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Hint: Bonds are responsible for holding atoms in a molecule. The electrons are responsible for formation of various bonds. The length of bonds depends upon various factors. One such factor is bond order, that defines the length of any bond. The bond order is the amount of bonds present.
Complete answer: Bond length of any bond in an atom is the measure of between the nuclei of the bonded atoms. Some factors that affect bond length of an atom are:
-Size of the atom: A greater size atom has more length of bond.
-Multiplicity of a bond: Greater the multiplicity of the bonds less is the bond length. Like a compound with triple bond has less bond length, then the compound with double bonds, while a compound with single bonds has greatest bond length.
-Types of hybridization: S orbital has a small size, so, more is the s character, and less is the bond length.
- Delocalization of electrons through resonance also affects the size of bonds.
Since, the compound contains unsaturation, we will see the resonance factor. The resonating structures of the compound are,
We can see that C1-C2 are having a partial double bond character throughout the delocalization of electrons, while C3-C4 are having a single bond character.
As stated before, that multiplicity of bonds reduces the bond length, while the bond length of a single bond is more, so, due to the resonating structures, C1-C2 has less bond length than C3-C4.
Hence, option (b), C1-C2 bond is shorter than C3-C4 bond is correct.
Note: Bond order which is the number of bonds present also affects the length of bonds. More bond order means less bond length, this factor is also related to resonating structures.
Complete answer: Bond length of any bond in an atom is the measure of between the nuclei of the bonded atoms. Some factors that affect bond length of an atom are:
-Size of the atom: A greater size atom has more length of bond.
-Multiplicity of a bond: Greater the multiplicity of the bonds less is the bond length. Like a compound with triple bond has less bond length, then the compound with double bonds, while a compound with single bonds has greatest bond length.
-Types of hybridization: S orbital has a small size, so, more is the s character, and less is the bond length.
- Delocalization of electrons through resonance also affects the size of bonds.
Since, the compound contains unsaturation, we will see the resonance factor. The resonating structures of the compound are,
We can see that C1-C2 are having a partial double bond character throughout the delocalization of electrons, while C3-C4 are having a single bond character.
As stated before, that multiplicity of bonds reduces the bond length, while the bond length of a single bond is more, so, due to the resonating structures, C1-C2 has less bond length than C3-C4.
Hence, option (b), C1-C2 bond is shorter than C3-C4 bond is correct.
Note: Bond order which is the number of bonds present also affects the length of bonds. More bond order means less bond length, this factor is also related to resonating structures.
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