RD Sharma Class 10 Solutions Chapter 3 - Exercise 3.8

Q: 4. A shopkeeper gives books on rent for reading to students. He takes a fixed charge for the two days and an additional charge for each day thereafter. Rima paid Rupees 22 for a book kept for six days, while Ruchi paid Rupees 16 for the book kept for four days, then what will be the charge for an extra day?(A) Rupees 5(B) Rupees 4(C) Rupees 3(D) Rupees 2

(C)Explanation: Let Rupees x be the fixed charge and Rupees y be the charge for each extra day.Then by the given conditionsx + 4y = 22 …..(i)x + 2y = 16 …..(ii)Subtracting equation (ii) from (i), we get: y = Rupees 3

RD Sharma Solutions

RD Sharma Class 10 Solutions Chapter 3 - Exercise 3.8

Last updated date: 23rd Apr 2024

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Download Free PDF of RD Sharma Class 10 Solutions Chapter 3 - Pair of Linear Equations in Two Variables (Ex 3.8) Exercise 3.8

Free PDF download of RD Sharma Class 10 Solutions Chapter 3 - Pair of Linear Equations in Two Variables Exercise 3.8 solved by Expert Mathematics Teachers on Vedantu.com. All Chapter 3 - Pair of Linear Equations in Two Variables Ex 3.8 Questions with Solutions for RD Sharma to help you to revise complete Syllabus and Score More marks.

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Pair of Linear Equations in Two Variables (Chapter 3, Class 10)

“Pair of Linear Equations in two variables” is the third chapter in the NCERT (CBSE) book of Class 10. A Linear Equation is an algebraic equation where each term has an exponent of 1 and when this equation is placed in a graph, it always results in a straight line. Hence, it is called a Linear Equation.

Example for the Linear Equation for two variables- We can take the example of a one-day cricket match between India and Sri Lanka played in Delhi where two Indian batsmen together scored 100 runs. We can see that the scores of neither of them are known, i.e., there are two unknown quantities. The unknown quantities can be expressed in the form of an equation. Thus, the number of runs scored by one of the batsmen is x, and the number of runs scored by the other is y. We know that x + y = 100, which is the equation we need. This is an example of a Linear Equation in two variables. It is conventional to denote the variables in such equations by x and y, but other letters may also be used.

FAQs on RD Sharma Class 10 Solutions Chapter 3 - Exercise 3.8

1. Where can I find study materials for Chapter 3 of CBSE Class 10?

Students can find study materials on the Vedantu app or website. Vedantu has all the solved questions with solutions, revision notes and important questions. Students can simply log in and access the study materials they are looking for. It is free and easily accessible. You may access all the free materials available and also get the help of subject experts/tutors online and clear your doubts if any.

2. Following concepts of Chapter 3 CBSE Class 10, if a pair of Linear Equations is consistent, then the lines will be

(a) always coincident

(b) parallel

(c) always intersecting

(d) intersecting or coincident

(d) If a pair of Linear Equations is consistent the two lines represented by these equations have a solution, this implies that either line is intersecting or coincident.

3. What is a Linear Equation as taught in Chapter 3 of CBSE Class 10?

A Linear Equation is defined as an equation with a maximum degree of 1. This means that in a Linear Equation, no variable has an exponent greater than 1. A Linear Equation's graph is always a straight line. The standard form of a Linear Equation in one variable is of the form Ax + B = 0. Here, x is a variable, and A and B are constants.

4. A shopkeeper gives books on rent for reading to students. He takes a fixed charge for the two days and an additional charge for each day thereafter. Rima paid Rupees 22 for a book kept for six days, while Ruchi paid Rupees 16 for the book kept for four days, then what will be the charge for an extra day?

(A) Rupees 5

(B) Rupees 4

(D) Rupees 2

(C)

Explanation: Let Rupees x be the fixed charge and Rupees y be the charge for each extra day.

Then by the given conditions

x + 4y = 22 …..(i)

x + 2y = 16 …..(ii)

Subtracting equation (ii) from (i), we get: y = Rupees 3

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