
The equivalent weight of ${{K}_{2}}C{{r}_{2}}{{O}_{7}}$ in acidic medium is expressed in terms of its molecular weight (M) as –
(A) M/3
(B) M/4
(C) M/6
(D) M/7
Answer
585k+ views
Hint: Equivalent weight is related to molecular weight by the equation –
Equivalent weight = molecular weight / chemical equivalent.
We will get the answer in terms of molecular weight by substituting the chemical equivalent.
Complete step by step solution:
- Let us first understand the concepts of molecular weight and equivalent weight.
- Molecular weight is the mass of one molecule of a particular compound. The molecular weight of a particular molecule can be found using its chemical formula. The sum of atomic weights of the atoms in the molecule gives you the molecular weight.
- The equivalent weight can be defined as the ratio of molecular weight to the chemical equivalent. The chemical equivalent can be calculated by finding the number of electrons that participate in the chemical reaction.
- Molecular weight is related to equivalent weight by the formula –
Equivalent weight = molecular weight / chemical equivalent
- This equation can be used to find the equivalent weight from the molecular weight of the substance.
- We have to find the equivalent weight of ${{K}_{2}}C{{r}_{2}}{{O}_{7}}$ in acidic medium. ${{K}_{2}}C{{r}_{2}}{{O}_{7}}$ in acidic medium gives the following ions-
${{K}_{2}}C{{r}_{2}}{{O}_{7}}+14{{H}^{+}}+6{{e}^{-}}\to 2{{K}^{+}}+2C{{r}^{3+}}+7{{H}_{2}}O$
- Hence, we can conclude that the chemical equivalent is 6. This is because there are 6 electrons participating in the chemical reaction.
- We have to find the equivalent weight in terms of molecular weight. So let us take the molecular weight of ${{K}_{2}}C{{r}_{2}}{{O}_{7}}$ to be M.
- Let us now substitute the molecular weight and chemical equivalent in the equation.
Equivalent weight = M / 6.
- Hence, the answer is option (C) M/6.
Note: Molecular weight should not be confused with molar mass. Molar mass and molecular weight are two different concepts. Molar mass is the mass of one mole of a given compound. Whereas, molecular weight is the mass of one molecule of a particular compound.
Equivalent weight = molecular weight / chemical equivalent.
We will get the answer in terms of molecular weight by substituting the chemical equivalent.
Complete step by step solution:
- Let us first understand the concepts of molecular weight and equivalent weight.
- Molecular weight is the mass of one molecule of a particular compound. The molecular weight of a particular molecule can be found using its chemical formula. The sum of atomic weights of the atoms in the molecule gives you the molecular weight.
- The equivalent weight can be defined as the ratio of molecular weight to the chemical equivalent. The chemical equivalent can be calculated by finding the number of electrons that participate in the chemical reaction.
- Molecular weight is related to equivalent weight by the formula –
Equivalent weight = molecular weight / chemical equivalent
- This equation can be used to find the equivalent weight from the molecular weight of the substance.
- We have to find the equivalent weight of ${{K}_{2}}C{{r}_{2}}{{O}_{7}}$ in acidic medium. ${{K}_{2}}C{{r}_{2}}{{O}_{7}}$ in acidic medium gives the following ions-
${{K}_{2}}C{{r}_{2}}{{O}_{7}}+14{{H}^{+}}+6{{e}^{-}}\to 2{{K}^{+}}+2C{{r}^{3+}}+7{{H}_{2}}O$
- Hence, we can conclude that the chemical equivalent is 6. This is because there are 6 electrons participating in the chemical reaction.
- We have to find the equivalent weight in terms of molecular weight. So let us take the molecular weight of ${{K}_{2}}C{{r}_{2}}{{O}_{7}}$ to be M.
- Let us now substitute the molecular weight and chemical equivalent in the equation.
Equivalent weight = M / 6.
- Hence, the answer is option (C) M/6.
Note: Molecular weight should not be confused with molar mass. Molar mass and molecular weight are two different concepts. Molar mass is the mass of one mole of a given compound. Whereas, molecular weight is the mass of one molecule of a particular compound.
Recently Updated Pages
Why are manures considered better than fertilizers class 11 biology CBSE

Find the coordinates of the midpoint of the line segment class 11 maths CBSE

Distinguish between static friction limiting friction class 11 physics CBSE

The Chairman of the constituent Assembly was A Jawaharlal class 11 social science CBSE

The first National Commission on Labour NCL submitted class 11 social science CBSE

Number of all subshell of n + l 7 is A 4 B 5 C 6 D class 11 chemistry CBSE

Trending doubts
Differentiate between an exothermic and an endothermic class 11 chemistry CBSE

10 examples of friction in our daily life

One Metric ton is equal to kg A 10000 B 1000 C 100 class 11 physics CBSE

Difference Between Prokaryotic Cells and Eukaryotic Cells

1 Quintal is equal to a 110 kg b 10 kg c 100kg d 1000 class 11 physics CBSE

State the laws of reflection of light

