Answer
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Hint:As we know that Circumference of circle is $2\pi r$ . Perimeter implies that the circumference of a circle and quadrant of a circle means one-fourth part of the circle. Using this concept we will get the required solution .
Complete step-by-step answer:
As We learn that Perimeter of the circle is $2\pi r$.
But in this question we have to find the perimeter of a quadrant of circle means that one-fourth of the perimeter of circle
Here we see that the blue colored part is the quadrant of the circle .
Perimeter of quadrant of circle is $\dfrac{{2\pi r}}{4}$
where we take $\pi = \dfrac{{22}}{7}$ and Radius of circle is given $r = \dfrac{7}{2}$ ;
By putting these value ,
= $\dfrac{{2 \times \dfrac{{22}}{7} \times \dfrac{7}{2}}}{4}$
When we solve we get
= $\dfrac{{22}}{4}$$cm$
In decimal form
= $5.5cm$
So, the correct answer is “Option B”.
Note:Students should also remembered that Area of Circle is = $\pi {r^2}$ And the area of quadrant is $\dfrac{{\pi {r^2}}}{4}$.Perimeter of semi-circle is $\pi r$ and Area of semi-circle is $\dfrac{{\pi {r^2}}}{2}$.
Perimeter of Square is $4 \times a$ and Area of Square is ${a^2}$ where a is the side of the square.
Perimeter of rectangle is $2\left( {l + b} \right)$ and Area of rectangle is $l \times b$ where $l = $ Length of Rectangle and $b = $ breadth of Rectangle.
Complete step-by-step answer:
As We learn that Perimeter of the circle is $2\pi r$.
But in this question we have to find the perimeter of a quadrant of circle means that one-fourth of the perimeter of circle
Here we see that the blue colored part is the quadrant of the circle .
Perimeter of quadrant of circle is $\dfrac{{2\pi r}}{4}$
where we take $\pi = \dfrac{{22}}{7}$ and Radius of circle is given $r = \dfrac{7}{2}$ ;
By putting these value ,
= $\dfrac{{2 \times \dfrac{{22}}{7} \times \dfrac{7}{2}}}{4}$
When we solve we get
= $\dfrac{{22}}{4}$$cm$
In decimal form
= $5.5cm$
So, the correct answer is “Option B”.
Note:Students should also remembered that Area of Circle is = $\pi {r^2}$ And the area of quadrant is $\dfrac{{\pi {r^2}}}{4}$.Perimeter of semi-circle is $\pi r$ and Area of semi-circle is $\dfrac{{\pi {r^2}}}{2}$.
Perimeter of Square is $4 \times a$ and Area of Square is ${a^2}$ where a is the side of the square.
Perimeter of rectangle is $2\left( {l + b} \right)$ and Area of rectangle is $l \times b$ where $l = $ Length of Rectangle and $b = $ breadth of Rectangle.
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