Answer
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Hint: To solve an equation means we have to find the variable value in the equation. We are going to use basic algebraic calculations to solve the equation.
Complete step-by-step answer:
The given equation is $\dfrac{{2b}}{3} - 5 = 3$
Multiplying the above equation with ‘3’ on both side, we get
$\eqalign{
& \Rightarrow \left( {\dfrac{{2b}}{3} - 5} \right) \times 3 = 3 \times 3 \cr
& \Rightarrow \left( {\dfrac{{2b}}{3} \times 3 - 5 \times 3} \right) = 9 \cr
& \Rightarrow 2b - 15 = 9 \cr} $
Adding ‘15’ on both sides of the above equation,
$ \Rightarrow 2b - 15 + 15 = 9 + 15$
$ \Rightarrow 2b = 24$
Dividing the above equation with ‘2’ on both sides, we get
$ \Rightarrow \dfrac{{2b}}{2} = \dfrac{{24}}{2}$
$ \Rightarrow b = 12$
$\therefore $ The solution of the given equation $\dfrac{{2b}}{3} - 5 = 3$ is $b = 12$
Note: An equation is something that tells us the terms on both sides of ‘=’ are equal. The solution of an equation is a particular value that can be placed in the variable to make the equation true.
Complete step-by-step answer:
The given equation is $\dfrac{{2b}}{3} - 5 = 3$
Multiplying the above equation with ‘3’ on both side, we get
$\eqalign{
& \Rightarrow \left( {\dfrac{{2b}}{3} - 5} \right) \times 3 = 3 \times 3 \cr
& \Rightarrow \left( {\dfrac{{2b}}{3} \times 3 - 5 \times 3} \right) = 9 \cr
& \Rightarrow 2b - 15 = 9 \cr} $
Adding ‘15’ on both sides of the above equation,
$ \Rightarrow 2b - 15 + 15 = 9 + 15$
$ \Rightarrow 2b = 24$
Dividing the above equation with ‘2’ on both sides, we get
$ \Rightarrow \dfrac{{2b}}{2} = \dfrac{{24}}{2}$
$ \Rightarrow b = 12$
$\therefore $ The solution of the given equation $\dfrac{{2b}}{3} - 5 = 3$ is $b = 12$
Note: An equation is something that tells us the terms on both sides of ‘=’ are equal. The solution of an equation is a particular value that can be placed in the variable to make the equation true.
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