Answer
Verified
447.9k+ views
Hint: We must check the statements first. If both the statements are correct then we must check if there is any relation between the two statements. Finally we must check the options which match the answer.
Complete step-by-step answer:
We have statement 1 as If in two triangles, two angles of one triangle are respectively equal to the two angles of the other triangle, then the two triangles are similar.
First, we will try to find out if it is true or not.
Let’s consider two triangles as follows:
Without loss of generality, let us suppose that $\angle A = \angle D$ and $\angle B = \angle E$ ………(1)
We also know that the sum of all the angles of a triangle results in 180$^ \circ $.
So, \[\angle A{\text{ }} + \angle \;B{\text{ }} + \angle C{\text{ }} = {180^ \circ }\] …….(2) and similarly \[\angle D{\text{ }} + \angle E{\text{ }} + \angle F = {180^ \circ }\]…….(3)
Comparing (2) and (3), we have:-
\[\angle A{\text{ }} + \angle \;B{\text{ }} + \angle C{\text{ }} = \angle D{\text{ }} + \angle E{\text{ }} + \angle F\]
This implies \[\angle A{\text{ }} - \angle D{\text{ }} + \angle \;B{\text{ }} - \angle E{\text{ }} + \angle C{\text{ }} = \angle F\] …….(4)
Using (1) in (4):-
$\angle C = \angle F$
Hence, all the corresponding angles are equal and thus, we have:-
$\vartriangle ABC \sim \vartriangle DEF$
This is because of the AAA similarity rule.
Now, in statement two the reason is different.
Hence, option (A) is discarded and since statement 1 is true, so option (D) is discarded as well.
Now, let us check statement 2.
If in two triangles, corresponding angles are equal, then their corresponding sides are in the same ratio and hence the two triangles are similar.
This states that in the given triangles $\dfrac{{AB}}{{DE}} = \dfrac{{BC}}{{EF}}$.
This is a fact related to similar triangles which we can prove by constructing PQ parallel to EF and then using the theorem that: If a line is drawn parallel to one side of the triangle to intersect the other two sides in distinct points, the other two sides are divided in the same ratio.
Hence, it is true as well.
Hence, the correct option is (B).
Note: Since the options (A) and (B) are almost similar, we must look at them carefully because we may mistakenly misread them.
We might make the mistake to infer statement 2 as the correct reason because Statement 1 implies statement 2.
We must remember the facts that: sum of all the angles of a triangle results in ${180^ \circ }$ and If in two triangles, corresponding angles are equal, then their corresponding sides are in the same ratio and hence the two triangles are similar.
Complete step-by-step answer:
We have statement 1 as If in two triangles, two angles of one triangle are respectively equal to the two angles of the other triangle, then the two triangles are similar.
First, we will try to find out if it is true or not.
Let’s consider two triangles as follows:
Without loss of generality, let us suppose that $\angle A = \angle D$ and $\angle B = \angle E$ ………(1)
We also know that the sum of all the angles of a triangle results in 180$^ \circ $.
So, \[\angle A{\text{ }} + \angle \;B{\text{ }} + \angle C{\text{ }} = {180^ \circ }\] …….(2) and similarly \[\angle D{\text{ }} + \angle E{\text{ }} + \angle F = {180^ \circ }\]…….(3)
Comparing (2) and (3), we have:-
\[\angle A{\text{ }} + \angle \;B{\text{ }} + \angle C{\text{ }} = \angle D{\text{ }} + \angle E{\text{ }} + \angle F\]
This implies \[\angle A{\text{ }} - \angle D{\text{ }} + \angle \;B{\text{ }} - \angle E{\text{ }} + \angle C{\text{ }} = \angle F\] …….(4)
Using (1) in (4):-
$\angle C = \angle F$
Hence, all the corresponding angles are equal and thus, we have:-
$\vartriangle ABC \sim \vartriangle DEF$
This is because of the AAA similarity rule.
Now, in statement two the reason is different.
Hence, option (A) is discarded and since statement 1 is true, so option (D) is discarded as well.
Now, let us check statement 2.
If in two triangles, corresponding angles are equal, then their corresponding sides are in the same ratio and hence the two triangles are similar.
This states that in the given triangles $\dfrac{{AB}}{{DE}} = \dfrac{{BC}}{{EF}}$.
This is a fact related to similar triangles which we can prove by constructing PQ parallel to EF and then using the theorem that: If a line is drawn parallel to one side of the triangle to intersect the other two sides in distinct points, the other two sides are divided in the same ratio.
Hence, it is true as well.
Hence, the correct option is (B).
Note: Since the options (A) and (B) are almost similar, we must look at them carefully because we may mistakenly misread them.
We might make the mistake to infer statement 2 as the correct reason because Statement 1 implies statement 2.
We must remember the facts that: sum of all the angles of a triangle results in ${180^ \circ }$ and If in two triangles, corresponding angles are equal, then their corresponding sides are in the same ratio and hence the two triangles are similar.
Recently Updated Pages
How many sigma and pi bonds are present in HCequiv class 11 chemistry CBSE
Mark and label the given geoinformation on the outline class 11 social science CBSE
When people say No pun intended what does that mea class 8 english CBSE
Name the states which share their boundary with Indias class 9 social science CBSE
Give an account of the Northern Plains of India class 9 social science CBSE
Change the following sentences into negative and interrogative class 10 english CBSE
Trending doubts
Difference Between Plant Cell and Animal Cell
Fill the blanks with the suitable prepositions 1 The class 9 english CBSE
Which are the Top 10 Largest Countries of the World?
Give 10 examples for herbs , shrubs , climbers , creepers
Difference between Prokaryotic cell and Eukaryotic class 11 biology CBSE
How do you graph the function fx 4x class 9 maths CBSE
Differentiate between homogeneous and heterogeneous class 12 chemistry CBSE
The Equation xxx + 2 is Satisfied when x is Equal to Class 10 Maths
Change the following sentences into negative and interrogative class 10 english CBSE