Write the first three terms in each of the sequence defined by the following:
1) ${a_n} = 3n + 2$
2) ${a_n} = {n^2} + 1$
Answer
619.5k+ views
Hint: The sequence of each term gives as many different values.
Our discussion for this sequence is about the first three terms only. Yet the sequence \[{a_n}\] has n number of values, when we put different values to the sequence it gives a different number.
Now, we are going to substitute positive integers for n of order \[1,2,3\] that is \[{a_1},{a_2},{a_3}\].
Complete step-by-step answer:
1) \[{a_n} = 3n + 2\]
Take n values for first three terms
So, \[n = 1,2,3\] we get
If we take \[n = 1\] ,
\[ \Rightarrow {a_1} = 3(1) + 2\]
\[ \Rightarrow {a_1} = 3 + 2\]
\[ \Rightarrow {a_1} = 5\]
If we take \[n = 2\] ,
\[ \Rightarrow {a_2} = 3(2) + 2\]
\[ \Rightarrow {a_2} = 6 + 2\]
\[ \Rightarrow {a_2} = 8\]
If we take \[n = 3\] ,
\[ \Rightarrow {a_3} = 3(3) + 2\]
\[ \Rightarrow {a_3} = 9 + 2\]
\[ \Rightarrow {a_3} = 11\]
Hence we get, \[{a_1} = 5,{a_2} = 8,{a_3} = 11\]
The first three terms for the sequence \[{a_n} = 3n + 2\] is \[5,8,11\]
2) \[{a_n} = {n^2} + 1\]
Take n values for first three terms
So, \[n = 1,2,3\]
If we take \[n = 1\]
\[ \Rightarrow {a_1} = {1^2} + 1\]
\[ \Rightarrow {a_1} = 1 + 1\]
\[ \Rightarrow {a_1} = 2\]
If we take \[n = 2\] ,
\[ \Rightarrow {a_2} = {2^2} + 1\]
\[ \Rightarrow {a_2} = 4 + 1\]
\[ \Rightarrow {a_2} = 5\]
If we take \[n = 3\] ,
\[ \Rightarrow {a_3} = {3^2} + 1\]
\[ \Rightarrow {a_3} = 9 + 1\]
\[ \Rightarrow {a_3} = 10\]
Hence we get, \[{a_1} = 2,{a_2} = 5,{a_3} = 10\]
$\therefore $The first three terms for the sequence \[{a_n} = {n^2} + 1\] is \[2,5,10\]
Note:Form the above observation in first sequence \[{a_n} = 3n + 2\]
if n is an odd number, the sequence is odd.
If n is an even number, the sequence is even.
In same way, the sequence \[{a_n} = {n^2} + 1\]
If n is an odd number, the sequence is even.
If n is an even number, the sequence is odd.
Both the sequences have n number of terms, for our convenience we take the first three terms. In some cases, they ask randomly, give value for \[n = 10\] or \[n = 20\] for the sequence, we can find that also by substitution.
Our discussion for this sequence is about the first three terms only. Yet the sequence \[{a_n}\] has n number of values, when we put different values to the sequence it gives a different number.
Now, we are going to substitute positive integers for n of order \[1,2,3\] that is \[{a_1},{a_2},{a_3}\].
Complete step-by-step answer:
1) \[{a_n} = 3n + 2\]
Take n values for first three terms
So, \[n = 1,2,3\] we get
If we take \[n = 1\] ,
\[ \Rightarrow {a_1} = 3(1) + 2\]
\[ \Rightarrow {a_1} = 3 + 2\]
\[ \Rightarrow {a_1} = 5\]
If we take \[n = 2\] ,
\[ \Rightarrow {a_2} = 3(2) + 2\]
\[ \Rightarrow {a_2} = 6 + 2\]
\[ \Rightarrow {a_2} = 8\]
If we take \[n = 3\] ,
\[ \Rightarrow {a_3} = 3(3) + 2\]
\[ \Rightarrow {a_3} = 9 + 2\]
\[ \Rightarrow {a_3} = 11\]
Hence we get, \[{a_1} = 5,{a_2} = 8,{a_3} = 11\]
The first three terms for the sequence \[{a_n} = 3n + 2\] is \[5,8,11\]
2) \[{a_n} = {n^2} + 1\]
Take n values for first three terms
So, \[n = 1,2,3\]
If we take \[n = 1\]
\[ \Rightarrow {a_1} = {1^2} + 1\]
\[ \Rightarrow {a_1} = 1 + 1\]
\[ \Rightarrow {a_1} = 2\]
If we take \[n = 2\] ,
\[ \Rightarrow {a_2} = {2^2} + 1\]
\[ \Rightarrow {a_2} = 4 + 1\]
\[ \Rightarrow {a_2} = 5\]
If we take \[n = 3\] ,
\[ \Rightarrow {a_3} = {3^2} + 1\]
\[ \Rightarrow {a_3} = 9 + 1\]
\[ \Rightarrow {a_3} = 10\]
Hence we get, \[{a_1} = 2,{a_2} = 5,{a_3} = 10\]
$\therefore $The first three terms for the sequence \[{a_n} = {n^2} + 1\] is \[2,5,10\]
Note:Form the above observation in first sequence \[{a_n} = 3n + 2\]
if n is an odd number, the sequence is odd.
If n is an even number, the sequence is even.
In same way, the sequence \[{a_n} = {n^2} + 1\]
If n is an odd number, the sequence is even.
If n is an even number, the sequence is odd.
Both the sequences have n number of terms, for our convenience we take the first three terms. In some cases, they ask randomly, give value for \[n = 10\] or \[n = 20\] for the sequence, we can find that also by substitution.
Recently Updated Pages
Master Class 12 Business Studies: Engaging Questions & Answers for Success

Master Class 12 Biology: Engaging Questions & Answers for Success

Master Class 12 Chemistry: Engaging Questions & Answers for Success

Class 12 Question and Answer - Your Ultimate Solutions Guide

Master Class 11 Social Science: Engaging Questions & Answers for Success

Master Class 11 English: Engaging Questions & Answers for Success

Trending doubts
Explain the Treaty of Vienna of 1815 class 10 social science CBSE

Who Won 36 Oscar Awards? Record Holder Revealed

What is the median of the first 10 natural numbers class 10 maths CBSE

Why is it 530 pm in india when it is 1200 afternoon class 10 social science CBSE

The highest temperature in Karnataka is recorded in class 10 social science CBSE

Define Potential, Developed, Stock and Reserved resources

