Answer
Verified
402.3k+ views
Hint: You can start by defining a vector quantity. Then convert the velocity of the trains which is given in $ km/hr $ to $ m/\sec $ . Now calculate the relative speed of both the trains. Then use the equation $ Velocity = \dfrac{{Displacement}}{{Time}} $ to find out the length of the trains which will be half of the displacement.
Complete step-by-step answer:
A vector is a mathematical quantity that has both a magnitude (size) and a direction. To imagine what a vector is like, imagine asking someone for directions in an unknown area and they tell you, “Go $ 5km $ towards the West”. In this sentence, we see an example of a displacement vector, “\[5km\]” is the magnitude of the displacement vector and “towards the North” is the indicator of the direction of the displacement vector.
A vector quantity is different from a scalar quantity in the fact that a scalar quantity has only magnitude, but a vector quantity possesses both direction and magnitude. Unlike scalar quantities, vector quantities cannot undergo any mathematical operation, instead they undergo Dot product and Cross product.
Some examples of vectors are – Displacement, Force, Acceleration, Velocity, Momentum, etc.
Let the length of each train be $ x $ .
For the faster train to pass the slower train it will have to train a distance of $ 2x $ .
Given
$ {v_f} = 46km/hr = 46 \times \dfrac{5}{{18}}m/s = $ Velocity of the faster train
$ {v_s} = 36km/hr = 36 \times \dfrac{5}{{18}}m/s = $ Velocity of the slower train
So the relative velocity of the faster train is
$ {v_r} = {v_f} - {v_s} $
$ \Rightarrow {v_r} = 46 \times \dfrac{5}{{18}} - 36 \times \dfrac{5}{{18}} $
$ \Rightarrow {v_r} = 10 \times \dfrac{5}{{18}} $
$ \Rightarrow {v_r} = \dfrac{{25}}{9}m/s $
We also know that
$ Velocity = \dfrac{{Displacement}}{{Time}} $
$ \Rightarrow \dfrac{{25}}{9} = \dfrac{{Displacement}}{{36}} $
$ \Rightarrow Displacement = 100m $
Here the displacement is equal to the length of the two trains
$ \Rightarrow 2x = 100 $
$ \therefore x = 50m $
Hence, option A is the correct choice
Note – In the solution we used the concept of relative velocity. We used it to determine the velocity of the faster rain with respect to the velocity of the slower train. Amazingly no velocity measured in the universe is absolute, each body that is measured, is measured against the velocity of another body. For example - The velocity of the trains are measured against the velocity of the earth.
Complete step-by-step answer:
A vector is a mathematical quantity that has both a magnitude (size) and a direction. To imagine what a vector is like, imagine asking someone for directions in an unknown area and they tell you, “Go $ 5km $ towards the West”. In this sentence, we see an example of a displacement vector, “\[5km\]” is the magnitude of the displacement vector and “towards the North” is the indicator of the direction of the displacement vector.
A vector quantity is different from a scalar quantity in the fact that a scalar quantity has only magnitude, but a vector quantity possesses both direction and magnitude. Unlike scalar quantities, vector quantities cannot undergo any mathematical operation, instead they undergo Dot product and Cross product.
Some examples of vectors are – Displacement, Force, Acceleration, Velocity, Momentum, etc.
Let the length of each train be $ x $ .
For the faster train to pass the slower train it will have to train a distance of $ 2x $ .
Given
$ {v_f} = 46km/hr = 46 \times \dfrac{5}{{18}}m/s = $ Velocity of the faster train
$ {v_s} = 36km/hr = 36 \times \dfrac{5}{{18}}m/s = $ Velocity of the slower train
So the relative velocity of the faster train is
$ {v_r} = {v_f} - {v_s} $
$ \Rightarrow {v_r} = 46 \times \dfrac{5}{{18}} - 36 \times \dfrac{5}{{18}} $
$ \Rightarrow {v_r} = 10 \times \dfrac{5}{{18}} $
$ \Rightarrow {v_r} = \dfrac{{25}}{9}m/s $
We also know that
$ Velocity = \dfrac{{Displacement}}{{Time}} $
$ \Rightarrow \dfrac{{25}}{9} = \dfrac{{Displacement}}{{36}} $
$ \Rightarrow Displacement = 100m $
Here the displacement is equal to the length of the two trains
$ \Rightarrow 2x = 100 $
$ \therefore x = 50m $
Hence, option A is the correct choice
Note – In the solution we used the concept of relative velocity. We used it to determine the velocity of the faster rain with respect to the velocity of the slower train. Amazingly no velocity measured in the universe is absolute, each body that is measured, is measured against the velocity of another body. For example - The velocity of the trains are measured against the velocity of the earth.
Recently Updated Pages
Basicity of sulphurous acid and sulphuric acid are
Assertion The resistivity of a semiconductor increases class 13 physics CBSE
Three beakers labelled as A B and C each containing 25 mL of water were taken A small amount of NaOH anhydrous CuSO4 and NaCl were added to the beakers A B and C respectively It was observed that there was an increase in the temperature of the solutions contained in beakers A and B whereas in case of beaker C the temperature of the solution falls Which one of the following statements isarecorrect i In beakers A and B exothermic process has occurred ii In beakers A and B endothermic process has occurred iii In beaker C exothermic process has occurred iv In beaker C endothermic process has occurred
The branch of science which deals with nature and natural class 10 physics CBSE
What is the stopping potential when the metal with class 12 physics JEE_Main
The momentum of a photon is 2 times 10 16gm cmsec Its class 12 physics JEE_Main
Trending doubts
Difference between Prokaryotic cell and Eukaryotic class 11 biology CBSE
Difference Between Plant Cell and Animal Cell
Fill the blanks with the suitable prepositions 1 The class 9 english CBSE
Change the following sentences into negative and interrogative class 10 english CBSE
Give 10 examples for herbs , shrubs , climbers , creepers
What organs are located on the left side of your body class 11 biology CBSE
Write an application to the principal requesting five class 10 english CBSE
What is the type of food and mode of feeding of the class 11 biology CBSE
Name 10 Living and Non living things class 9 biology CBSE