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# The element A burns in nitrogen to give an ionic compound B. The compound B reacts with water to give C and D. A solution of C becomes milky on bubbling carbon dioxide. What is the nature of compound (D)? A. AcidicB. BasicC. AmphotericD. Neutral

Last updated date: 14th Jun 2024
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Hint: First synchronize the whole process using a flowchart, so that reactions and all elements are considered, without any confusion. The flowchart of the above mentioned reactions is: \begin{align} & \text{A}\xrightarrow{{{\text{N}}_{2}}}\underset{\text{ionic}}{\mathop{\text{B}}}\,\xrightarrow{{{\text{H}}_{2}}\text{O}}\text{D}+\left( \text{C} \right)\xrightarrow{\text{C}{{\text{O}}_{2}}}\text{milkiness} \\ & \text{ } \\ \end{align}. We should follow this flowchart from the backside to solve the question easily. The milkiness appears because of formation of white-coloured precipitate of carbonate.

- When C reacts with carbon dioxide, the solution turns milky. This milkiness is observed due to formation of calcium carbonate in the solution. The reaction would be $\text{Ca}{{\left( \text{OH} \right)}_{2}}\left( \text{aq}\text{.} \right)+\text{C}{{\text{O}}_{2}}\left( \text{g} \right)\to \text{CaC}{{\text{O}}_{3}}\downarrow \left( \text{s} \right)+{{\text{H}}_{2}}\text{O}\left( \text{l} \right)$. So, it is clear that the compound $\left( \text{C} \right)$ is calcium hydroxide.
- Reaction of element ‘A’ with nitrogen would be ionic in nature. The reaction would be $\text{3Ca}+{{\text{N}}_{2}}\to \text{C}{{\text{a}}_{3}}{{\text{N}}_{2}}$. The compound formed is calcium nitride. So, the ionic compound ‘B’ is calcium nitride.
- When calcium nitride undergoes hydrolysis, the compounds formed are $\text{C}{{\text{a}}_{3}}{{\text{N}}_{2}}+6{{\text{H}}_{2}}\text{O}\to 2\text{N}{{\text{H}}_{3}}+3\text{Ca}{{\left( \text{OH} \right)}_{2}}$. Where compound ‘D’ is ammonia gas and compound ‘C’ is calcium hydroxide.
The reactions and flowchart is completed; \begin{align} & \text{Ca}\xrightarrow{{{\text{N}}_{2}}}\underset{\text{ionic}}{\mathop{\text{C}{{\text{a}}_{3}}{{\text{N}}_{2}}}}\,\xrightarrow{{{\text{H}}_{2}}\text{O}}\text{N}{{\text{H}}_{3}}+\left[ \text{Ca}{{\left( \text{OH} \right)}_{2}} \right]\xrightarrow{\text{C}{{\text{O}}_{2}}}\text{milkiness} \\ & \text{ } \\ \end{align} . The nature of compound ‘D’ is basic in nature. We know ammonia has a lone pair, so it denotes its lone pair to electrophiles. The basic nature of ammonia can be explained by a reaction$\text{N}{{\text{H}}_{3}}+{{\text{H}}_{2}}\text{O}\to \text{N}{{\text{H}}_{4}}^{+}+\text{O}{{\text{H}}^{-}}$ by the formation of $\text{O}{{\text{H}}^{-}}$ ions.