Answer
351.9k+ views
Hint: The area can be defined as the space occupied by a flat surface of an object. The area is the number of unit squares closed by figure. Perimeter is the total length of the sides of the two dimensional shape. Perimeter is always less than the area of the given figure. Because the perimeter is outer and the area is inner property. Volume is the capacity which hold by objects
As we know that
$\therefore V = \dfrac{1}{3}\pi {r^2}h$
Here
V=volume
r=radius
h=height
Complete step-by-step solution:
Given,
Diameter of heap,$d = 48m$
Radius of heap, $r = \dfrac{{48}}{2}m$
Radius of heap, $r = 24m$
Height of heap, $h = 7m$
Rate of canvass $Rs.7\,per\,100c{m^2}$
Volume=?
Slant height of heap, $l = ?$
As we know that
$\therefore l = \sqrt {{h^2} + {r^2}} $
Put the value
$ \Rightarrow l = \sqrt {{7^2} + {{24}^2}} $
$ \Rightarrow l = \sqrt {49 + 576} $
$ \Rightarrow l = \sqrt {625} $
$ \Rightarrow l = 25m$
Now the volume of heap
As we know that
$\therefore V = \dfrac{1}{3}\pi {r^2}h$
Put the value
$ \Rightarrow V = \dfrac{1}{3} \times \dfrac{{22}}{7} \times {(24)^2} \times 7$
Simplify
$ \Rightarrow V = 22 \times 24 \times 8$
$ \Rightarrow V = 4224{m^3}$
Now area covered by canvas
As we know that
$\therefore A = \pi rl$
Put the value
$ \Rightarrow A = \dfrac{{22}}{7} \times 24 \times 25$
Simplify
$ \Rightarrow A = \dfrac{{13200}}{7}$
$ \Rightarrow A = 1885.71{m^2}$
Now
The price of canvas,
$ \Rightarrow \text{Price of canvas} = \text{Area covered} \times \text{Rate of canvas}$
Put the value
$ \Rightarrow \text{Price of canvas} = 1885.71 \times \dfrac{7}{{100}}$
$1{m^2} = 10000c{m^2}$
$ \Rightarrow \text{Price of canvas} = 1885.71 \times \dfrac{7}{{100}} \times 10000$
$ \Rightarrow \text{Price of canvas} = Rs.1320000$
Note: The slant height of an object (such as frustum, cone, and pyramid) is the distance measured along a lateral face from the base to the apex along the “center” of the face. As we know that the slant height is given by
$\therefore l = \sqrt {{h^2} + {r^2}} $
Here
h=height of cone
r=base radius of cone
Here slant height is important to find the curved surface area of the cone, curved surface area means the area of surface which we can touch(outer surface).
As we know that
$\therefore V = \dfrac{1}{3}\pi {r^2}h$
Here
V=volume
r=radius
h=height
Complete step-by-step solution:
![seo images](https://www.vedantu.com/question-sets/2f87ac70-dfb1-44a6-b652-f6ab858f7c025058425658214566852.png)
Given,
Diameter of heap,$d = 48m$
Radius of heap, $r = \dfrac{{48}}{2}m$
Radius of heap, $r = 24m$
Height of heap, $h = 7m$
Rate of canvass $Rs.7\,per\,100c{m^2}$
Volume=?
Slant height of heap, $l = ?$
As we know that
$\therefore l = \sqrt {{h^2} + {r^2}} $
Put the value
$ \Rightarrow l = \sqrt {{7^2} + {{24}^2}} $
$ \Rightarrow l = \sqrt {49 + 576} $
$ \Rightarrow l = \sqrt {625} $
$ \Rightarrow l = 25m$
Now the volume of heap
As we know that
$\therefore V = \dfrac{1}{3}\pi {r^2}h$
Put the value
$ \Rightarrow V = \dfrac{1}{3} \times \dfrac{{22}}{7} \times {(24)^2} \times 7$
Simplify
$ \Rightarrow V = 22 \times 24 \times 8$
$ \Rightarrow V = 4224{m^3}$
Now area covered by canvas
As we know that
$\therefore A = \pi rl$
Put the value
$ \Rightarrow A = \dfrac{{22}}{7} \times 24 \times 25$
Simplify
$ \Rightarrow A = \dfrac{{13200}}{7}$
$ \Rightarrow A = 1885.71{m^2}$
Now
The price of canvas,
$ \Rightarrow \text{Price of canvas} = \text{Area covered} \times \text{Rate of canvas}$
Put the value
$ \Rightarrow \text{Price of canvas} = 1885.71 \times \dfrac{7}{{100}}$
$1{m^2} = 10000c{m^2}$
$ \Rightarrow \text{Price of canvas} = 1885.71 \times \dfrac{7}{{100}} \times 10000$
$ \Rightarrow \text{Price of canvas} = Rs.1320000$
Note: The slant height of an object (such as frustum, cone, and pyramid) is the distance measured along a lateral face from the base to the apex along the “center” of the face. As we know that the slant height is given by
$\therefore l = \sqrt {{h^2} + {r^2}} $
Here
h=height of cone
r=base radius of cone
Here slant height is important to find the curved surface area of the cone, curved surface area means the area of surface which we can touch(outer surface).
Recently Updated Pages
How many sigma and pi bonds are present in HCequiv class 11 chemistry CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Why Are Noble Gases NonReactive class 11 chemistry CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Let X and Y be the sets of all positive divisors of class 11 maths CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Let x and y be 2 real numbers which satisfy the equations class 11 maths CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Let x 4log 2sqrt 9k 1 + 7 and y dfrac132log 2sqrt5 class 11 maths CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Let x22ax+b20 and x22bx+a20 be two equations Then the class 11 maths CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Trending doubts
Fill the blanks with the suitable prepositions 1 The class 9 english CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
At which age domestication of animals started A Neolithic class 11 social science CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Which are the Top 10 Largest Countries of the World?
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Give 10 examples for herbs , shrubs , climbers , creepers
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Difference between Prokaryotic cell and Eukaryotic class 11 biology CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Difference Between Plant Cell and Animal Cell
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Write a letter to the principal requesting him to grant class 10 english CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Change the following sentences into negative and interrogative class 10 english CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Fill in the blanks A 1 lakh ten thousand B 1 million class 9 maths CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)