Question

What is the normality of 2M ${H_2}S{O_4}$ ?

Answer 1

Hint: Normality is denoted by letter N and is referred to as the equivalent concentration of a solution. Normally it is calculated according to the formula:
      $N = Molarity \times Basicity$
Or $N = Molarity \times Acidity$

Complete step by step answer:
Normality is one of the expressions used to measure the concentration of a solution.
Normality as per definition is defined as the number of gram or mole equivalents of solute present in one litre of the solution.
Normality can be calculated using number of formulas:
$Normality = \dfrac{{\left( {Number{\text{ of gram equivalents}}} \right)}}{{Volume{\text{ of solution in litres}}}}$

$Normality = Weight{\text{ of solute (gram)}} \times {\text{Equivalent weight}} \times {\text{Volume (L)}}$

$N = Molarity \times Molar{\text{ mass}} \times {\left[ {equivalent{\text{ mass}}} \right]^{ - 1}}$

$N = Molarity \times {\text{Basicity}}$
                                 Or
              $N = Molarity \times Acidity$
The units of normality are$eq{L^{ - 1}}$or $meq{L^{ - 1}}$.
Now, in the given question we have to calculate the normality of 2M ${H_2}S{O_4}$.
As we know that, the acidity is the number of replaceable ${H^ + }$ ions present in an acid.
So, for ${H_2}S{O_4}$, there are two replaceable ${H^ + }$ ions in ${H_2}S{O_4}$.
Therefore, acidity= 2
Now, using the formula,
$Normality = Molarity \times Acidity$
N=$2 \times 2$ [Molarity is given to be 2M]
N= 4N
Hence, the normality of 2M ${H_2}S{O_4}$ is 4 N.

Note:
The term number of gram equivalents is related to normality. Gram equivalents refer to the ratio of weight of the solute to the equivalent weight of the solute.