Two supplementary angles are in the ratio \[5:4\]. Find the angles.
Answer
585.3k+ views
Hint: Here we assume both the angles as separate variables. Then using the information in the question we form an equation of sum of angles. Also, using the concept of ratio, we write the angles in the ratio form and equate it to the given ratio.
* Two angles are said to be supplementary to each other if they have the sum of angles as \[{180^ \circ }\]
* Ratio \[m:n\]can be written in the form of fraction as \[\dfrac{m}{n}\].
Complete answer:
Let us assume one angle as ‘x’ and another angle as ‘y’.
Since we know both the angles are supplementary angles, then their sum must be equal to \[{180^ \circ }\]
So we can write the sum of angles x and y as \[{180^ \circ }\]
\[ \Rightarrow x + y = {180^ \circ }\] … (1)
Now we are given that the angles are in the ratio \[5:4\]
So we can write that the ratio of angles x and y is \[5:4\].
Substitute the values of angles we assumed in the beginning of the solution.
\[ \Rightarrow x:y = 5:4\] … (2)
Now since we know we can convert the ratio \[a:b\] into a form of fraction as \[\dfrac{a}{b}\].
Therefore, we can write the equation (2) as
\[ \Rightarrow \dfrac{x}{y} = \dfrac{5}{4}\]
Multiply both sides of the equation by y
\[ \Rightarrow \dfrac{x}{y} \times y = \dfrac{5}{4} \times y\]
Cancel the same terms from numerator and denominator.
\[ \Rightarrow x = \dfrac{5}{4}y\] … (3)
Substitute the value of x from equation (3) in equation (1).
\[ \Rightarrow \dfrac{{5y}}{4} + y = {180^ \circ }\]
Take LCM on the left hand side of the equation.
\[ \Rightarrow \dfrac{{5y + 4y}}{4} = {180^ \circ }\]
Calculate the sum in the numerator.
\[ \Rightarrow \dfrac{{9y}}{4} = {180^ \circ }\]
Multiply both sides by \[\dfrac{4}{9}\]
\[ \Rightarrow \dfrac{{9y}}{4} \times \dfrac{4}{9} = {180^ \circ } \times \dfrac{4}{9}\]
Cancel out the same terms from numerator and denominator.
\[ \Rightarrow y = {\left( {20 \times 4} \right)^ \circ }\]
Calculate the product.
\[ \Rightarrow y = {80^ \circ }\]
Now we substitute the value of y in equation (1) to calculate the value of x.
\[ \Rightarrow x + {80^ \circ } = {180^ \circ }\]
Shift all constants to one side of the equation.
\[ \Rightarrow x = {180^ \circ } - {80^ \circ }\]
Calculate the value on RHS.
\[ \Rightarrow x = {100^ \circ }\]
\[\therefore \]Two supplementary angles that are in the ratio \[5:4\] are \[{100^ \circ }\] and \[{80^ \circ }\]
Note:
Students many times make the equation formed by the ratio as a complex equation when they cross multiply the values to both sides and then solve. Always try to keep that value on one side of the equation which can later be directly substituted in another equation. Also, keep in mind ratio should always be in simplest form i.e. there should not be any common factor between numerator and denominator.
* Two angles are said to be supplementary to each other if they have the sum of angles as \[{180^ \circ }\]
* Ratio \[m:n\]can be written in the form of fraction as \[\dfrac{m}{n}\].
Complete answer:
Let us assume one angle as ‘x’ and another angle as ‘y’.
Since we know both the angles are supplementary angles, then their sum must be equal to \[{180^ \circ }\]
So we can write the sum of angles x and y as \[{180^ \circ }\]
\[ \Rightarrow x + y = {180^ \circ }\] … (1)
Now we are given that the angles are in the ratio \[5:4\]
So we can write that the ratio of angles x and y is \[5:4\].
Substitute the values of angles we assumed in the beginning of the solution.
\[ \Rightarrow x:y = 5:4\] … (2)
Now since we know we can convert the ratio \[a:b\] into a form of fraction as \[\dfrac{a}{b}\].
Therefore, we can write the equation (2) as
\[ \Rightarrow \dfrac{x}{y} = \dfrac{5}{4}\]
Multiply both sides of the equation by y
\[ \Rightarrow \dfrac{x}{y} \times y = \dfrac{5}{4} \times y\]
Cancel the same terms from numerator and denominator.
\[ \Rightarrow x = \dfrac{5}{4}y\] … (3)
Substitute the value of x from equation (3) in equation (1).
\[ \Rightarrow \dfrac{{5y}}{4} + y = {180^ \circ }\]
Take LCM on the left hand side of the equation.
\[ \Rightarrow \dfrac{{5y + 4y}}{4} = {180^ \circ }\]
Calculate the sum in the numerator.
\[ \Rightarrow \dfrac{{9y}}{4} = {180^ \circ }\]
Multiply both sides by \[\dfrac{4}{9}\]
\[ \Rightarrow \dfrac{{9y}}{4} \times \dfrac{4}{9} = {180^ \circ } \times \dfrac{4}{9}\]
Cancel out the same terms from numerator and denominator.
\[ \Rightarrow y = {\left( {20 \times 4} \right)^ \circ }\]
Calculate the product.
\[ \Rightarrow y = {80^ \circ }\]
Now we substitute the value of y in equation (1) to calculate the value of x.
\[ \Rightarrow x + {80^ \circ } = {180^ \circ }\]
Shift all constants to one side of the equation.
\[ \Rightarrow x = {180^ \circ } - {80^ \circ }\]
Calculate the value on RHS.
\[ \Rightarrow x = {100^ \circ }\]
\[\therefore \]Two supplementary angles that are in the ratio \[5:4\] are \[{100^ \circ }\] and \[{80^ \circ }\]
Note:
Students many times make the equation formed by the ratio as a complex equation when they cross multiply the values to both sides and then solve. Always try to keep that value on one side of the equation which can later be directly substituted in another equation. Also, keep in mind ratio should always be in simplest form i.e. there should not be any common factor between numerator and denominator.
Recently Updated Pages
Three beakers labelled as A B and C each containing 25 mL of water were taken A small amount of NaOH anhydrous CuSO4 and NaCl were added to the beakers A B and C respectively It was observed that there was an increase in the temperature of the solutions contained in beakers A and B whereas in case of beaker C the temperature of the solution falls Which one of the following statements isarecorrect i In beakers A and B exothermic process has occurred ii In beakers A and B endothermic process has occurred iii In beaker C exothermic process has occurred iv In beaker C endothermic process has occurred

Master Class 10 Social Science: Engaging Questions & Answers for Success

Master Class 10 Science: Engaging Questions & Answers for Success

Master Class 10 Maths: Engaging Questions & Answers for Success

Master Class 10 General Knowledge: Engaging Questions & Answers for Success

Master Class 10 Computer Science: Engaging Questions & Answers for Success

Trending doubts
Explain the Treaty of Vienna of 1815 class 10 social science CBSE

In cricket, what is the term for a bowler taking five wickets in an innings?

Who Won 36 Oscar Awards? Record Holder Revealed

What is the median of the first 10 natural numbers class 10 maths CBSE

Why is it 530 pm in india when it is 1200 afternoon class 10 social science CBSE

What is deficiency disease class 10 biology CBSE

