Answer
424.5k+ views
Hint: First synchronize the whole process using a flowchart, so that reactions and all elements are considered, without any confusion. The flowchart of the above mentioned reactions is: $\begin{align}
& \text{A}\xrightarrow{{{\text{N}}_{2}}}\underset{\text{ionic}}{\mathop{\text{B}}}\,\xrightarrow{{{\text{H}}_{2}}\text{O}}\text{D}+\left( \text{C} \right)\xrightarrow{\text{C}{{\text{O}}_{2}}}\text{milkiness} \\
& \text{ } \\
\end{align}$. We should follow this flowchart from the backside to solve the question easily. The milkiness appears because of formation of white-coloured precipitate of carbonate.
Complete answer:
Let us start solving this question from the back, as it would be easier to find the compounds from the back side.
- When C reacts with carbon dioxide, the solution turns milky. This milkiness is observed due to formation of calcium carbonate in the solution. The reaction would be $\text{Ca}{{\left( \text{OH} \right)}_{2}}\left( \text{aq}\text{.} \right)+\text{C}{{\text{O}}_{2}}\left( \text{g} \right)\to \text{CaC}{{\text{O}}_{3}}\downarrow \left( \text{s} \right)+{{\text{H}}_{2}}\text{O}\left( \text{l} \right)$. So, it is clear that the compound $\left( \text{C} \right)$ is calcium hydroxide.
- If element ‘A’ reacts with nitrogen gas then, the ionic compound formed must have nitrogen in it. Further, on hydrolysis, the nitrogenous compound would have been formed along with calcium hydroxide. So, it is clear that element ‘A’ is calcium because calcium is not introduced in between the reaction.
- Reaction of element ‘A’ with nitrogen would be ionic in nature. The reaction would be $\text{3Ca}+{{\text{N}}_{2}}\to \text{C}{{\text{a}}_{3}}{{\text{N}}_{2}}$. The compound formed is calcium nitride. So, the ionic compound ‘B’ is calcium nitride.
- When calcium nitride undergoes hydrolysis, the compounds formed are $\text{C}{{\text{a}}_{3}}{{\text{N}}_{2}}+6{{\text{H}}_{2}}\text{O}\to 2\text{N}{{\text{H}}_{3}}+3\text{Ca}{{\left( \text{OH} \right)}_{2}}$. Where compound ‘D’ is ammonia gas and compound ‘C’ is calcium hydroxide.
The reactions and flowchart is completed; $\begin{align}
& \text{Ca}\xrightarrow{{{\text{N}}_{2}}}\underset{\text{ionic}}{\mathop{\text{C}{{\text{a}}_{3}}{{\text{N}}_{2}}}}\,\xrightarrow{{{\text{H}}_{2}}\text{O}}\text{N}{{\text{H}}_{3}}+\left[ \text{Ca}{{\left( \text{OH} \right)}_{2}} \right]\xrightarrow{\text{C}{{\text{O}}_{2}}}\text{milkiness} \\
& \text{ } \\
\end{align}$ . The nature of compound ‘D’ is basic in nature. We know ammonia has a lone pair, so it denotes its lone pair to electrophiles. The basic nature of ammonia can be explained by a reaction$\text{N}{{\text{H}}_{3}}+{{\text{H}}_{2}}\text{O}\to \text{N}{{\text{H}}_{4}}^{+}+\text{O}{{\text{H}}^{-}}$ by the formation of $\text{O}{{\text{H}}^{-}}$ ions.
So, the correct answer is “Option B”.
Note: In this question, the points to remember are the basic equations and the nature of the compounds formed. Such questions can be easily tackled if we make a proper flowchart, considering all the reactions and reagents along with their properties.
& \text{A}\xrightarrow{{{\text{N}}_{2}}}\underset{\text{ionic}}{\mathop{\text{B}}}\,\xrightarrow{{{\text{H}}_{2}}\text{O}}\text{D}+\left( \text{C} \right)\xrightarrow{\text{C}{{\text{O}}_{2}}}\text{milkiness} \\
& \text{ } \\
\end{align}$. We should follow this flowchart from the backside to solve the question easily. The milkiness appears because of formation of white-coloured precipitate of carbonate.
