## RD Sharma Class 9 Solutions Chapter 15 - Areas of Parallelograms and Triangles (Ex 15.2) Exercise 15.2 - Free PDF

## FAQs on RD Sharma Class 9 Solutions Chapter 15 - Areas of Parallelograms and Triangles (Ex 15.2) Exercise 15.2

**1. How to find the areas of a triangle and a parallelogram formed on same base?**

When a triangle and parallelogram are constructed on the same base, they are said to be formed between the same pair of parallel lines. Therefore, the height of the parallelogram and the triangle is the same. Now, let the length of the base be b and the height be h.

Area of triangle= \[\frac{1}{2}bh\]

Area of parallelogram= bh

Therefore, the area of the triangle is half the area of the parallelogram constructed on the same base.

**2. Give two properties of parallelogram and triangles.**

Two properties of a parallelogram are as follows.

There are two diagonals in a parallelogram, which bisect each other.

Every two opposite angles in a parallelogram are equal.

Two properties of a triangle are as follows.

The sum of all angles in any given triangle is 180 degrees.

The sum of any two sides of a given triangle is always greater than the measure of the third side.