Answer

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Hint:- It can have any pair of integers as an answer satisfying the given condition.

An integer is a whole number that can be positive, negative or zero.

Let the pair of integers be a and b.

Now, we have only one condition mentioned in the question. And we have to find two numbers.

So, we can have many different pairs of integers following the condition.

According to the condition, ${\text{a + b = - 3}}$

If a = 1 , putting in above equation we get,

$

1{\text{ + b = - 3}} \\

{\text{b = - 3 - 1}} \\

{\text{ = - 4}} \\

$

Hence, we have a pair of integers (1,-4) which satisfies the given condition.

The answer is (1,-4).

Note:- For finding a single unknown value, we need just one algebraic equation. But, if we need to find more than one unknown value , we will need a number of equations equal to the number of unknown values to get a unique solution. But if the number of equations is less than the number of unknowns then there can be many solutions. And if the number of equations are more , still we can have a unique solution to the problem.

An integer is a whole number that can be positive, negative or zero.

Let the pair of integers be a and b.

Now, we have only one condition mentioned in the question. And we have to find two numbers.

So, we can have many different pairs of integers following the condition.

According to the condition, ${\text{a + b = - 3}}$

If a = 1 , putting in above equation we get,

$

1{\text{ + b = - 3}} \\

{\text{b = - 3 - 1}} \\

{\text{ = - 4}} \\

$

Hence, we have a pair of integers (1,-4) which satisfies the given condition.

The answer is (1,-4).

Note:- For finding a single unknown value, we need just one algebraic equation. But, if we need to find more than one unknown value , we will need a number of equations equal to the number of unknown values to get a unique solution. But if the number of equations is less than the number of unknowns then there can be many solutions. And if the number of equations are more , still we can have a unique solution to the problem.

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