Question

# The solution of which of the following equations is neither a fraction nor an integer? $\begin{array}{*{20}{l}} {A.{\text{ }}2x + 6 = 0} \\ {B.{\text{ }}3x - 5 = 0} \\ {C.{\text{ }}5x - 8 = x + 4} \\ {D.{\text{ }}4x + 7 = x + 2} \end{array}$

Verified
129.3k+ views
Hint: Firstly solve all the four equations given in the options one-by-one, to find the value of x. Then check whether x is a fraction or an integer.

In option B: 3x-5=0 hence x = $\dfrac{5}{3}$ which is a fraction
In option D: 4x+7=x+2 hence x =($- \dfrac{5}{3}$ ​) which is neither a proper fraction, nor an integer.
Note that, in a proper fraction, the value of the numerator is always less than the value of the denominator. For example, $\dfrac{1}{3}$is a proper fraction, but $\dfrac{7}{3}$ is not.