Which of the following is the strongest reducing agent in aqueous medium?
A. \[Mg\]
B. \[Na\]
C. \[Li\]
D. \[Ca\]
Answer
622.2k+ views
Hint: Lithium has little size and enormous warmth of hydration. The hydration vitality more than remunerates the ionization vitality. This results in high oxidation potential for \[Li\].
Complete step-by-step answer:
This expands the straightforwardness with which the accompanying change happens.
\[Li(s)\to Li+{{e}^{-}}\]
Because of this, lithium is the most grounded diminishing operator in watery solutions. Undoubtedly, antacid metals are acceptable decreasing specialists attributable to inexactly held single "\[n{{s}^{1}}\]" valence electrons.
In fact, "extreme" honourable gas centre gives powerful protection and consequently it has low ionization vitality.
Further, diminishing character or the reactivity of antacid metals increments going down the gathering in vaporous state.
It is supposed to be for the most part because of the expansion in the quantity of shells among different variables.
Based on this conversation, \[Li\] is the most fragile lessening specialist and \[Cs\] is the most grounded diminishing operator (among salt metals) in vaporous basic state.
Nonetheless, for the most part we manage conduct and responses in water (fluid arrangement). Diminishing or oxidizing conduct is subsequently referenced to be needy upon or identified with the "terminal possibilities". Further, as should be obvious from action arrangement, anode potential is identified with the development/decrease of watery particles from/into metals in their stable physical state.
Thus, as a matter of course, diminishing character is estimated by oxidation potential or the inclination of metals to lose electrons to shape (solvated) particles in arrangement.
The correct answer is C.
Note: Lithium being little in size has high ionization enthalpy. Then again in light of little size it is broadly hydrated and has exceptionally high hydration enthalpy. This high hydration enthalpy repays the high vitality expected to evacuate electrons. In this manner \[Li\] tends to lose electrons in arrangement than other antacid metals. In this manner, \[Li\] is the most grounded decreasing operator.
Complete step-by-step answer:
This expands the straightforwardness with which the accompanying change happens.
\[Li(s)\to Li+{{e}^{-}}\]
Because of this, lithium is the most grounded diminishing operator in watery solutions. Undoubtedly, antacid metals are acceptable decreasing specialists attributable to inexactly held single "\[n{{s}^{1}}\]" valence electrons.
In fact, "extreme" honourable gas centre gives powerful protection and consequently it has low ionization vitality.
Further, diminishing character or the reactivity of antacid metals increments going down the gathering in vaporous state.
It is supposed to be for the most part because of the expansion in the quantity of shells among different variables.
Based on this conversation, \[Li\] is the most fragile lessening specialist and \[Cs\] is the most grounded diminishing operator (among salt metals) in vaporous basic state.
Nonetheless, for the most part we manage conduct and responses in water (fluid arrangement). Diminishing or oxidizing conduct is subsequently referenced to be needy upon or identified with the "terminal possibilities". Further, as should be obvious from action arrangement, anode potential is identified with the development/decrease of watery particles from/into metals in their stable physical state.
Thus, as a matter of course, diminishing character is estimated by oxidation potential or the inclination of metals to lose electrons to shape (solvated) particles in arrangement.
The correct answer is C.
Note: Lithium being little in size has high ionization enthalpy. Then again in light of little size it is broadly hydrated and has exceptionally high hydration enthalpy. This high hydration enthalpy repays the high vitality expected to evacuate electrons. In this manner \[Li\] tends to lose electrons in arrangement than other antacid metals. In this manner, \[Li\] is the most grounded decreasing operator.
Recently Updated Pages
Three beakers labelled as A B and C each containing 25 mL of water were taken A small amount of NaOH anhydrous CuSO4 and NaCl were added to the beakers A B and C respectively It was observed that there was an increase in the temperature of the solutions contained in beakers A and B whereas in case of beaker C the temperature of the solution falls Which one of the following statements isarecorrect i In beakers A and B exothermic process has occurred ii In beakers A and B endothermic process has occurred iii In beaker C exothermic process has occurred iv In beaker C endothermic process has occurred

Master Class 10 Social Science: Engaging Questions & Answers for Success

Master Class 10 Science: Engaging Questions & Answers for Success

Master Class 10 Maths: Engaging Questions & Answers for Success

Master Class 10 General Knowledge: Engaging Questions & Answers for Success

Master Class 10 Computer Science: Engaging Questions & Answers for Success

Trending doubts
Explain the Treaty of Vienna of 1815 class 10 social science CBSE

In cricket, what is the term for a bowler taking five wickets in an innings?

Who Won 36 Oscar Awards? Record Holder Revealed

What is the name of Japan Parliament?

What is the median of the first 10 natural numbers class 10 maths CBSE

Why is it 530 pm in india when it is 1200 afternoon class 10 social science CBSE

