Answer
Verified
396.6k+ views
Hint: To check the presence of nitrate ion in the solution, a test is commonly known as ring test. In this test, iron (II) sulphate is added to the solution in which the presence of nitrate ion is to be checked. The formation of the brown coloured ring confirms the presence of nitrate ions.
Complete answer:
Note: In the reaction, the nitrate ion is reduced to the nitric oxide due to decrease in the oxidation state or loss of the electrons whereas iron (II) is oxidised to the iron (III) due to increase in the oxidation state or gain of the electron.
Complete answer:
The given reaction in the question is performed to check if the nitrate ion is present in the solution or not.
- In the ring test, the complex of ferrous (II) sulphate is added to the solution consisting of nitrate ions (as given in the question).
- Along with the ferrous (II) sulphate, the concentrated sulfuric acid is also added slowly to the solution due to which they yield Hexa aqua iron (II) ion and nitric oxide.
- The balanced reaction will be:
\[3{{\left( \text{Fe}{{({{\text{H}}_{2}}\text{O)}}_{6}} \right)}^{2+}}\,\text{+ NO}_{3}^{-}\ +\text{ 4}{{\text{H}}^{+}}\text{ }\to \text{ NO + 3}{{\left( \text{Fe}{{({{\text{H}}_{2}}\text{O)}}_{6}} \right)}^{3+}}\ \text{+ 2}{{\text{H}}_{2}}\text{O}\]
- Here, nitric oxide is formed which is brown.
- Now, in the second reaction, nitric oxide will react with the iron complex. Also, we can see that one molecule of water is released so in the ligand one molecule will decrease.
- So, the product formed will have one ligand that is nitric oxide so the reaction will be:
\[{{\left( \text{Fe}{{({{\text{H}}_{2}}\text{O)}}_{6}} \right)}^{2+}}\,\text{+ NO }\to \text{ }{{\left( \text{Fe}{{({{\text{H}}_{2}}\text{O)}}_{5}}\text{NO} \right)}^{2+}}\text{ + }{{\text{H}}_{2}}\text{O}\]
- To balance the equation, one should remember that the no. of atoms at the product as well as at the reactant side should be the same.
- Also, the net charge of the molecule should be the same at both the reactant and product side.
Recently Updated Pages
Basicity of sulphurous acid and sulphuric acid are
Three beakers labelled as A B and C each containing 25 mL of water were taken A small amount of NaOH anhydrous CuSO4 and NaCl were added to the beakers A B and C respectively It was observed that there was an increase in the temperature of the solutions contained in beakers A and B whereas in case of beaker C the temperature of the solution falls Which one of the following statements isarecorrect i In beakers A and B exothermic process has occurred ii In beakers A and B endothermic process has occurred iii In beaker C exothermic process has occurred iv In beaker C endothermic process has occurred
The branch of science which deals with nature and natural class 10 physics CBSE
The Equation xxx + 2 is Satisfied when x is Equal to Class 10 Maths
How do you arrange NH4 + BF3 H2O C2H2 in increasing class 11 chemistry CBSE
Is H mCT and q mCT the same thing If so which is more class 11 chemistry CBSE
Trending doubts
Difference between Prokaryotic cell and Eukaryotic class 11 biology CBSE
Fill the blanks with the suitable prepositions 1 The class 9 english CBSE
Write an application to the principal requesting five class 10 english CBSE
Difference Between Plant Cell and Animal Cell
a Tabulate the differences in the characteristics of class 12 chemistry CBSE
Change the following sentences into negative and interrogative class 10 english CBSE
What organs are located on the left side of your body class 11 biology CBSE
Discuss what these phrases mean to you A a yellow wood class 9 english CBSE
List some examples of Rabi and Kharif crops class 8 biology CBSE