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**Hint:**We draw a circle having radius ‘a’ circumscribed inside a square. Use the property of sides of squares being equal to compare with the diameter of the circle. Use the formula of perimeter of square to find the perimeter.

* Perimeter of a square having side ‘x’ is 4x. A square is a quadrilateral having all four sides of equal length and having all angles as right angles.

* Circumscribed word means to enclose a figure within some bounds. When we say x circumscribing y we mean that y is enclosed completely within x.

**Complete step-by-step solution:**

We draw a figure where a square is circumscribing a circle of radius ‘a’.

We know the perimeter of square PQRS is the sum of the lengths of all sides of the square.

\[ \Rightarrow \]Perimeter\[ = \left( {PQ + QR + RS + SP} \right)\]

Since all sides of the square are equal

So, \[PQ = QR = RS = SP\]

\[ \Rightarrow \]Perimeter\[ = \left( {PQ + PQ + PQ + PQ} \right)\]

\[ \Rightarrow \]Perimeter\[ = 4PQ\]....................… (1)

Now we know the radius of the circle is ‘a’.

Since diameter is twice the radius of the circle

\[ \Rightarrow \]Diameter of the circle\[ = 2a\]cm…………………..… (2)

If we draw diameter in such a way that it is parallel to the side of the square, then the length of the diameter is equal to the length of the side of the square.

\[ \Rightarrow PQ = 2a\]cm

Substitute the value of PQ in equation (1)

\[ \Rightarrow \]Perimeter of square PQRS \[ = \left( {4 \times 2a} \right)\]cm

\[ \Rightarrow \]Perimeter of square PQRS\[ = 8a\]cm

\[\therefore \]Perimeter of square is 8a (cm)

**\[\therefore \]Correct option is A.**

**Note:**Students are likely to make mistakes by drawing the opposite diagram, they tend to draw squares inside the circle. Keep in mind circumscribing means that the square has a circle inscribed in it.

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