Students of a class are made to stand in rows. If one student is extra in a row, there would be two rows less. If one student is less in a row there would be 3 rows more. Find the number of students in the class.
Answer
645.9k+ views
Hint – In this question use the property that the number of students in a class is equal to multiplication of number of rows and number of students in each row ,also the number of students in a class remains the same.
Let number of rows $ = x$
And number of students in each row $ = y$
So, the total number of students in class = number of rows $ \times $ number of students in each row
Therefore total number of students in class $ = xy$.
Case 1
If one student is extra in a row i.e.$\left( {y + 1} \right)$, there would be two rows less i.e. $\left( {x - 2} \right)$.
But the total number of students in the class remains the same.
$
\Rightarrow xy = \left( {x - 2} \right)\left( {y + 1} \right) \\
\Rightarrow xy = xy + x - 2y - 2 \\
\Rightarrow x - 2y - 2 = 0.................\left( 1 \right) \\
$
Case 2
If one student is less in a row i.e. $\left( {y - 1} \right)$ there would be 3 rows more i.e. $\left( {x + 3} \right)$.
But the total number of students in the class remains the same.
$
\Rightarrow xy = \left( {x + 3} \right)\left( {y - 1} \right) \\
\Rightarrow xy = xy - x + 3y - 3 \\
\Rightarrow x - 3y + 3 = 0.................\left( 2 \right) \\
$
Now subtract equation (1) from equation (2)
$
x - 3y + 3 - x + 2y + 2 = 0 \\
- y + 5 = 0 \\
\Rightarrow y = 5 \\
$
Therefore from equation (1)
$
x - 2y - 2 = 0 \\
x - 2\left( 5 \right) - 2 = 0 \\
x = 10 + 2 = 12 \\
$
Therefore total number of students in the class
$ = xy = \left( 5 \right)\left( {12} \right) = 60$
So, there are 60 students in the class.
Note – In such types of questions first construct the equations according to given conditions as above then simplify these equations and calculate the values of number of rows and number of students in a particular row, then multiply these two values we will get the required number of students in the class.
Let number of rows $ = x$
And number of students in each row $ = y$
So, the total number of students in class = number of rows $ \times $ number of students in each row
Therefore total number of students in class $ = xy$.
Case 1
If one student is extra in a row i.e.$\left( {y + 1} \right)$, there would be two rows less i.e. $\left( {x - 2} \right)$.
But the total number of students in the class remains the same.
$
\Rightarrow xy = \left( {x - 2} \right)\left( {y + 1} \right) \\
\Rightarrow xy = xy + x - 2y - 2 \\
\Rightarrow x - 2y - 2 = 0.................\left( 1 \right) \\
$
Case 2
If one student is less in a row i.e. $\left( {y - 1} \right)$ there would be 3 rows more i.e. $\left( {x + 3} \right)$.
But the total number of students in the class remains the same.
$
\Rightarrow xy = \left( {x + 3} \right)\left( {y - 1} \right) \\
\Rightarrow xy = xy - x + 3y - 3 \\
\Rightarrow x - 3y + 3 = 0.................\left( 2 \right) \\
$
Now subtract equation (1) from equation (2)
$
x - 3y + 3 - x + 2y + 2 = 0 \\
- y + 5 = 0 \\
\Rightarrow y = 5 \\
$
Therefore from equation (1)
$
x - 2y - 2 = 0 \\
x - 2\left( 5 \right) - 2 = 0 \\
x = 10 + 2 = 12 \\
$
Therefore total number of students in the class
$ = xy = \left( 5 \right)\left( {12} \right) = 60$
So, there are 60 students in the class.
Note – In such types of questions first construct the equations according to given conditions as above then simplify these equations and calculate the values of number of rows and number of students in a particular row, then multiply these two values we will get the required number of students in the class.
Recently Updated Pages
Master Class 11 English: Engaging Questions & Answers for Success

Master Class 11 Maths: Engaging Questions & Answers for Success

Class 11 Question and Answer - Your Ultimate Solutions Guide

Master Class 11 Biology: Engaging Questions & Answers for Success

Master Class 11 Physics: Engaging Questions & Answers for Success

Master Class 11 Accountancy: Engaging Questions & Answers for Success

Trending doubts
Explain the Treaty of Vienna of 1815 class 10 social science CBSE

Who Won 36 Oscar Awards? Record Holder Revealed

What is the median of the first 10 natural numbers class 10 maths CBSE

Why is it 530 pm in india when it is 1200 afternoon class 10 social science CBSE

Why is there a time difference of about 5 hours between class 10 social science CBSE

What is the full form of POSCO class 10 social science CBSE

