Question

The reduction potential values of M, N, and O are ${ +2.46 V, 1.13V, -3.13V }$ respectively. Which of the following orders is correct regarding the reducing property?A. ONMB. OMNC. MNOD. MON

Hint: According to the reactivity series, going from bottom to top, the metals: lose electrons more readily to form positive ions; so they become stronger reducing agents.

A reduction reaction is a sort of compound reaction that includes an exchange of electrons between two species. A reduction reaction is any concoction reaction where the oxidation number of a particle, molecule, or particle changes by picking up or losing an electron.
It is given that the reduction potential values of M, N, and O are ${ +2.46 V, 1.13V, -3.13V }$ respectively.
Here, the negative sign demonstrates that when this half cell is associated with the standard hydrogen electrode (SHE), at that point it will give electrons to the hydrogen anode or will go through oxidation. A positive indication of reduction potential truly signifies a non-spontaneous reduction response and a negative sign shows a spontaneous reduction reaction.

Hence, the correct option is A.

The standard reduction potential is the anode potential estimated under standard conditions: ${ 25 }^{ \circ }{ C }$ and a ${ 1 M }$ fixation for every particle partaking in the reaction, the halfway weight of 1atm for each gas that is a piece of the response, and metals in their pure state. The standard reduction likely is characterized comparative with a standard hydrogen terminal (reference cathode) which is discretionarily given a capability of ${ 0.00volts }$.
Note: The possibility to make a mistake is that as we move down the group ionization enthalpy increases down the group and more the negative estimation of ${ E }^{ \circ }$, more will be it’s reducing property.