpful.

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Exercise 1.2

1. Represent these numbers on the number line.

1. $\dfrac{7}{4}$

Ans: Since, $\dfrac{7}{4}$ is approximately equal to $1.75$.

Therefore, $\dfrac{7}{4}$ can be represented on the number line as follows:

1. $-\dfrac{5}{6}$

Ans: Since, $-\dfrac{5}{6}$ is approximately equal to $-0.833$.

Thus, $-\dfrac{5}{6}$ can be represented on the number line as follows:

2. Represent $\text{-}\dfrac{\text{2}}{\text{11}}\text{,-}\dfrac{\text{5}}{\text{11}}\text{,-}\dfrac{\text{9}}{\text{11}}$ on the number line.

Ans: We can divide interval between $\text{0}$ and $\text{-1}$ in $\text{11}$ parts to get $\text{-}\dfrac{\text{2}}{\text{11}}\text{,-}\dfrac{\text{5}}{\text{11}}\text{,-}\dfrac{\text{9}}{\text{11}}$ on number line.

Thus, $\text{-}\dfrac{\text{2}}{\text{11}}\text{,-}\dfrac{\text{5}}{\text{11}}\text{,-}\dfrac{\text{9}}{\text{11}}$ can be represented on the number line as follows:

3. Write five rational numbers which are smaller than $\text{2}$.

Ans: Since, we have to write five rational numbers which are less than $\text{2}$ .

Therefore, we can multiply and divide $\text{2}$ by $7$.

Now, $\text{2}$ becomes $\dfrac{\text{14}}{\text{7}}$.

Thus, five rational numbers which are smaller than $\text{2}$ are given as -

$\dfrac{\text{13}}{\text{7}}\text{,}\dfrac{\text{12}}{\text{7}}\text{,}\dfrac{\text{11}}{\text{7}}\text{,}\dfrac{\text{10}}{\text{7}}\text{,}\dfrac{\text{9}}{\text{7}}$.

4. Find ten rational numbers between $\dfrac{\text{-2}}{\text{5}}$ and $\dfrac{\text{1}}{\text{2}}$.

Ans: We can make denominator of  $\dfrac{\text{-2}}{\text{5}}$ and $\dfrac{\text{1}}{\text{2}}$ same.

Therefore, multiplying and dividing $\dfrac{\text{-2}}{\text{5}}$ by $\text{4}$ and $\dfrac{\text{1}}{\text{2}}$ by $\text{10}$.

Thus, now $\dfrac{\text{-2}}{\text{5}}$ becomes $\dfrac{\text{-8}}{\text{20}}$  and  $\dfrac{\text{1}}{\text{2}}$ becomes $\dfrac{\text{10}}{\text{20}}$ .

Hence, ten rational numbers between $\dfrac{\text{-2}}{\text{5}}$ and $\dfrac{\text{1}}{\text{2}}$ are-

$\text{-}\dfrac{\text{7}}{\text{20}}\text{,-}\dfrac{\text{6}}{\text{20}}\text{,-}\dfrac{\text{5}}{\text{20}}\text{,-}\dfrac{\text{4}}{\text{20}}\text{,-}\dfrac{\text{3}}{\text{20}}\text{,-}\dfrac{\text{2}}{\text{20}}\text{,-}\dfrac{\text{1}}{\text{20}}\text{,0,}\dfrac{\text{1}}{\text{20}}\text{,}\dfrac{\text{2}}{\text{20}}$.

5. Find five rational numbers between-

1. $\dfrac{\text{2}}{\text{3}}$ and $\dfrac{\text{4}}{\text{5}}$

Ans: We can make denominator of  $\dfrac{\text{2}}{\text{3}}$ and $\dfrac{\text{4}}{\text{5}}$ same.

Therefore, multiplying and dividing $\dfrac{\text{2}}{\text{3}}$ by $\text{15}$ and $\dfrac{\text{4}}{\text{5}}$ by $9$.

Thus, now $\dfrac{\text{2}}{\text{3}}$ becomes $\dfrac{\text{30}}{\text{45}}$  and  $\dfrac{\text{4}}{\text{5}}$ becomes $\dfrac{\text{36}}{\text{45}}$ .

Hence, ten rational numbers between $\dfrac{\text{2}}{\text{3}}$ and $\dfrac{\text{4}}{\text{5}}$ are-

$\dfrac{\text{31}}{\text{45}}\text{,}\dfrac{\text{32}}{\text{45}}\text{,}\dfrac{\text{33}}{\text{45}}\text{,}\dfrac{\text{34}}{\text{45}}\text{,}\dfrac{\text{35}}{\text{45}}$.

