
Two bodies of mass 4 kg and 6 kg are attached to the end of a string passing over a pulley. The 4 kg mass is starched to the table top by another string. What is the free body?
Answer
615.3k+ views
Hint: First, start by drawing the diagram of the arrangement and denoting all the possible forces that are acting on the body like the tensions on the string of pulley that are $T_1$ and $T_2$ and the force due to the gravitation that is mg. Then draw the free body diagram for each mass and denote all the forces on the body. After that add all the forces and equate to zero to find the unknown forces.
Complete Step-by-Step solution:
First we will be drawing the diagram for the given arrangement as shown in figure 1
We know that the tension on both ends of the string over the pulley will be equal so tension $T_1$ is developed across both the ends of the pulley. And a tension is also developed in the string connecting the 4 kg mass to the ground. Now looking at the free body diagram as shown in figure 2.
First considering the free body diagram 4kg mass we can see all the forces and their direction in which they are acting on. That is tension $T_1$ is acting upward, Tension $T_2$ is acting downward and the force due to gravity is acting on the downward.
\[T_1 = {m_4}g + T_2\]
\[ \Rightarrow T_1 = 4 \times 9.8 + T_2\]
\[ \Rightarrow T_1 = 39.2N + T_2\]--------------- (1)
Here we take acceleration due to gravity as g= 9.8 $m/s^2$
Similarly considering the free body diagram of the 6 kg mass we can see that there are only two forces that are acting in the opposite direction that is tension $T_1$ is acting upward and the force due to the gravity is acting downward.
\[ \Rightarrow T_1 = {m_6}g\]
\[ \Rightarrow T_1 = 6 \times 9.8\]
\[ \Rightarrow T_1 = 58.8N\]----------------- (2)
We can equate equation (1) and (2) to get the value of $T_2$ that is
\[ \Rightarrow 58.8 = 39.2 + T_2\]
\[ \Rightarrow T_2 = 58.8 - 39.2 = 19.6N\]---------- (3)
Now substituting (3) in equation (1) we get
\[ \Rightarrow T_1 = 39.2 + 19.6\]
\[ \Rightarrow T_1 = 58.8N\]
Hence, using these we can easily draw the free body diagram.
Note: To solve these types of questions we need to have a clear understanding of how to draw the free body diagram and representing all the forces that are acting. We need to be careful with the direction in which the forces are acting and the equation to find the values of unknown forces.
Complete Step-by-Step solution:
First we will be drawing the diagram for the given arrangement as shown in figure 1
Figure 1
We know that the tension on both ends of the string over the pulley will be equal so tension $T_1$ is developed across both the ends of the pulley. And a tension is also developed in the string connecting the 4 kg mass to the ground. Now looking at the free body diagram as shown in figure 2.
Figure 2
First considering the free body diagram 4kg mass we can see all the forces and their direction in which they are acting on. That is tension $T_1$ is acting upward, Tension $T_2$ is acting downward and the force due to gravity is acting on the downward.
\[T_1 = {m_4}g + T_2\]
\[ \Rightarrow T_1 = 4 \times 9.8 + T_2\]
\[ \Rightarrow T_1 = 39.2N + T_2\]--------------- (1)
Here we take acceleration due to gravity as g= 9.8 $m/s^2$
Similarly considering the free body diagram of the 6 kg mass we can see that there are only two forces that are acting in the opposite direction that is tension $T_1$ is acting upward and the force due to the gravity is acting downward.
\[ \Rightarrow T_1 = {m_6}g\]
\[ \Rightarrow T_1 = 6 \times 9.8\]
\[ \Rightarrow T_1 = 58.8N\]----------------- (2)
We can equate equation (1) and (2) to get the value of $T_2$ that is
\[ \Rightarrow 58.8 = 39.2 + T_2\]
\[ \Rightarrow T_2 = 58.8 - 39.2 = 19.6N\]---------- (3)
Now substituting (3) in equation (1) we get
\[ \Rightarrow T_1 = 39.2 + 19.6\]
\[ \Rightarrow T_1 = 58.8N\]
Hence, using these we can easily draw the free body diagram.
Note: To solve these types of questions we need to have a clear understanding of how to draw the free body diagram and representing all the forces that are acting. We need to be careful with the direction in which the forces are acting and the equation to find the values of unknown forces.
Recently Updated Pages
Basicity of sulphurous acid and sulphuric acid are

Master Class 10 English: Engaging Questions & Answers for Success

Master Class 10 Social Science: Engaging Questions & Answers for Success

Master Class 10 Computer Science: Engaging Questions & Answers for Success

Class 10 Question and Answer - Your Ultimate Solutions Guide

Master Class 10 General Knowledge: Engaging Questions & Answers for Success

Trending doubts
Who is known as the "Little Master" in Indian cricket history?

A boat goes 24 km upstream and 28 km downstream in class 10 maths CBSE

Who Won 36 Oscar Awards? Record Holder Revealed

Why is there a time difference of about 5 hours between class 10 social science CBSE

Explain the Treaty of Vienna of 1815 class 10 social science CBSE

What is the median of the first 10 natural numbers class 10 maths CBSE

