Question

# The 600 person took a dip in a rectangular tank which is 60 meter long and 40 meter broad. What is the rise in the level of water in the tank, if the average displacement of water by a person is $0.04{m^3}$?

Hint: In the above question, we are asked to calculate the rise in the level of water in the tank. The dimensions of the tank are given which can be used to calculate the various unknown parameters of the tank.

We have the given values in the question as:
The average displacement of water by one person $= 0.04{m^3}$
Thus, displacement of water by 600 person
$= 0.04{m^3} \times 600$
$= 24{m^3}$
The length of a rectangular tank $l = 60m$
The breadth of a rectangular tank $b = 40m$
Therefore, the area of the base of a rectangular tank
$= l \times b$
$= 60m \times 40m$
$= 2400{m^2}$
Thus, rise in water level = Volume of water displaced $\div$ Area of base of rectangular tank
$= \dfrac{{24{m^3}}}{{2400{m^2}}}$
$= 0.01m$
$= 1cm$
Hence, the rise in the level of water in the tank is $1cm$.

Note: When we encounter such a type of problem, calculate the total volume of the water displaced in the tank and the total area of the base of the rectangular tank. The ratio of these two quantities will lead us to the rise in level of water of the tank.