Answer
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Hint: In this type of question we have to use the concept of multiplication of a decimal number by another decimal number. We know that to multiply a decimal number by another decimal number, we first multiply the two numbers by ignoring the decimal points and then place the decimal point in the product in such a way that decimal places in the product is equal to the sum of the decimal places in the given numbers.
Complete step by step answer:
Now, we have to find the product of 0.03 and 0.9.
To find this product let us proceed as follows:
First we will perform the multiplication of 0.03 and 0.9 by ignoring the decimal points. So that we get,
\[\Rightarrow 3\times 9=27\]
Now, we will place the decimal point in the product to give as many decimal places in the product as there are in the multiplicand and in the multiplier together. Here, it is equal to three. Hence,
\[\Rightarrow 0.03\times 0.9=0.027\]
Hence, the product of 0.03 and 0.9 is 0.027.
So, the correct answer is “Option c”.
Note: In this type of questions students have to remember the steps involved in multiplication of a decimal number by another decimal number. Students have to take care that when they replace the decimal point in the product the counting must always be done from the unit place of the product.
Complete step by step answer:
Now, we have to find the product of 0.03 and 0.9.
To find this product let us proceed as follows:
First we will perform the multiplication of 0.03 and 0.9 by ignoring the decimal points. So that we get,
\[\Rightarrow 3\times 9=27\]
Now, we will place the decimal point in the product to give as many decimal places in the product as there are in the multiplicand and in the multiplier together. Here, it is equal to three. Hence,
\[\Rightarrow 0.03\times 0.9=0.027\]
Hence, the product of 0.03 and 0.9 is 0.027.
So, the correct answer is “Option c”.
Note: In this type of questions students have to remember the steps involved in multiplication of a decimal number by another decimal number. Students have to take care that when they replace the decimal point in the product the counting must always be done from the unit place of the product.
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