
The angle of elevation of the top of the tower at a distance of 300 meters from its foot on a horizontal plane is found to be \[{30^ \circ }\]. The height of the tower is
A. 173m
B. \[300\sqrt 3 m\]
C. 100m
D. None of these
Answer
541.8k+ views
Hint: This problem is from heights and distances. We will easily solve this just by applying \[{30^ \circ } - {60^ \circ } - {90^ \circ }\] triangle theorem. That is side opposite to \[{60^ \circ }\] is \[{{{\sqrt 3 }} \!{\left/
{\vphantom {{\sqrt 3 } 2}}\right.}
\!\lower0.7ex{2}}\] times the hypotenuse and that opposite to \[{30^ \circ }\] is half of the hypotenuse. This is the simple and correct approach we will use here only because we know the angle of elevation.
Step by step solution:
Now let’s draw the figure first with a tower of height supposed to say h and the angle of elevation is \[{30^ \circ }\]. Also given that the distance is 300 meters from its foot on a horizontal plane.
This is the figure so formed. Now we will find the height of the tower with the help of hypotenuse of the figure.
Using our \[{30^ \circ } - {60^ \circ } - {90^ \circ }\] triangle theorem,
Side opposite to \[{60^ \circ }\]=300
\[ \Rightarrow {{{\sqrt 3 }} \!{\left/
{\vphantom {{\sqrt 3 } 2}}\right.}
\!\lower0.7ex{2}} \times hypt = 300\]
Thus value of hypotenuse is
\[ \Rightarrow hypt = 300 \times {{2} \!{\left/
{\vphantom {2 {\sqrt 3 }}}\right.}
\!\lower0.7ex{{\sqrt 3 }}}\]
Thus we get, \[ \Rightarrow hypt = {{{600}} \!{\left/
{\vphantom {{600} {\sqrt 3 }}}\right.}
\!\lower0.7ex{{\sqrt 3 }}}m\]
Now to get the height of the tower we will use this hypotenuse length.
Height of the tower is exactly the side opposite to the elevation angle \[{30^ \circ }\].
Side opposite to \[{30^ \circ }\]= \[{{1} \!{\left/
{\vphantom {1 2}}\right.}
\!\lower0.7ex{2}} \times hypt\]
\[ \Rightarrow h = {{1} \!{\left/
{\vphantom {1 2}}\right.}
\!\lower0.7ex{2}} \times hypt\]
Putting the value of hypotenuse
\[ \Rightarrow h = {{1} \!{\left/
{\vphantom {1 2}}\right.}
\!\lower0.7ex{2}} \times {{{600}} \!{\left/
{\vphantom {{600} {\sqrt 3 }}}\right.}
\!\lower0.7ex{{\sqrt 3 }}}\]
\[ \Rightarrow h = {{{300}} \!{\left/
{\vphantom {{300} {\sqrt 3 }}}\right.}
\!\lower0.7ex{{\sqrt 3 }}}m\]
This is the height of the tower \[ \Rightarrow h = {{{300}} \!{\left/
{\vphantom {{300} {\sqrt 3 }}}\right.}
\!\lower0.7ex{{\sqrt 3 }}}m\]
But there is no option matching here. Thus option D is the correct option “none of these”.
Note:
Students don’t hurry when you choose options because most of the students find the correct answer but fail to select. See here in this case the answer is in ratio form but since option B is similar looking people may tick it as correct. But it is the wrong one. So be careful when you choose the option.
{\vphantom {{\sqrt 3 } 2}}\right.}
\!\lower0.7ex{2}}\] times the hypotenuse and that opposite to \[{30^ \circ }\] is half of the hypotenuse. This is the simple and correct approach we will use here only because we know the angle of elevation.
Step by step solution:
Now let’s draw the figure first with a tower of height supposed to say h and the angle of elevation is \[{30^ \circ }\]. Also given that the distance is 300 meters from its foot on a horizontal plane.
This is the figure so formed. Now we will find the height of the tower with the help of hypotenuse of the figure.
Using our \[{30^ \circ } - {60^ \circ } - {90^ \circ }\] triangle theorem,
Side opposite to \[{60^ \circ }\]=300
\[ \Rightarrow {{{\sqrt 3 }} \!{\left/
{\vphantom {{\sqrt 3 } 2}}\right.}
\!\lower0.7ex{2}} \times hypt = 300\]
Thus value of hypotenuse is
\[ \Rightarrow hypt = 300 \times {{2} \!{\left/
{\vphantom {2 {\sqrt 3 }}}\right.}
\!\lower0.7ex{{\sqrt 3 }}}\]
Thus we get, \[ \Rightarrow hypt = {{{600}} \!{\left/
{\vphantom {{600} {\sqrt 3 }}}\right.}
\!\lower0.7ex{{\sqrt 3 }}}m\]
Now to get the height of the tower we will use this hypotenuse length.
Height of the tower is exactly the side opposite to the elevation angle \[{30^ \circ }\].
Side opposite to \[{30^ \circ }\]= \[{{1} \!{\left/
{\vphantom {1 2}}\right.}
\!\lower0.7ex{2}} \times hypt\]
\[ \Rightarrow h = {{1} \!{\left/
{\vphantom {1 2}}\right.}
\!\lower0.7ex{2}} \times hypt\]
Putting the value of hypotenuse
\[ \Rightarrow h = {{1} \!{\left/
{\vphantom {1 2}}\right.}
\!\lower0.7ex{2}} \times {{{600}} \!{\left/
{\vphantom {{600} {\sqrt 3 }}}\right.}
\!\lower0.7ex{{\sqrt 3 }}}\]
\[ \Rightarrow h = {{{300}} \!{\left/
{\vphantom {{300} {\sqrt 3 }}}\right.}
\!\lower0.7ex{{\sqrt 3 }}}m\]
This is the height of the tower \[ \Rightarrow h = {{{300}} \!{\left/
{\vphantom {{300} {\sqrt 3 }}}\right.}
\!\lower0.7ex{{\sqrt 3 }}}m\]
But there is no option matching here. Thus option D is the correct option “none of these”.
Note:
Students don’t hurry when you choose options because most of the students find the correct answer but fail to select. See here in this case the answer is in ratio form but since option B is similar looking people may tick it as correct. But it is the wrong one. So be careful when you choose the option.
Recently Updated Pages
Two men on either side of the cliff 90m height observe class 10 maths CBSE

What happens to glucose which enters nephron along class 10 biology CBSE

Cutting of the Chinese melon means A The business and class 10 social science CBSE

Write a dialogue with at least ten utterances between class 10 english CBSE

Show an aquatic food chain using the following organisms class 10 biology CBSE

A circle is inscribed in an equilateral triangle and class 10 maths CBSE

Trending doubts
The shortest day of the year in India

Why is there a time difference of about 5 hours between class 10 social science CBSE

Write a letter to the principal requesting him to grant class 10 english CBSE

What is the median of the first 10 natural numbers class 10 maths CBSE

The Equation xxx + 2 is Satisfied when x is Equal to Class 10 Maths

What is the missing number in the sequence 259142027 class 10 maths CBSE