1. $\dfrac{\text{-3}}{\text{2}}$ and $\dfrac{\text{5}}{\text{3}}$.

Ans: We can make denominator of  $\text{-}\dfrac{\text{3}}{\text{2}}$ and $\dfrac{\text{5}}{\text{3}}$ same.

Therefore, multiplying and dividing $\text{-}\dfrac{\text{3}}{\text{2}}$ by $3$ and $\dfrac{\text{5}}{\text{3}}$ by $2$.

Thus, now $\text{-}\dfrac{\text{3}}{\text{2}}$ becomes $\text{-}\dfrac{\text{9}}{\text{6}}$  and  $\dfrac{\text{5}}{\text{3}}$ becomes $\dfrac{\text{10}}{\text{6}}$ .

Hence, ten rational numbers between $\text{-}\dfrac{\text{3}}{\text{2}}$ and $\dfrac{\text{5}}{\text{3}}$ are-

$\text{-}\dfrac{\text{8}}{\text{6}}\text{,-}\dfrac{\text{7}}{\text{6}}\text{,-1,-}\dfrac{\text{5}}{\text{6}}\text{,-}\dfrac{\text{4}}{\text{6}}$.

1. $\dfrac{\text{1}}{\text{4}}$ and $\dfrac{\text{1}}{\text{2}}$

Ans: We can make denominator of  $\dfrac{\text{1}}{\text{4}}$ and $\dfrac{\text{1}}{\text{2}}$ same.

Therefore, multiplying and dividing $\dfrac{\text{1}}{\text{4}}$ by $8$ and $\dfrac{\text{1}}{\text{2}}$ by $16$.

Thus, now $\dfrac{\text{1}}{\text{4}}$ becomes $\dfrac{\text{8}}{\text{32}}$  and  $\dfrac{\text{1}}{\text{2}}$ becomes $\dfrac{\text{16}}{\text{32}}$ .

Hence, ten rational numbers between $\dfrac{\text{1}}{\text{4}}$ and $\dfrac{\text{1}}{\text{2}}$ are-

$\dfrac{\text{9}}{\text{32}}\text{,}\dfrac{\text{10}}{\text{32}}\text{,}\dfrac{\text{11}}{\text{32}}\text{,}\dfrac{\text{12}}{\text{32}}\text{,}\dfrac{\text{13}}{\text{32}}$.

6. Write five rational numbers greater than $\text{-2}$.

Ans:

Since, we have to write five rational numbers which are greater than $\text{-2}$.

Therefore, we can multiply and divide $\text{-2}$ by $7$.

Now, $\text{-2}$ becomes $\text{-}\dfrac{\text{14}}{\text{7}}$.

Thus, five rational numbers greater than $\text{-2}$ are given as-

$\text{-}\dfrac{\text{13}}{\text{7}}\text{,-}\dfrac{\text{12}}{\text{7}}\text{,-}\dfrac{\text{11}}{\text{7}}\text{,-}\dfrac{\text{10}}{\text{7}}\text{,-}\dfrac{\text{9}}{\text{7}}$.

7. Find ten rational numbers between $\dfrac{\text{3}}{\text{5}}$ and $\dfrac{\text{3}}{\text{4}}$.

Ans: We can make denominator of  $\dfrac{\text{3}}{\text{5}}$ and $\dfrac{\text{3}}{\text{4}}$ same.

Therefore, multiplying and dividing $\dfrac{\text{3}}{\text{5}}$ by $16$ and $\dfrac{\text{3}}{\text{4}}$ by $20$.

Thus, now $\dfrac{\text{3}}{\text{5}}$ becomes $\dfrac{\text{48}}{\text{80}}$  and  $\dfrac{\text{3}}{\text{4}}$ becomes $\dfrac{\text{60}}{\text{80}}$ .

Hence, ten rational numbers between $\dfrac{\text{3}}{\text{5}}$ and $\dfrac{\text{3}}{\text{4}}$ are-

$\dfrac{\text{49}}{\text{80}}\text{,}\dfrac{\text{50}}{\text{80}}\text{,}\dfrac{\text{51}}{\text{80}}\text{,}\dfrac{\text{52}}{\text{80}}\text{,}\dfrac{\text{53}}{\text{80}}\text{,}\dfrac{\text{54}}{\text{80}}\text{,}\dfrac{\text{55}}{\text{80}}\text{,}\dfrac{\text{56}}{\text{80}}\text{,}\dfrac{\text{57}}{\text{80}}\text{,}\dfrac{\text{58}}{\text{80}}$.

