The volume of a cuboid is $1200{\text{c}}{{\text{m}}^{\text{3}}}$. The length is 15cm and breadth is 10cm. Find its height.
Last updated date: 27th Mar 2023
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Answer
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Hint: Here we will proceed to the solution by using the formula of the volume of the cube, which includes length, breadth and height from which we can get the height of the cuboid.
Given that the volume of cuboid is $1200{\text{c}}{{\text{m}}^{\text{3}}}$.
And also given length (l) =15cm and breadth (b) =10cm.
Now let us consider height of cuboid as h cm
We know that
Volume of cuboid =$l \times b \times h$
Where l is length, b is the breadth and h is the height of cuboid.
Now on using the formula, we can write
$
\Rightarrow 1200 = 15 \times 10 \times h \\
\Rightarrow h = \dfrac{{1200}}{{15 \times 10}} \\
\Rightarrow h = 8 \\
$
Therefore height of a cuboid =8cm
NOTE: In this problem volume of a cuboid is given along with length and breadth where we have to find height. As we know that the volume of cuboid is lbh. So now on substituting the values in the formula we get the height of the cuboid. Here we have to make a note that measures units of length, breadth and height is cm. Don’t miss mentioning the units after finding the value.
Given that the volume of cuboid is $1200{\text{c}}{{\text{m}}^{\text{3}}}$.
And also given length (l) =15cm and breadth (b) =10cm.
Now let us consider height of cuboid as h cm
We know that
Volume of cuboid =$l \times b \times h$
Where l is length, b is the breadth and h is the height of cuboid.
Now on using the formula, we can write
$
\Rightarrow 1200 = 15 \times 10 \times h \\
\Rightarrow h = \dfrac{{1200}}{{15 \times 10}} \\
\Rightarrow h = 8 \\
$
Therefore height of a cuboid =8cm
NOTE: In this problem volume of a cuboid is given along with length and breadth where we have to find height. As we know that the volume of cuboid is lbh. So now on substituting the values in the formula we get the height of the cuboid. Here we have to make a note that measures units of length, breadth and height is cm. Don’t miss mentioning the units after finding the value.
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