
Intensity Formulas - Definitions & Solved Example Questions
Example: What is the intensity of light incident normal to a circular surface of radius 5 cm from a 100 W source of light?
Solution:
r = 5 cm = 5 × 10–2 m, P = 100 W, \[I\]=?
\[I = \frac{P}{{\pi {r^2}}} = \frac{{100}}{{\pi \times {{(5 \times {{10}^{--2}})}^2}}} = 1.27 \times {10^4}W{m^{--2}}\]
Question: The intensity of a light source with power P on a circular surface of radius r placed at a certain distance is \[I\]. If at the same distance from another source, if the intensity on a circular surface of double the radius, is 4\[I\], then what is the power of the second source?
Options:
(a) 4 P
(b) 16 P
(c) 2 P
(d) P / 4
Answer: (b)
Best Seller - Grade 11 - JEE
View More>
Recently Updated Pages
CBSE Class 6 to 12 Maths, Physics & Chemistry Formula, Important Formulas

Profit Formula - Explanation, Calculation, Solved Examples, and FAQs

Perimeter of Rhombus Formula - Explanation, Area, Solved Examples, and FAQs

Loss Percentage – Formula, Solved Examples and FAQs

Compound Interest Formula – Formula Derivation, Applications and Problems

CBSE Class 8 Maths Chapter 6 - Squares and Square Roots Formulas

Trending topics
Physics Formulas

Mean Formula

CBSE Class 9 Maths Formulas

Algebraic Formulas for Class 9 – Complete List with Examples

Centripetal Force Formula

CBSE Class 10 Maths Formulas and Important Equations

Other Pages
One Day International Cricket

Important Days in February 2026 – Check All National & International Events List

List of 10 Fastest Centuries in ODIs

Chhatrapati Shivaji Maharaj Biography

Important Days in March 2026 Calendar With Holidays and Events

List of Winners Runnersup of the ICC Cricket World Cup

















