Answer
384k+ views
Hint:In this question, an algebraic expression containing five unknown variable quantities is given to us. We know that we need an “n” number of equations to find the value of “n” unknown variables. So to find the value of each unknown variable we need 5 equations, but in the given question, we have to solve for x. So, we treat the other unknown variables as constant, now we have 1 unknown quantity and exactly one equation to find the value of x. For finding the value, we will rearrange the equation such that x lies on one side of the equation and all other terms lie on the other side. Then by applying the given arithmetic operations, we can find the value of x.
Complete step by step answer:
We are given that \[ax - k = bx + h\]
To find the value of x, we will take $bx$ to the left-hand side and k to the right-hand side so that the terms containing x are present on one side and the constant terms are present on the other side –
$ \Rightarrow ax - bx = h + k$
Taking x common –
$x(a - b) = h + k$
Now, we will take $(a - b)$ to the right-hand side –
$x = \dfrac{{h + k}}{{a - b}}$
Hence, when \[ax - k = bx + h\] , we get $x = \dfrac{{h + k}}{{a - b}}$ .
Note: The obtained equation contains x on the one side and the terms a, b, h and k on the other side, so we can get the value of x by putting the values of a, b, h and k in the obtained equation. The answer is in fractional form, so after putting the values of a, b, h and k, we will also simplify the fraction, if it is not in the simplified form.
Complete step by step answer:
We are given that \[ax - k = bx + h\]
To find the value of x, we will take $bx$ to the left-hand side and k to the right-hand side so that the terms containing x are present on one side and the constant terms are present on the other side –
$ \Rightarrow ax - bx = h + k$
Taking x common –
$x(a - b) = h + k$
Now, we will take $(a - b)$ to the right-hand side –
$x = \dfrac{{h + k}}{{a - b}}$
Hence, when \[ax - k = bx + h\] , we get $x = \dfrac{{h + k}}{{a - b}}$ .
Note: The obtained equation contains x on the one side and the terms a, b, h and k on the other side, so we can get the value of x by putting the values of a, b, h and k in the obtained equation. The answer is in fractional form, so after putting the values of a, b, h and k, we will also simplify the fraction, if it is not in the simplified form.
Recently Updated Pages
How many sigma and pi bonds are present in HCequiv class 11 chemistry CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Why Are Noble Gases NonReactive class 11 chemistry CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Let X and Y be the sets of all positive divisors of class 11 maths CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Let x and y be 2 real numbers which satisfy the equations class 11 maths CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Let x 4log 2sqrt 9k 1 + 7 and y dfrac132log 2sqrt5 class 11 maths CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Let x22ax+b20 and x22bx+a20 be two equations Then the class 11 maths CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Trending doubts
Fill the blanks with the suitable prepositions 1 The class 9 english CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
At which age domestication of animals started A Neolithic class 11 social science CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Which are the Top 10 Largest Countries of the World?
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Give 10 examples for herbs , shrubs , climbers , creepers
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Difference between Prokaryotic cell and Eukaryotic class 11 biology CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Difference Between Plant Cell and Animal Cell
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Write a letter to the principal requesting him to grant class 10 english CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Change the following sentences into negative and interrogative class 10 english CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Fill in the blanks A 1 lakh ten thousand B 1 million class 9 maths CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)