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Hint: we need to know the basic factorization of quadratic equations to solve this problem.

Given equation is $5\sqrt {\frac{3}{x}} + 7 + \sqrt {\frac{x}{3}} = 22\frac{2}{3}$

For simplification of calculations put $t = \sqrt {\frac{3}{x}} $ then $\sqrt {\frac{x}{3}} = \frac{1}{t}$ , then the given equation will be

$5t + \frac{7}{t} = \frac{{68}}{3}$

Simplifying the above equation

$\frac{{5{t^2} + 7}}{t} = \frac{{68}}{3}$

$15{t^2} + 21 = 68t$

$15{t^2} - 68t + 21 = 0$

Now we got a quadratic equation, on factorization we get

$15{t^2} - 5t - 63t + 21 = 0$

$5t(3t - 1) - 21(3t - 1) = 0$

$(5t - 21)(3t - 1) = 0$

$t = \frac{{21}}{5},\frac{1}{3}$

Now, we know that $t = \sqrt {\frac{3}{x}} $

${t^2} = \frac{3}{x}$

$x = \frac{3}{{{t^2}}}$ , solving for the values of x using t value.

For $t = \frac{{21}}{5}$

$$x = \frac{3}{{{{\left( {\frac{{21}}{5}} \right)}^2}}} = \frac{{25}}{{147}}$$

For $t = \frac{1}{3}$

$x = \frac{3}{{{{\left( {\frac{1}{3}} \right)}^2}}} = 27$

$\therefore x = 27,\frac{{25}}{{147}}$ are the required values.

Note: Here we are converting the given equation into a quadratic equation by using the substitution method. We substituted $\sqrt {\frac{3}{x}} $as t, after substitution we simplified the equation and solved for t. After getting t values, we have to again substitute the value of t in terms of x, then finding x values easily.

Given equation is $5\sqrt {\frac{3}{x}} + 7 + \sqrt {\frac{x}{3}} = 22\frac{2}{3}$

For simplification of calculations put $t = \sqrt {\frac{3}{x}} $ then $\sqrt {\frac{x}{3}} = \frac{1}{t}$ , then the given equation will be

$5t + \frac{7}{t} = \frac{{68}}{3}$

Simplifying the above equation

$\frac{{5{t^2} + 7}}{t} = \frac{{68}}{3}$

$15{t^2} + 21 = 68t$

$15{t^2} - 68t + 21 = 0$

Now we got a quadratic equation, on factorization we get

$15{t^2} - 5t - 63t + 21 = 0$

$5t(3t - 1) - 21(3t - 1) = 0$

$(5t - 21)(3t - 1) = 0$

$t = \frac{{21}}{5},\frac{1}{3}$

Now, we know that $t = \sqrt {\frac{3}{x}} $

${t^2} = \frac{3}{x}$

$x = \frac{3}{{{t^2}}}$ , solving for the values of x using t value.

For $t = \frac{{21}}{5}$

$$x = \frac{3}{{{{\left( {\frac{{21}}{5}} \right)}^2}}} = \frac{{25}}{{147}}$$

For $t = \frac{1}{3}$

$x = \frac{3}{{{{\left( {\frac{1}{3}} \right)}^2}}} = 27$

$\therefore x = 27,\frac{{25}}{{147}}$ are the required values.

Note: Here we are converting the given equation into a quadratic equation by using the substitution method. We substituted $\sqrt {\frac{3}{x}} $as t, after substitution we simplified the equation and solved for t. After getting t values, we have to again substitute the value of t in terms of x, then finding x values easily.