
The sides of a triangle are in the ratio of $13:14:15$ and its perimeter is $84$ centimeter. Then the area of the triangle is: -
A. $136$ square cm
B. $236$square cm
C. $336$square cm
D. $436$square cm
Answer
573.3k+ views
Hint: We will use Heron's formula to solve this question.
The Heron’s formula for the area of triangle is
$A=\sqrt{s\left( s-a \right)\left( s-b \right)\left( s-c \right)}$
Here, ‘$a$’, ‘$b$’ and ‘$c$’ are the lengths of the three sides of the triangle.
Also, in Heron’s formula ‘$s$’ stands for semi-circumference and it is given by
\[s=\dfrac{P}{2}=\dfrac{a+b+c}{2}\]
where $P$ is the perimeter of the triangle.
Complete step-by-step answer:
According to the question, the sides of the triangle are in the ratio of $13:14:15$.
Let the lengths of the three sides of the triangle be $13x$, $14x$ and $15x$.
\[\begin{align}
& \text{Perimeter of the triangle }=\text{ }84\text{ centimeter} \\
& \text{side }+\text{ side }+\text{ side }=\text{ }84\text{ centimeter} \\
& \text{13}x+14x+15x=84\text{ centimeter} \\
& 42x=84\text{ centimeter} \\
& x=\dfrac{84}{42} \\
& =2
\end{align}\]
Let us now find the lengths of the sides of the triangle: -
\[\begin{align}
& \Rightarrow a=13x\ \ =\ \ 13\ \ \times \ \ 2\ \ =\ \ 26 \\
& \Rightarrow b=14x\ \ =\ \ 14\ \ \times \ \ 2\ \ =\ \ 28 \\
& \Rightarrow c=15x\ \ =\ \ 15\ \ \times \ \ 2\ \ =\ \ 30 \\
\end{align}\]
\[\]
Hence, the lengths of the sides of the triangle are $26$, $28$ and $30$. So, the values of $a$, $b$ and $c$ are $26$, $28$ and $30$ respectively.
Now, we will find the value of ‘$s$’ where $s$ is the semi-circumference then,
\[\begin{align}
& s=\dfrac{\text{Premieter of the triangle}}{2} \\
& =\dfrac{84}{2} \\
& =42
\end{align}\]
Now substitute the value of $s$ in the heron’s equation to find the area of the triangle.\[\begin{align}
& A=\sqrt{s\left( s-a \right)\left( s-b \right)\left( s-c \right)} \\
& =\sqrt{42\left( 42-26 \right)\left( 42-28 \right)\left( 42-30 \right)} \\
& =\sqrt{42\left( 16 \right)\left( 14 \right)\left( 12 \right)} \\
& =\sqrt{112896} \\
& =336\text{ square centimeters}
\end{align}\]
So, the correct answer is “Option C”.
Note: You can find the value of $s$ from the formula
$\begin{align}
& s=\dfrac{a+b+c}{2} \\
& =\dfrac{26+28+30}{2} \\
& =42
\end{align}$
From the above formula also, we get the same value for the $s$. Please remember the formula for finding the area of the triangle that is Heron's formula which is given by
$A=\sqrt{s\left( s-a \right)\left( s-b \right)\left( s-c \right)}$
The Heron’s formula for the area of triangle is
$A=\sqrt{s\left( s-a \right)\left( s-b \right)\left( s-c \right)}$
Here, ‘$a$’, ‘$b$’ and ‘$c$’ are the lengths of the three sides of the triangle.
Also, in Heron’s formula ‘$s$’ stands for semi-circumference and it is given by
\[s=\dfrac{P}{2}=\dfrac{a+b+c}{2}\]
where $P$ is the perimeter of the triangle.
Complete step-by-step answer:
According to the question, the sides of the triangle are in the ratio of $13:14:15$.
Let the lengths of the three sides of the triangle be $13x$, $14x$ and $15x$.
\[\begin{align}
& \text{Perimeter of the triangle }=\text{ }84\text{ centimeter} \\
& \text{side }+\text{ side }+\text{ side }=\text{ }84\text{ centimeter} \\
& \text{13}x+14x+15x=84\text{ centimeter} \\
& 42x=84\text{ centimeter} \\
& x=\dfrac{84}{42} \\
& =2
\end{align}\]
Let us now find the lengths of the sides of the triangle: -
\[\begin{align}
& \Rightarrow a=13x\ \ =\ \ 13\ \ \times \ \ 2\ \ =\ \ 26 \\
& \Rightarrow b=14x\ \ =\ \ 14\ \ \times \ \ 2\ \ =\ \ 28 \\
& \Rightarrow c=15x\ \ =\ \ 15\ \ \times \ \ 2\ \ =\ \ 30 \\
\end{align}\]
Hence, the lengths of the sides of the triangle are $26$, $28$ and $30$. So, the values of $a$, $b$ and $c$ are $26$, $28$ and $30$ respectively.
Now, we will find the value of ‘$s$’ where $s$ is the semi-circumference then,
\[\begin{align}
& s=\dfrac{\text{Premieter of the triangle}}{2} \\
& =\dfrac{84}{2} \\
& =42
\end{align}\]
Now substitute the value of $s$ in the heron’s equation to find the area of the triangle.\[\begin{align}
& A=\sqrt{s\left( s-a \right)\left( s-b \right)\left( s-c \right)} \\
& =\sqrt{42\left( 42-26 \right)\left( 42-28 \right)\left( 42-30 \right)} \\
& =\sqrt{42\left( 16 \right)\left( 14 \right)\left( 12 \right)} \\
& =\sqrt{112896} \\
& =336\text{ square centimeters}
\end{align}\]
So, the correct answer is “Option C”.
Note: You can find the value of $s$ from the formula
$\begin{align}
& s=\dfrac{a+b+c}{2} \\
& =\dfrac{26+28+30}{2} \\
& =42
\end{align}$
From the above formula also, we get the same value for the $s$. Please remember the formula for finding the area of the triangle that is Heron's formula which is given by
$A=\sqrt{s\left( s-a \right)\left( s-b \right)\left( s-c \right)}$
Recently Updated Pages
Master Class 10 Computer Science: Engaging Questions & Answers for Success

Master Class 10 General Knowledge: Engaging Questions & Answers for Success

Master Class 10 English: Engaging Questions & Answers for Success

Master Class 10 Social Science: Engaging Questions & Answers for Success

Master Class 10 Maths: Engaging Questions & Answers for Success

Master Class 10 Science: Engaging Questions & Answers for Success

Trending doubts
What is the median of the first 10 natural numbers class 10 maths CBSE

The draft of the Preamble of the Indian Constitution class 10 social science CBSE

Which women's tennis player has 24 Grand Slam singles titles?

Who gave "Inqilab Zindabad" slogan?

Why is there a time difference of about 5 hours between class 10 social science CBSE

Who is the Brand Ambassador of Incredible India?

