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More # State True or False. If $a$,$b$,$c$ are in A.P., then $b + c$,$c + a$,$a + b$ are also in A.P. $A$. $True$$B.False Answer Verified 363.3k+ views Hint: The above problem is related to arithmetic progression. First, we should be able to define an arithmetic sequence. After that its properties can be used to solve the above problem. Arithmetic Progression is a sequence of numbers such that the difference of any two consecutive numbers is constant. General {n^{th}} term of an A.P. is given by: {a_n} = a + \left( {n - 1} \right)d Where a is the first term of the A.P. sequence and d is known as the common difference. Given in the problem, a,b,c are in A.P. \Rightarrow First term = a \Rightarrow Second term = a + d = b \Rightarrow Third term = a + 2d = c \Rightarrow b - a = c - b = d ……………………………….. (1) Here d is the common difference. Since we need to check whether b + c,c + a,a + b are in A.P. or not. We need to find the common difference of the consecutive terms. \Rightarrow c + a - \left( {b + c} \right) = c + a - b - c = a - b Using equation (1) in above, we get c + a - \left( {b + c} \right) = a - b = - d ………………………….(2) Similarly, a + b - \left( {c + a} \right) = a + b - c - a = b - c \Rightarrow a + b - \left( {c + a} \right) = b - c = - d ………………...(3) From (2) and (3) , the common difference of the consecutive terms is equal. \Rightarrow$$b + c$,$c + a$,$a + b$ are in A.P.
Hence option $(A)$ is the correct answer.