# Solve the following equation $\dfrac{{2b}}{3} - 5 = 3$

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Hint: To solve an equation means we have to find the variable value in the equation. We are going to use basic algebraic calculations to solve the equation.

Complete step-by-step answer:

The given equation is $\dfrac{{2b}}{3} - 5 = 3$

Multiplying the above equation with ‘3’ on both side, we get

$\eqalign{

& \Rightarrow \left( {\dfrac{{2b}}{3} - 5} \right) \times 3 = 3 \times 3 \cr

& \Rightarrow \left( {\dfrac{{2b}}{3} \times 3 - 5 \times 3} \right) = 9 \cr

& \Rightarrow 2b - 15 = 9 \cr} $

Adding ‘15’ on both sides of the above equation,

$ \Rightarrow 2b - 15 + 15 = 9 + 15$

$ \Rightarrow 2b = 24$

Dividing the above equation with ‘2’ on both sides, we get

$ \Rightarrow \dfrac{{2b}}{2} = \dfrac{{24}}{2}$

$ \Rightarrow b = 12$

$\therefore $ The solution of the given equation $\dfrac{{2b}}{3} - 5 = 3$ is $b = 12$

Note: An equation is something that tells us the terms on both sides of ‘=’ are equal. The solution of an equation is a particular value that can be placed in the variable to make the equation true.

Complete step-by-step answer:

The given equation is $\dfrac{{2b}}{3} - 5 = 3$

Multiplying the above equation with ‘3’ on both side, we get

$\eqalign{

& \Rightarrow \left( {\dfrac{{2b}}{3} - 5} \right) \times 3 = 3 \times 3 \cr

& \Rightarrow \left( {\dfrac{{2b}}{3} \times 3 - 5 \times 3} \right) = 9 \cr

& \Rightarrow 2b - 15 = 9 \cr} $

Adding ‘15’ on both sides of the above equation,

$ \Rightarrow 2b - 15 + 15 = 9 + 15$

$ \Rightarrow 2b = 24$

Dividing the above equation with ‘2’ on both sides, we get

$ \Rightarrow \dfrac{{2b}}{2} = \dfrac{{24}}{2}$

$ \Rightarrow b = 12$

$\therefore $ The solution of the given equation $\dfrac{{2b}}{3} - 5 = 3$ is $b = 12$

Note: An equation is something that tells us the terms on both sides of ‘=’ are equal. The solution of an equation is a particular value that can be placed in the variable to make the equation true.

Last updated date: 23rd Sep 2023

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