Answer
Verified
399.3k+ views
Hint: We have to draw the structure of \[1 - bromo - 1 - methylcyclohexane\] then only we can find the structure of alkene and understand the meaning of the word dehydrohalogenation.
Complete step by step solution:
Let's start with the formal definition, in dehydrohalogenation de stands for removal or elimination, hydro stands for hydrogen and halogen stands for halogen itself. So, dehydrohalogenation is the process of elimination of hydrogen and halogen. Therefore, we can understand that hydrogen bromide is being removed.
Now, we are given a substrate which is 1-Bromo-1-Methylcyclohexane whose molecular formula is $C_7H_13Br$. From the name of the substrate, we can see that the bromine, as well as the methyl group both, is present at the same position. So, the structure of the substrate is as follows
Now, in the presence of alcoholic KOH, bromine (halogen) and hydrogen from an adjacent carbon is being removed which leads to the formation of an alkene. The formation of alkene is shown below
Therefore we can conclude that the alkene formed is\[1 - methylcyclohex - 1 - ene\]. This nomenclature is due to the presence of a methyl group at 1st position and a double bond present between the 1st and 2nd position. The other products of this reaction are KBr and $H_2O$.
Additional information:
- Halogen groups represent all the atoms present in Group 17 of periodic table i.e. \[Fluorine{\text{ }}\left( F \right),{\text{ }}Chlorine{\text{ }}\left( {Cl} \right),{\text{ }}Bromine{\text{ }}\left( {Br} \right),{\text{ }}Iodine{\text{ }}\left( I \right),{\text{ }}and{\text{ }}Astatine{\text{ }}\left( {At} \right).\]
- Alcoholic KOH is being used so that KOH acts as a base not as a nucleophile, if KOH acts as a nucleophile it will lead to the formation of alcohol rather than an alkene.
Note: We must understand that quicklime $CaO$ is used in daily household works and with the demand increasing in its production; industrial revolution is taking place with proper enumeration using it.
Complete step by step solution:
Let's start with the formal definition, in dehydrohalogenation de stands for removal or elimination, hydro stands for hydrogen and halogen stands for halogen itself. So, dehydrohalogenation is the process of elimination of hydrogen and halogen. Therefore, we can understand that hydrogen bromide is being removed.
Now, we are given a substrate which is 1-Bromo-1-Methylcyclohexane whose molecular formula is $C_7H_13Br$. From the name of the substrate, we can see that the bromine, as well as the methyl group both, is present at the same position. So, the structure of the substrate is as follows
Now, in the presence of alcoholic KOH, bromine (halogen) and hydrogen from an adjacent carbon is being removed which leads to the formation of an alkene. The formation of alkene is shown below
Therefore we can conclude that the alkene formed is\[1 - methylcyclohex - 1 - ene\]. This nomenclature is due to the presence of a methyl group at 1st position and a double bond present between the 1st and 2nd position. The other products of this reaction are KBr and $H_2O$.
Additional information:
- Halogen groups represent all the atoms present in Group 17 of periodic table i.e. \[Fluorine{\text{ }}\left( F \right),{\text{ }}Chlorine{\text{ }}\left( {Cl} \right),{\text{ }}Bromine{\text{ }}\left( {Br} \right),{\text{ }}Iodine{\text{ }}\left( I \right),{\text{ }}and{\text{ }}Astatine{\text{ }}\left( {At} \right).\]
- Alcoholic KOH is being used so that KOH acts as a base not as a nucleophile, if KOH acts as a nucleophile it will lead to the formation of alcohol rather than an alkene.
Note: We must understand that quicklime $CaO$ is used in daily household works and with the demand increasing in its production; industrial revolution is taking place with proper enumeration using it.
Recently Updated Pages
Basicity of sulphurous acid and sulphuric acid are
Three beakers labelled as A B and C each containing 25 mL of water were taken A small amount of NaOH anhydrous CuSO4 and NaCl were added to the beakers A B and C respectively It was observed that there was an increase in the temperature of the solutions contained in beakers A and B whereas in case of beaker C the temperature of the solution falls Which one of the following statements isarecorrect i In beakers A and B exothermic process has occurred ii In beakers A and B endothermic process has occurred iii In beaker C exothermic process has occurred iv In beaker C endothermic process has occurred
What is the stopping potential when the metal with class 12 physics JEE_Main
The momentum of a photon is 2 times 10 16gm cmsec Its class 12 physics JEE_Main
How do you arrange NH4 + BF3 H2O C2H2 in increasing class 11 chemistry CBSE
Is H mCT and q mCT the same thing If so which is more class 11 chemistry CBSE
Trending doubts
Difference Between Plant Cell and Animal Cell
Difference between Prokaryotic cell and Eukaryotic class 11 biology CBSE
Fill the blanks with the suitable prepositions 1 The class 9 english CBSE
Change the following sentences into negative and interrogative class 10 english CBSE
Summary of the poem Where the Mind is Without Fear class 8 english CBSE
Give 10 examples for herbs , shrubs , climbers , creepers
Write an application to the principal requesting five class 10 english CBSE
What organs are located on the left side of your body class 11 biology CBSE
What is the z value for a 90 95 and 99 percent confidence class 11 maths CBSE