Courses
Courses for Kids
Free study material
Offline Centres
More
Store Icon
Store

Which of the following is used to dissolve gold?
A. Hydrochloric Acid
B. Sulphuric Acid
C. Nitric Acid
D. Aqua Regia

seo-qna
Last updated date: 20th Jun 2024
Total views: 414k
Views today: 6.14k
Answer
VerifiedVerified
414k+ views
Hint: Gold is a highly inert metal and therefore special treatment is to be done to dissolve it. So, we have to use a very strong oxidizing agent so as to oxidize gold. To solve this question, we have to find the acid or a mixture of acids which is most oxidizing in nature.

Complete answer:
The reason behind the fast that gold solid is largely unreactive is because the electrons in gold fall at energies which few molecules or chemicals match (i.e., due to relativistic effects). Aqua regia is used for dissolving gold.
Aqua regia is a mixture of concentrated nitric acid and concentrated hydrochloric acid in the ratio of c$1:3$. Either of the two acids would not be able to do this alone as their function in aqua regia are different.
$HN{{O}_{3}}$ is a powerful oxidizer which oxidizes a small quantity of gold to $A{{u}^{3+}}$ ions. $HCl$ in the solution provides $C{{l}^{-}}$ ions to $A{{u}^{3+}}$ ions to form the complex ion $\left[ AuC{{l}_{4}} \right]$. The reaction continues until it reaches an equilibrium. This is how it dissolves gold.
So, the correct answer is “Option D”.

Note: Aqua regia dissolves other inert take metals like platinum too. Aqua regia is a yellow-orange or red fuming liquid and it can dissolve the noble metals, gold and platinum, though not all metals. In aqua regia oxidizing agent present is the nascent chlorine which reacts with noble metals to form their chlorides and gets them dissolved.