# Rs 9,000 were divided equally among a certain number of persons. Had there been 20 persons more, each would have got Rs 160 less. Find the original number of persons.

Answer

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Hint- Here, we will be proceeding by making an equation in one variable by using the formula i.e., Amount divided among each person = $\dfrac{{{\text{Total amount to be divided}}}}{{{\text{Total number of persons}}}}$ and then solving for the unknown.

Let the original number of persons be x among which Rs 9000 is to be divided.

For the amount that each person will be getting, we will divide the total amount Rs 9000 by the original number of persons among which Rs 9000 is to be divided.

i.e., Amount that each person will be getting = Rs $\dfrac{{9000}}{x}$.

Now, when the total number of persons among which Rs 9000 is to be divided are 20 persons more than the original number of persons (x).

i.e., Number of persons amount which Rs 9000 is to be divided = (x+20) persons

Hence, amount that each person will be getting = Rs $\dfrac{{9000}}{{x + 20}}$

According to problem statement, $\dfrac{{9000}}{x} - \dfrac{{9000}}{{x + 20}} = 160$

Now, we will solve the above equation by taking x(x+20) as LCM to get the value of x.

$

\Rightarrow \dfrac{{9000}}{x} - \dfrac{{9000}}{{x + 20}} = 160

$

$

\Rightarrow \dfrac{{9000\left( {x + 20} \right) - 9000x}}{{x\left( {x + 20} \right)}} = 160

$

$

\Rightarrow \dfrac{{9000x + 180000 - 9000x}}{{x\left( {x + 20} \right)}} = 160 \\

$

$

\Rightarrow \dfrac{{180000}}{{x\left( {x + 20} \right)}} = 160 \\

$

By applying cross multiplication in the above equation, we get

$

\Rightarrow 180000 = 160x\left( {x + 20} \right)

$

$

\Rightarrow 1125 = x\left( {x + 20} \right)

$

$

\Rightarrow 1125 = {x^2} + 20x

$

$

\Rightarrow {x^2} + 20x - 1125 = 0 \\

$

$

\Rightarrow {x^2} + 45x - 25x - 1125 = 0

$

$

\Rightarrow x\left( {x + 45} \right) - 25\left( {x + 45} \right) = 0 \\

$

$

\Rightarrow \left( {x + 45} \right)\left( {x - 25} \right) = 0 \\

$

Either $\left( {x + 45} \right) = 0 \Rightarrow x = - 45$ or $\left( {x - 25} \right) = 0 \Rightarrow x = 25$

As we know that here x is representing the original number of persons among which Rs 9000 is getting divided and the number of persons will always be positive so, only positive values of x should be considered.

i.e., $x = - 45$ is neglected.

So, $x = 25$ is the correct value.

Therefore, the original number of persons among will Rs 9000 is to be divided are 25 persons.

Note- In this particular problem, we can easily see that if the number of persons (among which Rs 9000 is divided) is increased, then the amount that each person will get will automatically decrease because both of these are inversely proportional to each other.

Let the original number of persons be x among which Rs 9000 is to be divided.

For the amount that each person will be getting, we will divide the total amount Rs 9000 by the original number of persons among which Rs 9000 is to be divided.

i.e., Amount that each person will be getting = Rs $\dfrac{{9000}}{x}$.

Now, when the total number of persons among which Rs 9000 is to be divided are 20 persons more than the original number of persons (x).

i.e., Number of persons amount which Rs 9000 is to be divided = (x+20) persons

Hence, amount that each person will be getting = Rs $\dfrac{{9000}}{{x + 20}}$

According to problem statement, $\dfrac{{9000}}{x} - \dfrac{{9000}}{{x + 20}} = 160$

Now, we will solve the above equation by taking x(x+20) as LCM to get the value of x.

$

\Rightarrow \dfrac{{9000}}{x} - \dfrac{{9000}}{{x + 20}} = 160

$

$

\Rightarrow \dfrac{{9000\left( {x + 20} \right) - 9000x}}{{x\left( {x + 20} \right)}} = 160

$

$

\Rightarrow \dfrac{{9000x + 180000 - 9000x}}{{x\left( {x + 20} \right)}} = 160 \\

$

$

\Rightarrow \dfrac{{180000}}{{x\left( {x + 20} \right)}} = 160 \\

$

By applying cross multiplication in the above equation, we get

$

\Rightarrow 180000 = 160x\left( {x + 20} \right)

$

$

\Rightarrow 1125 = x\left( {x + 20} \right)

$

$

\Rightarrow 1125 = {x^2} + 20x

$

$

\Rightarrow {x^2} + 20x - 1125 = 0 \\

$

$

\Rightarrow {x^2} + 45x - 25x - 1125 = 0

$

$

\Rightarrow x\left( {x + 45} \right) - 25\left( {x + 45} \right) = 0 \\

$

$

\Rightarrow \left( {x + 45} \right)\left( {x - 25} \right) = 0 \\

$

Either $\left( {x + 45} \right) = 0 \Rightarrow x = - 45$ or $\left( {x - 25} \right) = 0 \Rightarrow x = 25$

As we know that here x is representing the original number of persons among which Rs 9000 is getting divided and the number of persons will always be positive so, only positive values of x should be considered.

i.e., $x = - 45$ is neglected.

So, $x = 25$ is the correct value.

Therefore, the original number of persons among will Rs 9000 is to be divided are 25 persons.

Note- In this particular problem, we can easily see that if the number of persons (among which Rs 9000 is divided) is increased, then the amount that each person will get will automatically decrease because both of these are inversely proportional to each other.

Last updated date: 02nd Oct 2023

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