Answer
Verified
417.9k+ views
Hint: Substitution Method:
In this method from the given two equations of two variables, we have to substitute the equation of any one variable from one of the equations and then substitute it in the other one such that the second equation becomes an equation of one variable and thereby we can solve for that one variable. So by using any of the above definitions we can solve the given pair of linear equations.
Complete step by step solution:
Given
\[
3x - y = 4.............\left( i \right) \\
2x - 3y = - 9.............\left( {ii} \right) \\
\]
Now we are using the substitution method which is one of the algebraic methods, as given above to solve the question.
So by using the above definition, let’s substitute x from equation (i) to (ii):
$
\Rightarrow 3x - y = 4 \\
\Rightarrow x = \dfrac{{4 + y}}{3}..................\left( {iii} \right) \\
$
Now substituting (iii) in (ii):
$ \Rightarrow x = \dfrac{{4 + y}}{3}$
Now substituting (iii), we get:
\[
\Rightarrow 2x - 3y = - 9 \\
\Rightarrow 2\left( {\dfrac{{4 + y}}{3}} \right) - 3y = - 9 \\
\Rightarrow 2\left( {\dfrac{{4 + y}}{3}} \right) = 3y - 9 \\
\Rightarrow 2\left( {4 + y} \right) = 3\left( {3y - 9} \right) \\
\Rightarrow 8 + 2y = 9y - 27 \\
\Rightarrow 9y - 2y = 8 + 27 \\
\Rightarrow 7y = 8 + 27..................\left( {iv} \right) \\
\]
On observing (iv) we get that it’s an equation of only ‘y’ such that we can solve for the variable ‘y’.
$
\Rightarrow 7y = 8 + 27 \\
\Rightarrow 7y = 35 \\
\Rightarrow y = \dfrac{{35}}{7} \\
\Rightarrow y = 5......................\left( v \right) \\
$
So now we get: $y = 5$
Now substituting (v) in (iii) to get the value of ‘x’:
$
\Rightarrow x = \dfrac{{4 + y}}{3} \\
\Rightarrow x = \dfrac{{4 + 5}}{3} \\
\Rightarrow x = \dfrac{9}{3} \\
\Rightarrow x = 3.........................\left( {vi} \right) \\
$
Therefore on solving $3x - y = 4\;{\text{and}}\;2x - 3y = - 9$ by substitution method we get $x =
3\;{\text{and}}\;{\text{y = 5}}{\text{.}}$
Additional Information:
A given pair of linear equations can be solved either by graphical or algebraic method. The algebraic
method is of three types:
1. Substitution Method
2. Elimination Method
3. Cross Multiplication Method
Note:
While solving a pair of linear equations one should take care of following things:
We need to express the two linear equations in two different variables, we can solve them either by substitution, elimination, cross multiplication method or by graphical method. We can also check the validation of the ‘x’ and ‘y’ values by putting them in the given equations and checking whether it satisfies mathematically or not.
In this method from the given two equations of two variables, we have to substitute the equation of any one variable from one of the equations and then substitute it in the other one such that the second equation becomes an equation of one variable and thereby we can solve for that one variable. So by using any of the above definitions we can solve the given pair of linear equations.
Complete step by step solution:
Given
\[
3x - y = 4.............\left( i \right) \\
2x - 3y = - 9.............\left( {ii} \right) \\
\]
Now we are using the substitution method which is one of the algebraic methods, as given above to solve the question.
So by using the above definition, let’s substitute x from equation (i) to (ii):
$
\Rightarrow 3x - y = 4 \\
\Rightarrow x = \dfrac{{4 + y}}{3}..................\left( {iii} \right) \\
$
Now substituting (iii) in (ii):
$ \Rightarrow x = \dfrac{{4 + y}}{3}$
Now substituting (iii), we get:
\[
\Rightarrow 2x - 3y = - 9 \\
\Rightarrow 2\left( {\dfrac{{4 + y}}{3}} \right) - 3y = - 9 \\
\Rightarrow 2\left( {\dfrac{{4 + y}}{3}} \right) = 3y - 9 \\
\Rightarrow 2\left( {4 + y} \right) = 3\left( {3y - 9} \right) \\
\Rightarrow 8 + 2y = 9y - 27 \\
\Rightarrow 9y - 2y = 8 + 27 \\
\Rightarrow 7y = 8 + 27..................\left( {iv} \right) \\
\]
On observing (iv) we get that it’s an equation of only ‘y’ such that we can solve for the variable ‘y’.
$
\Rightarrow 7y = 8 + 27 \\
\Rightarrow 7y = 35 \\
\Rightarrow y = \dfrac{{35}}{7} \\
\Rightarrow y = 5......................\left( v \right) \\
$
So now we get: $y = 5$
Now substituting (v) in (iii) to get the value of ‘x’:
$
\Rightarrow x = \dfrac{{4 + y}}{3} \\
\Rightarrow x = \dfrac{{4 + 5}}{3} \\
\Rightarrow x = \dfrac{9}{3} \\
\Rightarrow x = 3.........................\left( {vi} \right) \\
$
Therefore on solving $3x - y = 4\;{\text{and}}\;2x - 3y = - 9$ by substitution method we get $x =
3\;{\text{and}}\;{\text{y = 5}}{\text{.}}$
Additional Information:
A given pair of linear equations can be solved either by graphical or algebraic method. The algebraic
method is of three types:
1. Substitution Method
2. Elimination Method
3. Cross Multiplication Method
Note:
While solving a pair of linear equations one should take care of following things:
We need to express the two linear equations in two different variables, we can solve them either by substitution, elimination, cross multiplication method or by graphical method. We can also check the validation of the ‘x’ and ‘y’ values by putting them in the given equations and checking whether it satisfies mathematically or not.
Recently Updated Pages
what is the correct chronological order of the following class 10 social science CBSE
Which of the following was not the actual cause for class 10 social science CBSE
Which of the following statements is not correct A class 10 social science CBSE
Which of the following leaders was not present in the class 10 social science CBSE
Garampani Sanctuary is located at A Diphu Assam B Gangtok class 10 social science CBSE
Which one of the following places is not covered by class 10 social science CBSE
Trending doubts
Which are the Top 10 Largest Countries of the World?
Fill the blanks with the suitable prepositions 1 The class 9 english CBSE
How do you graph the function fx 4x class 9 maths CBSE
In Indian rupees 1 trillion is equal to how many c class 8 maths CBSE
The Equation xxx + 2 is Satisfied when x is Equal to Class 10 Maths
Give 10 examples for herbs , shrubs , climbers , creepers
Why is there a time difference of about 5 hours between class 10 social science CBSE
Difference between Prokaryotic cell and Eukaryotic class 11 biology CBSE
What is BLO What is the full form of BLO class 8 social science CBSE