Question

The height of a parallelogram is three-eighth of its base. If the area of the parallelogram is , find its height and base.

Answer 1

Hint: Frame an equation from the information given in the question and then use formula,
Area of parallelogram =Base* Height.

Complete step-by-step answer:
Given that the height of the parallelogram is three-eighth of its base. If b is the base and h is the height of the parallelogram, then we have:
$ \Rightarrow h = \dfrac{3}{8}b .....(i)$
Now, we know that the area of a parallelogram is given as:
$ \Rightarrow $ Area of parallelogram Base Height.
$ \Rightarrow A = b \times h$
Putting the area of parallelogram as from the question and the value of h from equation , we’ll get:

$
   \Rightarrow 96 = b \times \dfrac{3}{8}b, \\
   \Rightarrow {b^2} = \dfrac{{96 \times 8}}{3}, \\
   \Rightarrow {b^2} = 256, \\
   \Rightarrow b = 16 \\
$
Putting the value of b back in , we will get:
$
   \Rightarrow h = \dfrac{3}{8} \times 16, \\
   \Rightarrow h = 6 \\
$
Thus the height and base of the parallelogram are 6 cm and 16 cm respectively.

Note: Area of parallelogram is also calculated using formula:

$ \Rightarrow $ Area of parallelogram $ = \dfrac{1}{2} \times $ height (sum of parallel sides)
We can use any of them as per the data given in the question.