
Rs 9,000 were divided equally among a certain number of persons. Had there been 20 persons more, each would have got Rs 160 less. Find the original number of persons.
Answer
516.5k+ views
Hint- Here, we will be proceeding by making an equation in one variable by using the formula i.e., Amount divided among each person = $\dfrac{{{\text{Total amount to be divided}}}}{{{\text{Total number of persons}}}}$ and then solving for the unknown.
Let the original number of persons be x among which Rs 9000 is to be divided.
For the amount that each person will be getting, we will divide the total amount Rs 9000 by the original number of persons among which Rs 9000 is to be divided.
i.e., Amount that each person will be getting = Rs $\dfrac{{9000}}{x}$.
Now, when the total number of persons among which Rs 9000 is to be divided are 20 persons more than the original number of persons (x).
i.e., Number of persons amount which Rs 9000 is to be divided = (x+20) persons
Hence, amount that each person will be getting = Rs $\dfrac{{9000}}{{x + 20}}$
According to problem statement, $\dfrac{{9000}}{x} - \dfrac{{9000}}{{x + 20}} = 160$
Now, we will solve the above equation by taking x(x+20) as LCM to get the value of x.
$
\Rightarrow \dfrac{{9000}}{x} - \dfrac{{9000}}{{x + 20}} = 160
$
$
\Rightarrow \dfrac{{9000\left( {x + 20} \right) - 9000x}}{{x\left( {x + 20} \right)}} = 160
$
$
\Rightarrow \dfrac{{9000x + 180000 - 9000x}}{{x\left( {x + 20} \right)}} = 160 \\
$
$
\Rightarrow \dfrac{{180000}}{{x\left( {x + 20} \right)}} = 160 \\
$
By applying cross multiplication in the above equation, we get
$
\Rightarrow 180000 = 160x\left( {x + 20} \right)
$
$
\Rightarrow 1125 = x\left( {x + 20} \right)
$
$
\Rightarrow 1125 = {x^2} + 20x
$
$
\Rightarrow {x^2} + 20x - 1125 = 0 \\
$
$
\Rightarrow {x^2} + 45x - 25x - 1125 = 0
$
$
\Rightarrow x\left( {x + 45} \right) - 25\left( {x + 45} \right) = 0 \\
$
$
\Rightarrow \left( {x + 45} \right)\left( {x - 25} \right) = 0 \\
$
Either $\left( {x + 45} \right) = 0 \Rightarrow x = - 45$ or $\left( {x - 25} \right) = 0 \Rightarrow x = 25$
As we know that here x is representing the original number of persons among which Rs 9000 is getting divided and the number of persons will always be positive so, only positive values of x should be considered.
i.e., $x = - 45$ is neglected.
So, $x = 25$ is the correct value.
Therefore, the original number of persons among will Rs 9000 is to be divided are 25 persons.
Note- In this particular problem, we can easily see that if the number of persons (among which Rs 9000 is divided) is increased, then the amount that each person will get will automatically decrease because both of these are inversely proportional to each other.
Let the original number of persons be x among which Rs 9000 is to be divided.
For the amount that each person will be getting, we will divide the total amount Rs 9000 by the original number of persons among which Rs 9000 is to be divided.
i.e., Amount that each person will be getting = Rs $\dfrac{{9000}}{x}$.
Now, when the total number of persons among which Rs 9000 is to be divided are 20 persons more than the original number of persons (x).
i.e., Number of persons amount which Rs 9000 is to be divided = (x+20) persons
Hence, amount that each person will be getting = Rs $\dfrac{{9000}}{{x + 20}}$
According to problem statement, $\dfrac{{9000}}{x} - \dfrac{{9000}}{{x + 20}} = 160$
Now, we will solve the above equation by taking x(x+20) as LCM to get the value of x.
$
\Rightarrow \dfrac{{9000}}{x} - \dfrac{{9000}}{{x + 20}} = 160
$
$
\Rightarrow \dfrac{{9000\left( {x + 20} \right) - 9000x}}{{x\left( {x + 20} \right)}} = 160
$
$
\Rightarrow \dfrac{{9000x + 180000 - 9000x}}{{x\left( {x + 20} \right)}} = 160 \\
$
$
\Rightarrow \dfrac{{180000}}{{x\left( {x + 20} \right)}} = 160 \\
$
By applying cross multiplication in the above equation, we get
$
\Rightarrow 180000 = 160x\left( {x + 20} \right)
$
$
\Rightarrow 1125 = x\left( {x + 20} \right)
$
$
\Rightarrow 1125 = {x^2} + 20x
$
$
\Rightarrow {x^2} + 20x - 1125 = 0 \\
$
$
\Rightarrow {x^2} + 45x - 25x - 1125 = 0
$
$
\Rightarrow x\left( {x + 45} \right) - 25\left( {x + 45} \right) = 0 \\
$
$
\Rightarrow \left( {x + 45} \right)\left( {x - 25} \right) = 0 \\
$
Either $\left( {x + 45} \right) = 0 \Rightarrow x = - 45$ or $\left( {x - 25} \right) = 0 \Rightarrow x = 25$
As we know that here x is representing the original number of persons among which Rs 9000 is getting divided and the number of persons will always be positive so, only positive values of x should be considered.
i.e., $x = - 45$ is neglected.
So, $x = 25$ is the correct value.
Therefore, the original number of persons among will Rs 9000 is to be divided are 25 persons.
Note- In this particular problem, we can easily see that if the number of persons (among which Rs 9000 is divided) is increased, then the amount that each person will get will automatically decrease because both of these are inversely proportional to each other.
Recently Updated Pages
What happens to glucose which enters nephron along class 10 biology CBSE

Write a dialogue with at least ten utterances between class 10 english CBSE

A circle is inscribed in an equilateral triangle and class 10 maths CBSE

When the JanmiKudian Act was passed that granted the class 10 social science CBSE

A sector containing an angle of 120 circ is cut off class 10 maths CBSE

The sum of digits of a two digit number is 13 If t-class-10-maths-ICSE

Trending doubts
The shortest day of the year in India

Why is there a time difference of about 5 hours between class 10 social science CBSE

Write a letter to the principal requesting him to grant class 10 english CBSE

What is the median of the first 10 natural numbers class 10 maths CBSE

The Equation xxx + 2 is Satisfied when x is Equal to Class 10 Maths

What is the missing number in the sequence 259142027 class 10 maths CBSE