## What do you learn from Chapter 1 Rational Numbers Exercise 1.2?

• Summary

Rational numbers are indeed an important part of the CBSE Class 8 Maths curriculum. To be precise, in the problems associated with Class 8 Chapter 1, ex 1.2 you will have to deal with the properties of rational numbers. CBSE Class 8 Maths Chapter 1 exercise 1.2 teaches students about the closure property, commutative property, associative and distributive property of rational numbers.

• What Kind of Questions Can You Expect?

For those familiar with integers and fractions, rational numbers may seem relatively easy. However, once you delve deep into the fundamental theorems and concepts, the complexity of the problems in the exercise becomes obvious; and, this is where Class 8 Maths NCERT Solutions Chapter 1 exercise 1.2 can be helpful. To ensure a clear understanding of these properties, and translate your understanding into problem-solving skills, you can seek assistance from Vedantu’s free PDF download of Class 8 Maths exercise 1.2 solutions.

### Class 8 maths Chapter 1 exercise 1.2 solutions

NCERT Exercise 1.2 of Class 8 Maths Chapter 1, introduces us to the primary problem patterns you will encounter from the chapter on rational numbers. Finding solutions to all problems in exercise 1.2 Class 8 Maths, is easier said than done, on your own. So, if you wish to strengthen your foundation in solving problems involving rational numbers, visit Vedantu’s website to download the free PDF of NCERT Maths Class 8 exercise 1.2.

### Benefits of Vedantu NCERT Maths Class 8 Chapter 1 exercise 1.2?

You will find the answer to a lot of doubts you face in the maths NCERT solutions Class 8 chapter 1 exercise 1.2. NCERT Class 8 Maths, ex. 1.2. require you to find given rational numbers on a number line, find a sequence of rational numbers smaller than the given one, find rational number sequences occurring between two given rational numbers, and the likes. To guarantee full score when you attempt these in your Class 8 Maths paper, you can refer to the Vedantu Class 8 Maths Chapter 1.2 PDF solutions.

The PDF download is portable and is carried anywhere and perused for reference. The simplistic breakdown of the solution into easy-to-grasp steps, by Vedantu’s tutors, helps students clarify doubts easily. Conquer class 8 Maths chapter 1 exercise 1.2, with Vedantu, today!

1. How many questions are there in Class 8 Chapter 1 Exercise 1.2 of NCERT textbook?

Ans: A total of seven questions are there in Class 8 Chapter 1 Exercise 1.2 of NCERT textbook. We at Vedantu provide the solutions to all these problems as well which are also of great quality. If you are a student of Class 8, then you can definitely rely on these NCERT Solutions provided by Vedantu.

2. What are the concepts that Class 8 Chapter 1 Exercise 1.2 deals with?

Ans:  Class 8 Chapter 1 Exercise 1.2 of NCERT book deals with a few advanced concepts related to rational numbers. Below are they:

• Representation of rational numbers on a number line.

• Rational Numbers between two rational numbers.

3. What are the benefits of using Vedantu’s NCERT Solutions for Class 8 Chapter 1 Exercise 1.2?

Ans: You will find the answer to a lot of doubts you face in the maths NCERT solutions Class 8 chapter 1 exercise 1.2. NCERT Class 8 Maths, ex. 1.2. require you to find given rational numbers on a number line, find a sequence of rational numbers smaller than the given one, find rational number sequences occurring between two given rational numbers, and the like. To guarantee full score when you attempt these in your Class 8 Maths paper, you can refer to the Vedantu Class 8 Maths Chapter 1.2 PDF solutions.

4. What kind of questions can you expect from this chapter?

Ans: For those familiar with integers and fractions, rational numbers may seem relatively easy. However, once you delve deep into the fundamental theorems and concepts, the complexity of the problems in the exercise becomes obvious; and, this is where Class 8 Maths NCERT Solutions Chapter 1 exercise 1.2 can be helpful. To ensure a clear understanding of these properties, and translate your understanding into problem-solving skills, you can seek assistance from Vedantu’s free PDF download of Class 8 Maths exercise 1.2 solutions. SHARE TWEET SHARE SUBSCRIBE