# The two digit number \[{\text{x}}\] is the digit at unit place and \[{\text{y}}\] is the digit at unit place, then the number is :

\[

{\text{A}}.10y + x \\

{\text{B}}.10x + y \\

{\text{C}}.10y - x \\

{\text{D}}.10 - y \

\]

Last updated date: 23rd Mar 2023

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Answer

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Hint – Use the concept of ones and tens and make an equation, take an example of any two digit number.

It is a two digit number \[{\text{x}}\] is the digit at unit place and \[{\text{y}}\] is the digit at tens place .

Let us take an example of a two digit number \[51\] so here \[\,1\] is at the unit place and \[{\text{5}}\] is digit at the tense place . So here,

$x = 1\,\,\& \,\,y = 5$ ……(i)

We can write \[51\] as

\[51 = 50 + 1 = 10(5) + 1\]

We can write the above equation as \[10y + x\] ……(From (i))

Hence the correct option is A.

Note – In these types of questions we must have to know that, just left of decimal point is one place and left of one's place is a tens place. We should know that when we write the numbers of all these places in addition/subtraction then these numbers get multiplied by the number of their respective names, then aon adding/subtracting we will get the number .

It is a two digit number \[{\text{x}}\] is the digit at unit place and \[{\text{y}}\] is the digit at tens place .

Let us take an example of a two digit number \[51\] so here \[\,1\] is at the unit place and \[{\text{5}}\] is digit at the tense place . So here,

$x = 1\,\,\& \,\,y = 5$ ……(i)

We can write \[51\] as

\[51 = 50 + 1 = 10(5) + 1\]

We can write the above equation as \[10y + x\] ……(From (i))

Hence the correct option is A.

Note – In these types of questions we must have to know that, just left of decimal point is one place and left of one's place is a tens place. We should know that when we write the numbers of all these places in addition/subtraction then these numbers get multiplied by the number of their respective names, then aon adding/subtracting we will get the number .

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