Answer
Verified
445.2k+ views
Hint:In this question we have to find the sequence with \[{n^{th}}\] term and \[{a_n} = 3 + 4n\].
The expression \[{({a_n})_{n \in N}}\] denotes a sequence whose \[{n^{th}}\] element is given by the variable \[{a_n}\].
The \[{n^{th}}\] element of the sequence is given.Therefore we can get the \[{1^{st}},{\text{ }}{2^{nd}},\,{\text{ }}{3^{rd}},\,\;{4^{th}},\;\;....\] elements of the sequence respectively by putting the value of \[n = 1,{\text{ }}2,{\text{ }}3,{\text{ }}4,{\text{ }}.....\] in the expression \[{a_n}\].
Complete step-by-step answer:
It is given that the \[{n^{th}}\] term of the sequence is \[{a_n} = 3 + 4n\].
We need to find out the elements of the sequence.
By putting the value of \[n = 1,{\text{ }}2,{\text{ }}3,{\text{ }}4,\,{\text{ }}.....\] in the expression \[{a_n}\], we will get the \[{1^{st}},\;{\text{ }}{2^{nd}},\,{\text{ }}{3^{rd}},{\text{ }}{4^{th}},\,\,....\] terms of the sequence respectively.
Putting the value of \[n = 1\] in \[{a_n}\] we get,
The first term of the sequence, \[{a_1} = 3 + 4 \times 1 = 3 + 4 = 7\]
Putting the value of \[n = 2\] in \[{a_n}\] we get,
The second term of the sequence, \[{a_2} = 3 + 4 \times 2 = 3 + 8 = 11\]
Putting the value of \[n = 3\] in \[{a_n}\] we get,
The third term of the sequence, \[{a_3} = 3 + 4 \times 3 = 3 + 12 = 15\]
Putting the value of \[n = 4\] in \[{a_n}\] we get,
The fourth term of the sequence, \[{a_4} = 3 + 4 \times 4 = 3 + 16 = 19\]
Similarly we can find all the elements of the sequence.
Thus we get, the elements of the sequence are, \[7,{\text{ }}11,\;{\text{ }}15,\;\;19,\;.....\]
Hence we get, the sequence with \[{n^{th}}\] term \[{a_n} = 3 + 4n\] is \[7,{\text{ }}11,\;{\text{ }}15,\;\;19,\;.....\] .
So, the correct answer is “Option A”.
Note:In mathematics, a sequence is an enumerated collection of objects in which repetitions are allowed and order matters. Like a set, it contains members. The number of elements is called the length of the sequence.
The expression \[{({a_n})_{n \in N}}\] denotes a sequence whose \[{n^{th}}\] element is given by the variable \[{a_n}\].
The expression \[{({a_n})_{n \in N}}\] denotes a sequence whose \[{n^{th}}\] element is given by the variable \[{a_n}\].
The \[{n^{th}}\] element of the sequence is given.Therefore we can get the \[{1^{st}},{\text{ }}{2^{nd}},\,{\text{ }}{3^{rd}},\,\;{4^{th}},\;\;....\] elements of the sequence respectively by putting the value of \[n = 1,{\text{ }}2,{\text{ }}3,{\text{ }}4,{\text{ }}.....\] in the expression \[{a_n}\].
Complete step-by-step answer:
It is given that the \[{n^{th}}\] term of the sequence is \[{a_n} = 3 + 4n\].
We need to find out the elements of the sequence.
By putting the value of \[n = 1,{\text{ }}2,{\text{ }}3,{\text{ }}4,\,{\text{ }}.....\] in the expression \[{a_n}\], we will get the \[{1^{st}},\;{\text{ }}{2^{nd}},\,{\text{ }}{3^{rd}},{\text{ }}{4^{th}},\,\,....\] terms of the sequence respectively.
Putting the value of \[n = 1\] in \[{a_n}\] we get,
The first term of the sequence, \[{a_1} = 3 + 4 \times 1 = 3 + 4 = 7\]
Putting the value of \[n = 2\] in \[{a_n}\] we get,
The second term of the sequence, \[{a_2} = 3 + 4 \times 2 = 3 + 8 = 11\]
Putting the value of \[n = 3\] in \[{a_n}\] we get,
The third term of the sequence, \[{a_3} = 3 + 4 \times 3 = 3 + 12 = 15\]
Putting the value of \[n = 4\] in \[{a_n}\] we get,
The fourth term of the sequence, \[{a_4} = 3 + 4 \times 4 = 3 + 16 = 19\]
Similarly we can find all the elements of the sequence.
Thus we get, the elements of the sequence are, \[7,{\text{ }}11,\;{\text{ }}15,\;\;19,\;.....\]
Hence we get, the sequence with \[{n^{th}}\] term \[{a_n} = 3 + 4n\] is \[7,{\text{ }}11,\;{\text{ }}15,\;\;19,\;.....\] .
So, the correct answer is “Option A”.
Note:In mathematics, a sequence is an enumerated collection of objects in which repetitions are allowed and order matters. Like a set, it contains members. The number of elements is called the length of the sequence.
The expression \[{({a_n})_{n \in N}}\] denotes a sequence whose \[{n^{th}}\] element is given by the variable \[{a_n}\].
Recently Updated Pages
How many sigma and pi bonds are present in HCequiv class 11 chemistry CBSE
Mark and label the given geoinformation on the outline class 11 social science CBSE
When people say No pun intended what does that mea class 8 english CBSE
Name the states which share their boundary with Indias class 9 social science CBSE
Give an account of the Northern Plains of India class 9 social science CBSE
Change the following sentences into negative and interrogative class 10 english CBSE
Trending doubts
Difference Between Plant Cell and Animal Cell
Difference between Prokaryotic cell and Eukaryotic class 11 biology CBSE
Fill the blanks with the suitable prepositions 1 The class 9 english CBSE
Differentiate between homogeneous and heterogeneous class 12 chemistry CBSE
Which are the Top 10 Largest Countries of the World?
One cusec is equal to how many liters class 8 maths CBSE
Give 10 examples for herbs , shrubs , climbers , creepers
The mountain range which stretches from Gujarat in class 10 social science CBSE
The Equation xxx + 2 is Satisfied when x is Equal to Class 10 Maths