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# The lid of a rectangular box of sides 40 cm by 10 cm is sealed all around with tape. What is the length of the tape required?

Last updated date: 20th Jun 2024
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Hint: We will first draw the figure of the rectangular figure and then analyze the question and we will see that the length of the tape required will be equal to the perimeter of the lid. Therefore, we will first define the perimeter and then derive the formula of the perimeter of a rectangle and then put the given values and get the answer.

Now, to find the perimeter of a rectangle with a given length $l$ and breadth $b$ , the perimeter $P$ will be sum of all its sides that is: $P=l+l+b+b=2l+2b=2\left( l+b \right)$
Now, we have with us length as 40 cm and breadth as 10 cm, therefore the perimeter or the length of the boundary will be: $P=2\left( l+b \right)=2\left( 40+10 \right)=100\text{ cm}$ .