Answer
396.9k+ views
Hint:. The three main temperature scales are Celsius, Fahrenheit, and Kelvin. Temperatures can be converted from one scale to another using temperature conversion equations.
Formula used: $\dfrac{{^0F - 32}}{{180}} = \dfrac{{^0C - 0}}{{100}}$
Complete step-by-step solution:According to temperature scale: $\dfrac{{^0F - 32}}{{180}} = \dfrac{{^0C - 0}}{{100}}$
In the question temperature in Fahrenheit is given $F = 60$.So,
$\dfrac{{60 - 32}}{{180}} = \dfrac{{^0C}}{{100}}$
$\Rightarrow {^0C} = \dfrac{{28}}{{180}} \times 100$
$\Rightarrow {^0C} =\dfrac{{28 \times 5}}{9}$
$\therefore {^0C} = \dfrac{{140}}{9} = 15.55$
Hence ${15.55^0}C$ is the equivalent temperature of ${60^0}F$.
Additional information:The Kelvin scale is the absolute temperature scale that is commonly used in science. The SI temperature unit is the kelvin, which is abbreviated K (not accompanied by a degree sign). Thus 0 K is absolute zero. The freezing and boiling points of water are 273.15 K and 373.15 K, respectively. Therefore, temperature differences are the same in units of kelvins and degrees Celsius.
Note:On the Celsius scale, the freezing point of water is 0 degree Celsius and the boiling point is 100 degree Celsius. The unit of temperature on this scale is the degree Celsius ($^0C$). The Fahrenheit scale (still the most frequently used for common purposes in the United States) has the freezing point of water at 32 F and the boiling point at 212 F . Its unit is the degree Fahrenheit (F). You can see that 100 Celsius degrees span the same range as 180 Fahrenheit degrees. Thus, a temperature difference of one degree on the Celsius scale is 1.8 times as large as a difference of one degree on the Fahrenheit scale.
Formula used: $\dfrac{{^0F - 32}}{{180}} = \dfrac{{^0C - 0}}{{100}}$
Complete step-by-step solution:According to temperature scale: $\dfrac{{^0F - 32}}{{180}} = \dfrac{{^0C - 0}}{{100}}$
In the question temperature in Fahrenheit is given $F = 60$.So,
$\dfrac{{60 - 32}}{{180}} = \dfrac{{^0C}}{{100}}$
$\Rightarrow {^0C} = \dfrac{{28}}{{180}} \times 100$
$\Rightarrow {^0C} =\dfrac{{28 \times 5}}{9}$
$\therefore {^0C} = \dfrac{{140}}{9} = 15.55$
Hence ${15.55^0}C$ is the equivalent temperature of ${60^0}F$.
Additional information:The Kelvin scale is the absolute temperature scale that is commonly used in science. The SI temperature unit is the kelvin, which is abbreviated K (not accompanied by a degree sign). Thus 0 K is absolute zero. The freezing and boiling points of water are 273.15 K and 373.15 K, respectively. Therefore, temperature differences are the same in units of kelvins and degrees Celsius.
Note:On the Celsius scale, the freezing point of water is 0 degree Celsius and the boiling point is 100 degree Celsius. The unit of temperature on this scale is the degree Celsius ($^0C$). The Fahrenheit scale (still the most frequently used for common purposes in the United States) has the freezing point of water at 32 F and the boiling point at 212 F . Its unit is the degree Fahrenheit (F). You can see that 100 Celsius degrees span the same range as 180 Fahrenheit degrees. Thus, a temperature difference of one degree on the Celsius scale is 1.8 times as large as a difference of one degree on the Fahrenheit scale.
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