Complete answer:
Let us start solving this question from the back, as it would be easier to find the compounds from the back side.
- When C reacts with carbon dioxide, the solution turns milky. This milkiness is observed due to formation of calcium carbonate in the solution. The reaction would be $\text{Ca}{{\left( \text{OH} \right)}_{2}}\left( \text{aq}\text{.} \right)+\text{C}{{\text{O}}_{2}}\left( \text{g} \right)\to \text{CaC}{{\text{O}}_{3}}\downarrow \left( \text{s} \right)+{{\text{H}}_{2}}\text{O}\left( \text{l} \right)$. So, it is clear that the compound $\left( \text{C} \right)$ is calcium hydroxide.
- If element ‘A’ reacts with nitrogen gas then, the ionic compound formed must have nitrogen in it. Further, on hydrolysis, the nitrogenous compound would have been formed along with calcium hydroxide. So, it is clear that element ‘A’ is calcium because calcium is not introduced in between the reaction.
- Reaction of element ‘A’ with nitrogen would be ionic in nature. The reaction would be $\text{3Ca}+{{\text{N}}_{2}}\to \text{C}{{\text{a}}_{3}}{{\text{N}}_{2}}$. The compound formed is calcium nitride. So, the ionic compound ‘B’ is calcium nitride.
- When calcium nitride undergoes hydrolysis, the compounds formed are $\text{C}{{\text{a}}_{3}}{{\text{N}}_{2}}+6{{\text{H}}_{2}}\text{O}\to 2\text{N}{{\text{H}}_{3}}+3\text{Ca}{{\left( \text{OH} \right)}_{2}}$. Where compound ‘D’ is ammonia gas and compound ‘C’ is calcium hydroxide.
The reactions and flowchart is completed; $\begin{align}
& \text{Ca}\xrightarrow{{{\text{N}}_{2}}}\underset{\text{ionic}}{\mathop{\text{C}{{\text{a}}_{3}}{{\text{N}}_{2}}}}\,\xrightarrow{{{\text{H}}_{2}}\text{O}}\text{N}{{\text{H}}_{3}}+\left[ \text{Ca}{{\left( \text{OH} \right)}_{2}} \right]\xrightarrow{\text{C}{{\text{O}}_{2}}}\text{milkiness} \\
& \text{ } \\
\end{align}$ . The nature of compound ‘D’ is basic in nature. We know ammonia has a lone pair, so it denotes its lone pair to electrophiles. The basic nature of ammonia can be explained by a reaction$\text{N}{{\text{H}}_{3}}+{{\text{H}}_{2}}\text{O}\to \text{N}{{\text{H}}_{4}}^{+}+\text{O}{{\text{H}}^{-}}$ by the formation of $\text{O}{{\text{H}}^{-}}$ ions.
So, the correct answer is “Option B”.
Note: In this question, the points to remember are the basic equations and the nature of the compounds formed. Such questions can be easily tackled if we make a proper flowchart, considering all the reactions and reagents along with their properties.
Recently Updated Pages
How many sigma and pi bonds are present in HCequiv class 11 chemistry CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Why Are Noble Gases NonReactive class 11 chemistry CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Let X and Y be the sets of all positive divisors of class 11 maths CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Let x and y be 2 real numbers which satisfy the equations class 11 maths CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Let x 4log 2sqrt 9k 1 + 7 and y dfrac132log 2sqrt5 class 11 maths CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Let x22ax+b20 and x22bx+a20 be two equations Then the class 11 maths CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Trending doubts
Fill the blanks with the suitable prepositions 1 The class 9 english CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
At which age domestication of animals started A Neolithic class 11 social science CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Which are the Top 10 Largest Countries of the World?
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Give 10 examples for herbs , shrubs , climbers , creepers
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Difference between Prokaryotic cell and Eukaryotic class 11 biology CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Difference Between Plant Cell and Animal Cell
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Write a letter to the principal requesting him to grant class 10 english CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Change the following sentences into negative and interrogative class 10 english CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Fill in the blanks A 1 lakh ten thousand B 1 million class 9 maths CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)