A free-falling object formula describes the self-governing phenomena of the body having some mass. A free-fall concept that talks about the body freely falling under gravity.
Assume that a body with velocity v is descending freely from a mountain of height (h) for time (t) seconds. Now, because of gravity (g), the body falls in the following manner:
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From this example, we can describe the free-fall motion formula. As it covers a certain distance, we can describe the free fall distance formula. An object possessing a free-fall object formula bears velocity, which we can calculate by using the free-fall velocity formula.
Since the object falling from a mountain has a maximum height, so does the object. The eight can be calculated by using the maximum height formula free fall. As there is a rate of change of velocity in an object while free-falling, so we can determine the free-fall acceleration formula as well.
So, on this page, we will cover all the equations for a falling body along with the free fall physics formula, and then derive the free fall formula as well.
Free Fall Physics Formula
We know that any object that is moving and being acted upon only by the force of gravity is said to be "in a state of free fall." Such an object experiences a downward acceleration of 9.8 ms-2.
We must note that whether the object is falling or rising towards its peak if it is under the sole influence of gravity, its acceleration value will always remain 9.8 ms-2.
So, the free-fall acceleration formula says that ‘a’ always equals ‘g’ under free fall.
Free Falling Bodies Formula
The free-fall motion formula covers the following equations for a falling body:
The maximum height formula free fall is:
h = 1/2 gt2
The free velocity formula is:
v2 = 2gh, and
v = gt
Now, let us derive free fall formula:
Free Falling Object Formula
Below are the following kinematic equations for deriving the free-fall motion formula:
First equation: if = vi + at ………..(1)
The second equation: d = vi + vf/2 . t…..(2)
The third equation: vf2 = vi2 + 2* a* d…..(3)
The fourth equation: d = vit + 1/2 at2…..(4)
Here, we replaced ‘s’ with ‘d’, and ‘d’ is the displacement
vi and vf are the initial and the final velocities of a falling object
a = acceleration, and
t = time in seconds
Free Fall Velocity Formula
We must note that the initial velocity of the object will become zero, so the first equation becomes:
vf = at
Also, according to the free-fall object formula, ‘a = g,’ so the equation (1) becomes:
vf = gt
This free-falling bodies formula is the free-fall velocity formula.
Also, from equation (3), we have:
vf2 = vi2 + 2* a* d
vf2 = 2gh…….(5)
This is again the free-fall velocity formula.
Free Fall Distance Formula
From equation (4), we see that displacement is the height traveled by the falling object. So substituting ‘with ‘h,’ and ‘a’ with ‘a,’ we have:
h = vit + 1/2 at2
Putting vi = 0:
h = 1/2 gt2
This is the required free fall equation with height ‘h.’
Maximum Height Formula Free Fall
From equation (5), we have:
vf2 = 2gh
The maximum height formula free fall is:
h = vf2/2g
Concepts to Free Falling Objects Problem Solving
There are a few concepts of free-fall motion that hold paramount importance when using the equations to analyze free-fall motion. These concepts are as follows:
A freely falling object experiences an acceleration of 9.8 ms-2. (Here, the negative sign indicates a downward acceleration or deceleration).Whether clearly stated or not, the value of the acceleration in the kinematic equations remains 9.8 ms-2 for any freely falling object.
If an object is mistakenly dropped (as opposed to being thrown) from an elevated height, its initial velocity remains 0 m/s.
If an object is projected upwards in an exactly vertical direction, it slows down as it rises upward. The point at which it reaches the peak of its trajectory is the point where the velocity is 0 m/s. This value can be used as one of the important motion parameters in the kinematic equations; for instance, the final velocity (vf) after traveling to the peak reaches a value of 0 m/s.
If an object is projected upwards in an exactly vertical direction, its velocity at which it is projected equals in magnitude but in a sign opposite to the velocity after it returns to the same height.
In the nutshell, a ball projected with an upward velocity of + 50 m/s will have a downward velocity of - 50 m/s when it returns to the same height.
Now, let’s apply these concepts in solving problems on a free fall formula:
Free Fall Formula Calculator
For understanding the free fall formula; let’s have a look at the below examples to apply the equation for the freely falling body:
Example 1: What will be the height of the body if it has a mass of 3 kg and after 8 seconds it reaches the ground?
Height h =?
Time t = 8s
You are acquainted with the concept that free fall is independent of mass. So, using the free-fall formula here:
h = 1/2 gt2
Putting g = 9.8 ms-2 and t = 8s:
h = 1/2 * 9.8* (8)2
On solving, we get:
h = 313.6 m
Answer: Therefore, the maximum height that a body covers to reach the ground is 313.6 m.
Example 2: The cotton ball falls after 4 s and the iron ball falls after 7 s. Determine which object falls with a higher velocity?
Since the velocity in free fall is independent of mass, so apply the following formula:
v (Velocity of cotton ball) = gt = 9.8 m/s2 × 4 s = 39.2 m/s
v (Velocity of iron ball) = gt = 9.8 m/s2 × 7 s = 68.6 m/s
We see that the iron ball falls with a higher velocity than the cotton ball.
Study Habits Students should adopt for Better Scores
Inculcating good habits in daily routine helps an individual to make their days more productive in many ways. Science is a scoring subject and one can secure a good percentage with required hard work. Many students find science a tough subject but it can surely help you to gain more marks as it is based on logistics and reason. Read on to know a few study habits students can adopt to gain more than 95% in science:
Maintain different notebooks for your formulas, equations, and theories as it will help students to find what they are looking for easily from the vast sea of the syllabus. This will also help in making the revision process quick and easy.
While preparing for the science exam make sure to solve all the numericals by yourself first. Surely students can take help from their teachers or books if they are stuck with some question but the first efforts should be made to do it all by yourself and try again and again. Learning and understanding concepts are important but it is also important that students are aware of when these are to be implemented and how.
Students should analyze while studying the topics they are finding difficult to understand and focus on them. If students are aware of their weak points only then they can focus more on them and make it their strength.
Regularity is an important habit students must inculcate to secure good marks. A student regular with his/ her syllabus will help them to understand their grasp on concepts. Regularity not only includes attending classes, lectures, and tuitions but also self-study sessions.
Students should first concentrate on the course books that are provided by the NCERT. Many students have the habit of jumping to reference books before finishing the NCERT. It is an observation that most of the questions asked in board exams are asked from NCERT books. Reference books can be used as a source of extra material or for in-depth study of a particular concept. However, NCERT is a student’s bible during the exam season.
Students should maintain a notebook for notes. Notes work as a summary of each concept during the revision period. It speeds up the process of revision and is a convenient way to learn from. Students can also include insights from their teachers or their insights for particular topics.
We call the free fall bodies formula the kinematic equations free fall because they are derived from kinematic equations.
Also, free fall is independent of the mass and it only depends on the height the object fell from.