
The sides of a triangle are in the ratio of $13:14:15$ and its perimeter is $84$ centimeter. Then the area of the triangle is: -
A. $136$ square cm
B. $236$square cm
C. $336$square cm
D. $436$square cm
Answer
559.5k+ views
Hint: We will use Heron's formula to solve this question.
The Heron’s formula for the area of triangle is
$A=\sqrt{s\left( s-a \right)\left( s-b \right)\left( s-c \right)}$
Here, ‘$a$’, ‘$b$’ and ‘$c$’ are the lengths of the three sides of the triangle.
Also, in Heron’s formula ‘$s$’ stands for semi-circumference and it is given by
\[s=\dfrac{P}{2}=\dfrac{a+b+c}{2}\]
where $P$ is the perimeter of the triangle.
Complete step-by-step answer:
According to the question, the sides of the triangle are in the ratio of $13:14:15$.
Let the lengths of the three sides of the triangle be $13x$, $14x$ and $15x$.
\[\begin{align}
& \text{Perimeter of the triangle }=\text{ }84\text{ centimeter} \\
& \text{side }+\text{ side }+\text{ side }=\text{ }84\text{ centimeter} \\
& \text{13}x+14x+15x=84\text{ centimeter} \\
& 42x=84\text{ centimeter} \\
& x=\dfrac{84}{42} \\
& =2
\end{align}\]
Let us now find the lengths of the sides of the triangle: -
\[\begin{align}
& \Rightarrow a=13x\ \ =\ \ 13\ \ \times \ \ 2\ \ =\ \ 26 \\
& \Rightarrow b=14x\ \ =\ \ 14\ \ \times \ \ 2\ \ =\ \ 28 \\
& \Rightarrow c=15x\ \ =\ \ 15\ \ \times \ \ 2\ \ =\ \ 30 \\
\end{align}\]
\[\]
Hence, the lengths of the sides of the triangle are $26$, $28$ and $30$. So, the values of $a$, $b$ and $c$ are $26$, $28$ and $30$ respectively.
Now, we will find the value of ‘$s$’ where $s$ is the semi-circumference then,
\[\begin{align}
& s=\dfrac{\text{Premieter of the triangle}}{2} \\
& =\dfrac{84}{2} \\
& =42
\end{align}\]
Now substitute the value of $s$ in the heron’s equation to find the area of the triangle.\[\begin{align}
& A=\sqrt{s\left( s-a \right)\left( s-b \right)\left( s-c \right)} \\
& =\sqrt{42\left( 42-26 \right)\left( 42-28 \right)\left( 42-30 \right)} \\
& =\sqrt{42\left( 16 \right)\left( 14 \right)\left( 12 \right)} \\
& =\sqrt{112896} \\
& =336\text{ square centimeters}
\end{align}\]
So, the correct answer is “Option C”.
Note: You can find the value of $s$ from the formula
$\begin{align}
& s=\dfrac{a+b+c}{2} \\
& =\dfrac{26+28+30}{2} \\
& =42
\end{align}$
From the above formula also, we get the same value for the $s$. Please remember the formula for finding the area of the triangle that is Heron's formula which is given by
$A=\sqrt{s\left( s-a \right)\left( s-b \right)\left( s-c \right)}$
The Heron’s formula for the area of triangle is
$A=\sqrt{s\left( s-a \right)\left( s-b \right)\left( s-c \right)}$
Here, ‘$a$’, ‘$b$’ and ‘$c$’ are the lengths of the three sides of the triangle.
Also, in Heron’s formula ‘$s$’ stands for semi-circumference and it is given by
\[s=\dfrac{P}{2}=\dfrac{a+b+c}{2}\]
where $P$ is the perimeter of the triangle.
Complete step-by-step answer:
According to the question, the sides of the triangle are in the ratio of $13:14:15$.
Let the lengths of the three sides of the triangle be $13x$, $14x$ and $15x$.
\[\begin{align}
& \text{Perimeter of the triangle }=\text{ }84\text{ centimeter} \\
& \text{side }+\text{ side }+\text{ side }=\text{ }84\text{ centimeter} \\
& \text{13}x+14x+15x=84\text{ centimeter} \\
& 42x=84\text{ centimeter} \\
& x=\dfrac{84}{42} \\
& =2
\end{align}\]
Let us now find the lengths of the sides of the triangle: -
\[\begin{align}
& \Rightarrow a=13x\ \ =\ \ 13\ \ \times \ \ 2\ \ =\ \ 26 \\
& \Rightarrow b=14x\ \ =\ \ 14\ \ \times \ \ 2\ \ =\ \ 28 \\
& \Rightarrow c=15x\ \ =\ \ 15\ \ \times \ \ 2\ \ =\ \ 30 \\
\end{align}\]
Hence, the lengths of the sides of the triangle are $26$, $28$ and $30$. So, the values of $a$, $b$ and $c$ are $26$, $28$ and $30$ respectively.
Now, we will find the value of ‘$s$’ where $s$ is the semi-circumference then,
\[\begin{align}
& s=\dfrac{\text{Premieter of the triangle}}{2} \\
& =\dfrac{84}{2} \\
& =42
\end{align}\]
Now substitute the value of $s$ in the heron’s equation to find the area of the triangle.\[\begin{align}
& A=\sqrt{s\left( s-a \right)\left( s-b \right)\left( s-c \right)} \\
& =\sqrt{42\left( 42-26 \right)\left( 42-28 \right)\left( 42-30 \right)} \\
& =\sqrt{42\left( 16 \right)\left( 14 \right)\left( 12 \right)} \\
& =\sqrt{112896} \\
& =336\text{ square centimeters}
\end{align}\]
So, the correct answer is “Option C”.
Note: You can find the value of $s$ from the formula
$\begin{align}
& s=\dfrac{a+b+c}{2} \\
& =\dfrac{26+28+30}{2} \\
& =42
\end{align}$
From the above formula also, we get the same value for the $s$. Please remember the formula for finding the area of the triangle that is Heron's formula which is given by
$A=\sqrt{s\left( s-a \right)\left( s-b \right)\left( s-c \right)}$
Recently Updated Pages
Two men on either side of the cliff 90m height observe class 10 maths CBSE

What happens to glucose which enters nephron along class 10 biology CBSE

Cutting of the Chinese melon means A The business and class 10 social science CBSE

Write a dialogue with at least ten utterances between class 10 english CBSE

Show an aquatic food chain using the following organisms class 10 biology CBSE

A circle is inscribed in an equilateral triangle and class 10 maths CBSE

Trending doubts
Why is there a time difference of about 5 hours between class 10 social science CBSE

Write a letter to the principal requesting him to grant class 10 english CBSE

What is the median of the first 10 natural numbers class 10 maths CBSE

The Equation xxx + 2 is Satisfied when x is Equal to Class 10 Maths

Which of the following does not have a fundamental class 10 physics CBSE

State and prove converse of BPT Basic Proportionality class 10 maths CBSE

