Answer

Verified

452.4k+ views

Hint – Assume fixed charges and per km charges as two different variables .Now total cost is the sum of fixed charges and variable charges.

Let, the fixed charge be x Rs.

And let the per km charge be y Rs.

Now, it is given that for a journey of 12 km, the charges paid is Rs. 89.

$ \Rightarrow x + 12y = 89................\left( 1 \right)$

And also it is given that for a journey of 20 km the charge paid is Rs. 145.

$ \Rightarrow x + 20y = 145................\left( 2 \right)$

Subtract equation (1) from equation (2)

$

\Rightarrow x + 20y - x - 12y = 145 - 89 \\

\Rightarrow 8y = 56 \\

\Rightarrow y = 7 \\

$

So, per km charge is 7 Rs.

Now, from equation (1)

$

x + 12y = 89 \\

\Rightarrow x + 12 \times 7 = 89 \\

\Rightarrow x = 89 - 84 = 5 \\

$

So, fixed charges are 5 Rs.

Now we have to calculate what a person will have to pay for travelling a distance of 30km.

$

\Rightarrow x + 30y \\

= 5 + 30 \times 7 = 5 + 210 = 215 \\

$

Thus the person will have to pay 215 Rs. for travelling a distance of 30km.

Note – whenever we face such types of problems first construct the linear equations according to given information after that solve these equations and calculate the values of fixed and variable charges then we easily calculate how much a person will have to pay for travelling a distance of 30km.

Let, the fixed charge be x Rs.

And let the per km charge be y Rs.

Now, it is given that for a journey of 12 km, the charges paid is Rs. 89.

$ \Rightarrow x + 12y = 89................\left( 1 \right)$

And also it is given that for a journey of 20 km the charge paid is Rs. 145.

$ \Rightarrow x + 20y = 145................\left( 2 \right)$

Subtract equation (1) from equation (2)

$

\Rightarrow x + 20y - x - 12y = 145 - 89 \\

\Rightarrow 8y = 56 \\

\Rightarrow y = 7 \\

$

So, per km charge is 7 Rs.

Now, from equation (1)

$

x + 12y = 89 \\

\Rightarrow x + 12 \times 7 = 89 \\

\Rightarrow x = 89 - 84 = 5 \\

$

So, fixed charges are 5 Rs.

Now we have to calculate what a person will have to pay for travelling a distance of 30km.

$

\Rightarrow x + 30y \\

= 5 + 30 \times 7 = 5 + 210 = 215 \\

$

Thus the person will have to pay 215 Rs. for travelling a distance of 30km.

Note – whenever we face such types of problems first construct the linear equations according to given information after that solve these equations and calculate the values of fixed and variable charges then we easily calculate how much a person will have to pay for travelling a distance of 30km.

Recently Updated Pages

How many sigma and pi bonds are present in HCequiv class 11 chemistry CBSE

Why Are Noble Gases NonReactive class 11 chemistry CBSE

Let X and Y be the sets of all positive divisors of class 11 maths CBSE

Let x and y be 2 real numbers which satisfy the equations class 11 maths CBSE

Let x 4log 2sqrt 9k 1 + 7 and y dfrac132log 2sqrt5 class 11 maths CBSE

Let x22ax+b20 and x22bx+a20 be two equations Then the class 11 maths CBSE

Trending doubts

Which are the Top 10 Largest Countries of the World?

Fill the blanks with the suitable prepositions 1 The class 9 english CBSE

Write a letter to the principal requesting him to grant class 10 english CBSE

Summary of the poem Where the Mind is Without Fear class 8 english CBSE

Difference Between Plant Cell and Animal Cell

Difference between Prokaryotic cell and Eukaryotic class 11 biology CBSE

Give 10 examples for herbs , shrubs , climbers , creepers

Change the following sentences into negative and interrogative class 10 english CBSE

Differentiate between homogeneous and heterogeneous class 12 chemistry CBSE