The top of a table measures 2m 25cm by 1m 20cm. Find its area in square meters?
Last updated date: 28th Mar 2023
•
Total views: 307.8k
•
Views today: 2.84k
Answer
307.8k+ views
Hint: In this question the dimension of the table which is in a rectangular shape is given and we have to find the area of this table, simple use of the basic formula for area of rectangle will help you reach the right answer.
Complete step-by-step answer:
The top of the table is shown above and the measure of the table is given as 2 m 25 cm by 1m 20 cm.
Then we have to find out the area of the table.
So, let us consider that length of the table is $L = {\text{2 m 25 cm}}$
Now as we know that $1{\text{ cm = }}\dfrac{1}{{100}}{\text{ m}}$.
So length (L) = $\left( {2 + \dfrac{{25}}{{100}}} \right) = 2.25$ m.
Now let us consider that breadth of the table is $B = 1{\text{ m 20 cm}}$.
Now as we know that$1{\text{ cm = }}\dfrac{1}{{100}}{\text{ m}}$.
So breadth (B) = $\left( {1 + \dfrac{{20}}{{100}}} \right) = 1.20$ m.
So, as we see that the length and breadth of the top of the table are not equal therefore it is a rectangle table, so the area (A) of the rectangle is length multiplied by breadth.
$\therefore A = L \times B$
$ \Rightarrow A = \left( {2.25{\text{ m}}} \right) \times \left( {1.20{\text{ m}}} \right) = 2.7{\text{ }}{{\text{m}}^2}$
So, this is the required area of the top of the table.
Note: Whenever we face such a type of problem the basic concept is to use the direct formula for the area of the rectangle however the key point to note is the dimensions in this questions were not given into a single unit, so always synchronize the units for all the dimensions before putting values in the dedicated formula. This will help you to get the right answer always.
Complete step-by-step answer:

The top of the table is shown above and the measure of the table is given as 2 m 25 cm by 1m 20 cm.
Then we have to find out the area of the table.
So, let us consider that length of the table is $L = {\text{2 m 25 cm}}$
Now as we know that $1{\text{ cm = }}\dfrac{1}{{100}}{\text{ m}}$.
So length (L) = $\left( {2 + \dfrac{{25}}{{100}}} \right) = 2.25$ m.
Now let us consider that breadth of the table is $B = 1{\text{ m 20 cm}}$.
Now as we know that$1{\text{ cm = }}\dfrac{1}{{100}}{\text{ m}}$.
So breadth (B) = $\left( {1 + \dfrac{{20}}{{100}}} \right) = 1.20$ m.
So, as we see that the length and breadth of the top of the table are not equal therefore it is a rectangle table, so the area (A) of the rectangle is length multiplied by breadth.
$\therefore A = L \times B$
$ \Rightarrow A = \left( {2.25{\text{ m}}} \right) \times \left( {1.20{\text{ m}}} \right) = 2.7{\text{ }}{{\text{m}}^2}$
So, this is the required area of the top of the table.
Note: Whenever we face such a type of problem the basic concept is to use the direct formula for the area of the rectangle however the key point to note is the dimensions in this questions were not given into a single unit, so always synchronize the units for all the dimensions before putting values in the dedicated formula. This will help you to get the right answer always.
Recently Updated Pages
If a spring has a period T and is cut into the n equal class 11 physics CBSE

A planet moves around the sun in nearly circular orbit class 11 physics CBSE

In any triangle AB2 BC4 CA3 and D is the midpoint of class 11 maths JEE_Main

In a Delta ABC 2asin dfracAB+C2 is equal to IIT Screening class 11 maths JEE_Main

If in aDelta ABCangle A 45circ angle C 60circ then class 11 maths JEE_Main

If in a triangle rmABC side a sqrt 3 + 1rmcm and angle class 11 maths JEE_Main

Trending doubts
Difference Between Plant Cell and Animal Cell

Write an application to the principal requesting five class 10 english CBSE

Ray optics is valid when characteristic dimensions class 12 physics CBSE

Give 10 examples for herbs , shrubs , climbers , creepers

Write the 6 fundamental rights of India and explain in detail

Write a letter to the principal requesting him to grant class 10 english CBSE

List out three methods of soil conservation

Fill in the blanks A 1 lakh ten thousand B 1 million class 9 maths CBSE

Epipetalous and syngenesious stamens occur in aSolanaceae class 11 biology CBSE
