Answer

Verified

435.3k+ views

Hint:- Take constant terms and variables from different sides of the equation.

As, we are given the equation,

\[ \Rightarrow 2x - 1 = 14 - x\] (1)

As, we can see from the above equation that the given equation has only one variable.

So, whenever we are given with one equation having one variable then we will find the

value of variable by taking all the constant terms to one side of the equation.

And variable to the other side of the equation.

So, now for solving equation 1.

Adding \[x + 1\] to both sides of the equation 1. We get,

\[ \Rightarrow 3x = 15\]

Now, dividing both sides of the above equation by 3. We get,

\[ \Rightarrow x = \dfrac{{15}}{3} = 5\].

For checking the result.

If LHS = RHS, On putting the value of $x$ in the given equation. Then our result will be satisfied.

Putting the value of $x$ in equation 1.

\[

\Rightarrow (2*5) - 1 = 14 - 5 \\

\Rightarrow 9 = 9 \\

\]

Hence, LHS = RHS

So, the value of $x$ will be 5.

Note:- In these types of questions if there are n variables in an equation then there should be

minimum of n different equations, to get the value of all variables. And easiest and efficient

way to get values of different variables is by substituting the values of variables in different

equations.

As, we are given the equation,

\[ \Rightarrow 2x - 1 = 14 - x\] (1)

As, we can see from the above equation that the given equation has only one variable.

So, whenever we are given with one equation having one variable then we will find the

value of variable by taking all the constant terms to one side of the equation.

And variable to the other side of the equation.

So, now for solving equation 1.

Adding \[x + 1\] to both sides of the equation 1. We get,

\[ \Rightarrow 3x = 15\]

Now, dividing both sides of the above equation by 3. We get,

\[ \Rightarrow x = \dfrac{{15}}{3} = 5\].

For checking the result.

If LHS = RHS, On putting the value of $x$ in the given equation. Then our result will be satisfied.

Putting the value of $x$ in equation 1.

\[

\Rightarrow (2*5) - 1 = 14 - 5 \\

\Rightarrow 9 = 9 \\

\]

Hence, LHS = RHS

So, the value of $x$ will be 5.

Note:- In these types of questions if there are n variables in an equation then there should be

minimum of n different equations, to get the value of all variables. And easiest and efficient

way to get values of different variables is by substituting the values of variables in different

equations.

Recently Updated Pages

The branch of science which deals with nature and natural class 10 physics CBSE

The Equation xxx + 2 is Satisfied when x is Equal to Class 10 Maths

Define absolute refractive index of a medium

Find out what do the algal bloom and redtides sign class 10 biology CBSE

Prove that the function fleft x right xn is continuous class 12 maths CBSE

Find the values of other five trigonometric functions class 10 maths CBSE

Trending doubts

Difference Between Plant Cell and Animal Cell

Difference between Prokaryotic cell and Eukaryotic class 11 biology CBSE

Fill the blanks with the suitable prepositions 1 The class 9 english CBSE

Change the following sentences into negative and interrogative class 10 english CBSE

Write two gases which are soluble in water class 11 chemistry CBSE

Give 10 examples for herbs , shrubs , climbers , creepers

Fill the blanks with proper collective nouns 1 A of class 10 english CBSE

What organs are located on the left side of your body class 11 biology CBSE

The Equation xxx + 2 is Satisfied when x is Equal to Class 10 Maths